JEE Advanced 2025 Question Paper- Download Paper 1 and Paper 2 Question Paper with Answer Key

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Shivam Yadav

Educational Content Expert | Updated on - May 19, 2025

The JEE Advanced Question Paper 2025 with Solution PDF is available here once the exam is over.  The JEE Advanced 2025 has been scheduled for 18 May 2025. The exam is conducted in two parts, Paper 1 and Paper 2, each for 3 hours and consisting of sections like Physics, Chemistry, and Mathematics. Each paper consists of 48 questions divided equally between the three sections, with a mix of MCQs, Numerical answer-type questions, and matching or matrix-type questions.

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JEE Advanced 2025 Question Paper- Download Paper 1 and Paper 2 Question Paper with Answers and Solution PDF

JEE Advanced Question Paper 2025 with Solution PDF

Paper Name Question Paper Link Solutions Link
JEE Advanced 2025 Paper 1 Question Paper (English) Download PDF Check Solutions
JEE Advanced 2025 Paper 2 Question Paper (English) Download PDF Check Solutions

JEE Advanced Question 2025 Paper in Hindi

Paper Name Question Paper Link
JEE Advanced 2025 Paper 1 Question Paper (Hindi) Download PDF
JEE Advanced 2025 Paper 2 Question Paper (Hindi) Download PDF

JEE Advanced 2025 Question Paper PDF (Official)

IIT Kanpur has released the JEE Advanced 2025 Question Paper PDFs for Paper 1 and Paper 2 in English and Hindi:

Paper and Language Question Paper Link
JEE Advanced 2025 Paper 1 Question Paper (English) Download PDF
JEE Advanced 2025 Paper 1 Question Paper (Hindi) Download PDF
JEE Advanced 2025 Paper 2 Question Paper (English) Download PDF
JEE Advanced 2025 Paper 2 Question Paper (Hindi) Download PDF

JEE Advanced 2025 Exam Hall Strategy

JEE Advanced 2025 Marking Scheme – Paper 1 & Paper 2

In the JEE Advanced 2025 paper, each paper (Paper 1 and Paper 2) is divided into 3 Subjects – Physics, Chemistry, and Mathematics. Each subject section generally consists of different types of questions like MCQs, Numerical Value answers, and matching or matrix-type questions, each with its own marking rule.

Section Question Type No. of Questions Marks for Correct Answer Negative Marking Partial Marking
Section 1 MCQs (Single Correct Option) 4 +3 –1 No
Section 2 MCQs (Multiple Correct Questions) 3 +4 (if all correct) –2 Yes
Section 3 Numerical Answer Type (NAT) 6 +4 0 No
Section 4 Matching-Type Questions 4 +3 –1 (varies) Sometimes

*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.

JEE Advanced 2025 Questions

  • 1.
    Let $ a_0, a_1, ..., a_{23} $ be real numbers such that $$ \left(1 + \frac{2}{5}x \right)^{23} = \sum_{i=0}^{23} a_i x^i $$ for every real number $ x $. Let $ a_r $ be the largest among the numbers $ a_j $ for $ 0 \leq j \leq 23 $. Then the value of $ r $ is ________.


      • 2.

        The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____


          • 3.
            The total number of real solutions of the equation $$ \theta = \tan^{-1}(2 \tan \theta) - \frac{1}{2} \sin^{-1} \left( \frac{6 \tan \theta}{9 + \tan^2 \theta} \right) $$ is
            (Here, the inverse trigonometric functions $ \sin^{-1} x $ and $ \tan^{-1} x $ assume values in $[-\frac{\pi}{2}, \frac{\pi}{2}]$ and $(-\frac{\pi}{2}, \frac{\pi}{2})$, respectively.)

              • 1
              • 2
              • 3
              • 5

            • 4.
              Let $$ \alpha = \frac{1}{\sin 60^\circ \sin 61^\circ} + \frac{1}{\sin 62^\circ \sin 63^\circ} + \cdots + \frac{1}{\sin 118^\circ \sin 119^\circ}. $$ Then the value of $$ \left( \frac{\csc 1^\circ}{\alpha} \right)^2 $$ is \rule{1cm}{0.15mm}.


                • 5.
                  One of the products formed from the reaction of permanganate ion with iodide ion in neutral aqueous medium is:

                    • \( \text{I}_2 \)
                    • \( \text{IO}_3^- \)
                    • \( \text{IO}_4^- \)
                    • \( \text{IO}_2^- \) 

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                  Note: The application fee for foreign nationals from SAARC countries is USD 75 while for candidates who belong to Non-SAARC countries, the application fee is USD 150. Indian Nationals (including PIO/OCI) who have chosen exam centers outside India, have to pay USD 75 as the application fee.

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