NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.2

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.2 are provided in this article. Class 10 Maths Chapter 6 Triangles deals with questions related to the similarity and congruence of triangles. This chapter also covers important triangle theorems. Chapter 6 Exercise 6.2 includes questions based on theorems related to the sides of the triangle. 

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.2

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CBSE X Related Questions

  • 1.
    There are many varieties of mushrooms available in the world. One such mushroom ‘Amanita muscaria’ has a upper part which is like red cap (hemispherical) and lower part is like white stem (cylindrical). The hemispherical cap’s radius = 3 cm and cylindrical stem is 2 cm high with diameter 1.4 cm. Considering mushroom a solid object, answer the following questions:

    36(i) What is the total height of a mushroom ?


      • 2.
        Three coins are tossed together. The probability of getting exactly two tails is

          • \(\frac{2}{8}\)
          • \(\frac{1}{2}\)
          • \(\frac{3}{8}\)
          • 1

        • 3.
          PQ is tangent to the circle with centre O such that OP = 2OQ. m\(\angle\)OPQ is

            • 15\(^\circ\)
            • 60\(^\circ\)
            • 45\(^\circ\)
            • 30\(^\circ\)

          • 4.
            In the given figure, \(\Delta ABC\) is a right-angled triangle with \(\angle A = 90^\circ\). AD is perpendicular to BC.

            35(a)(i) Prove that \(\Delta DBA \sim \Delta DAC\)


              • 5.
                Find the missing frequencies p and q in the following frequency distribution, when sum of frequencies is 40 and mean is 19 :


                  • 6.
                    In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).

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