NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.3 Solutions

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NCERT Solutions for Class 9 Maths Chapter 7 Triangles Exercise 7.3 Solutions are based on the concepts of SSS congruence rules and RHS congruence rules.

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Exercise Solutions of Class 9 Maths Chapter 7 Triangles

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Important Chapter Related Topics
Mid Point Theorem	Isosceles Triangle	Congruence of triangles
Class 9 Maths Chapter 7 Triangles MCQs	Properties of inequalities and triangles	Sides of a Triangle
Similar Figures	Triangles

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Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Algebra
Trigonometry	Number Systems	Mensuration
Math Formula	NCERT Solutions for Class 9 Maths	Geometry

CBSE X Related Questions

1.
There are many varieties of mushrooms available in the world. One such mushroom ‘Amanita muscaria’ has a upper part which is like red cap (hemispherical) and lower part is like white stem (cylindrical). The hemispherical cap’s radius = 3 cm and cylindrical stem is 2 cm high with diameter 1.4 cm. Considering mushroom a solid object, answer the following questions:

36(i) What is the total height of a mushroom ?
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2.
In a circular museum hall of radius 14 m, some statues are displayed. Statues are kept inside the inner concentric circle of radius 7 m. One such statue lying in sector OAB, is fenced along line segments OA, AP, PB and BO where P is a point on outer circle. Based on above information, answer the following questions:

37(i) Find \(m\angle AOP\).
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3.
If \( 2 \sin A = 1 \), then the value of \( \tan A + \cot A \) is :
- \( \sqrt{3} \)
- \( \frac{4}{\sqrt{3}} \)
- \( \frac{\sqrt{3}}{2} \)
- \( 1 \)
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4.
Prove that : \(\sqrt{\frac{1 - \cos A}{1 + \cos A}} = \frac{\tan A}{\sec A + 1}\).
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5.
In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).
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6.
If 14th term of an A.P. is 4 and its 15th term is zero, then its first term is
- –48
- –56
- 56
- 48
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