CUET PG PYQs for Analysis of variance (ANOVA) with Solutions: Practice CUET PG Previous Year Questions

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Analysis of variance (ANOVA) is an important topic in the Statistics section in CUET PG exam. Practising this topic will increase your score overall and make your conceptual grip on CUET PG exam stronger.

This article gives you a full set of CUET PG PYQs for Analysis of variance (ANOVA) with explanations for effective preparation. Practice of CUET PG Statistics PYQs including Analysis of variance (ANOVA) questions regularly will improve accuracy, speed, and confidence in the CUET PG 2026 exam.

CUET PG PYQs for Analysis of variance (ANOVA) with Solutions

1.
For the given ANOVA table:

\[ \begin{array}{|l|c|c|} \hline \textbf{Source of variation} & \textbf{Sum of squares} & \textbf{Degrees of freedom} \\ \hline \text{Service station} & 6810 & 9 \\ \text{Rating} & 400 & 4 \\ \text{Total} & 9948 & 49 \\ \hline \end{array} \]

The test statistic to test that there is no significant difference between the service stations is:
- 8.6
- 12.95
- 9.95
- 6.85
View Solution
2.
From a set of data involving four "tropical feed stuffs A, B, C and D", tried on 20 chicks, the following information was extracted:

\[ \begin{array}{|l|c|c|} \hline \textbf{Source of variation} & \textbf{Sum of squares} & \textbf{Degrees of freedom} \\ \hline \text{Treatment} & 26000 & 3 \\ \text{Error} & 11500 & 16 \\ \hline \end{array} \]

All the 20 chicks were treated alike, except for the feeding treatment, and each feeding treatment was given to 5 chicks. Then, the critical difference between any two means is:
- 30.95
- 39.50
- 35.94
- 32.80
View Solution
3.
A test based on critical region $W$ is said to be unbiased for testing $H_0: \theta = \theta_0$ against $H_1: \theta \ne \theta_0$ if (where $\alpha$ and $\beta$ are Type I and Type II errors respectively)
- $\beta \ge \alpha$
- $1 - \beta < \alpha$
- $\beta \le \alpha$
- $1 - \beta \ge \alpha$
View Solution
4.
For the given model $x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m$, the degrees of freedom corresponding to sum of squares due to error is:
- $ (p-1)(q-1) $
- $ pq(m-1) $
- $ (pqm - p - q) $
- $ (pqm - 1) $
View Solution
5.
For the given model $x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m$, under the assumption of the normality of the parent population, the p.d.f. of $y = \frac{S_{AB}^2}{\sigma_e^2}$, is
- Gamma with parameters $(q/2, 2)$
- Gamma with parameters $(pq/2, 2)$
- Gamma with parameters $((p-1)(q-1)/2, 2)$
- Gamma with parameters $((p-1)/2, 2)$
View Solution
6.
Minimum number of replications required, when the coefficient of the variation for the plot values is given to be 12%, for an observed difference of 10% among the sample means to be significant at 5% level, is
- 5
- 7
- 8
- 11
View Solution
7.
It is given that there are six treatments and four blocks,

\[ \begin{array}{|l|cccccc|} \hline \textbf{Treatment totals} & T_1 & T_2 & T_3 & T_4 & T_5 & T_6 \\ & 63 & 65 & 57 & 64 & 65 & 66 \\ \hline \textbf{Block totals} & B_1 & B_2 & B_3 & B_4 & & \\ & 90 & 85 & 106 & 98 & & \\ \hline \end{array} \]

and that $ G = \sum_i \sum_j y_{ij} = 380 $, then the sum of squares due to treatment is:
- 9
- 18
- 13
- 17
View Solution

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CUET PG PYQs for Analysis of variance (ANOVA) with Solutions: Practice CUET PG Previous Year Questions

CUET PG PYQs for Analysis of variance (ANOVA) with Solutions

3.
A test based on critical region \(W\) is said to be unbiased for testing \(H_0: \theta = \theta_0\) against \(H_1: \theta \ne \theta_0\) if (where \(\alpha\) and \(\beta\) are Type I and Type II errors respectively)

4.
For the given model \(x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m\), the degrees of freedom corresponding to sum of squares due to error is:

5.
For the given model \(x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m\), under the assumption of the normality of the parent population, the p.d.f. of \(y = \frac{S_{AB}^2}{\sigma_e^2}\), is

6.
Minimum number of replications required, when the coefficient of the variation for the plot values is given to be 12%, for an observed difference of 10% among the sample means to be significant at 5% level, is

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CUET PG PYQs for Analysis of variance (ANOVA) with Solutions

3.A test based on critical region \(W\) is said to be unbiased for testing \(H_0: \theta = \theta_0\) against \(H_1: \theta \ne \theta_0\) if (where \(\alpha\) and \(\beta\) are Type I and Type II errors respectively)

4.For the given model \(x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m\), the degrees of freedom corresponding to sum of squares due to error is:

5.For the given model \(x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m\), under the assumption of the normality of the parent population, the p.d.f. of \(y = \frac{S_{AB}^2}{\sigma_e^2}\), is

6.Minimum number of replications required, when the coefficient of the variation for the plot values is given to be 12%, for an observed difference of 10% among the sample means to be significant at 5% level, is

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3.
A test based on critical region \(W\) is said to be unbiased for testing \(H_0: \theta = \theta_0\) against \(H_1: \theta \ne \theta_0\) if (where \(\alpha\) and \(\beta\) are Type I and Type II errors respectively)

4.
For the given model \(x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m\), the degrees of freedom corresponding to sum of squares due to error is:

5.
For the given model \(x_{ijk} = \mu + \alpha_i + \beta_j + \gamma_{ij} + e_{ijk}; i=1, \dots,p; j=1, \dots,q; k=1, \dots,m\), under the assumption of the normality of the parent population, the p.d.f. of \(y = \frac{S_{AB}^2}{\sigma_e^2}\), is

6.
Minimum number of replications required, when the coefficient of the variation for the plot values is given to be 12%, for an observed difference of 10% among the sample means to be significant at 5% level, is