NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.5

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Jasmine Grover

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NCERT Solutions for Class 10 Maths Chapter 6 Triangles Exercise 6.5 are provided in this article. Class 10 Maths Chapter 6 Triangles is an important chapter included under the Unit Geometry of class 10 maths syllabus. Exercise 6.5 includes questions based on Pythagoras theorem.

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Check below the NCERT solutions pdf for Class 10 Maths Chapter 6 Exercise 6.5

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CBSE X Related Questions

  • 1.
    It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

      • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
      • \(\frac{AB}{ED} = \frac{AC}{EF}\)
      • \(\angle A = \angle D, \angle C = \angle F\)
      • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

    • 2.
      In an A.P., if $a_{14} - a_8 = 24$, then the common difference of the A.P. is

        • $6$
        • $4$
        • $\pm 4$
        • $3$

      • 3.
        If roots of the quadratic equation \(x^2 - k\sqrt{3}x + 2 = 0\) are real and equal, then value of k is

          • \(-2\)
          • \(\sqrt{\frac{8}{3}}\)
          • \(1\)
          • \(2\)

        • 4.
          If \( \alpha \) and \( \beta \) are two zeroes of a polynomial \( f(x) = px^2 - 2x + 3p \) and \( \alpha + \beta = \alpha\beta \), then value of p is :

            • \( -\frac{2}{3} \)
            • \( \frac{2}{3} \)
            • \( \frac{1}{3} \)
            • \( -\frac{1}{3} \)

          • 5.
            In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

              • $55^\circ$
              • $20^\circ$
              • $35^\circ$
              • $70^\circ$

            • 6.
              If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

                • \(\frac{7}{2}\)
                • \(\frac{6}{7}\)
                • \(\frac{-7}{6}\)
                • \(\frac{7}{6}\)

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