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Content Writer | Updated On - Jul 15, 2024
KCET 2023 question paper with solution is available for download. Candidates can check and download code-wise question papers for Mathematics, Biology, Physics, Chemistry and Kannada language here. Each question had one mark with no negative marking.
KCET 2023 Question Paper with Answers PDF
Paper | Exam Date | Code | Question Paper with Solutions |
---|---|---|---|
Biology | May 20, 2023 | Code B4 | Check here |
Code C1 | Check here | ||
Code D2 | Check here | ||
Mathematics | May 20, 2023 | Code A1 | Check here |
Code A2 | Check here | ||
Code A3 | Check here | ||
Code A4 | Check here | ||
Code B1 | Check here | ||
Code B3 | Check here | ||
Code C2 | Check here | ||
Code C3 | Check here | ||
Code C4 | Check here | ||
Code D1 | Check here | ||
Code D2 | Check here | ||
Physics | May 21, 2023 | Code A3 | Check here |
Chemistry | May 21, 2023 | - | Check Here |
Kannada Language | May 22, 2023 | - | To be Updated |
KCET 2023 Questions
1. The equivalent resistance between the points A and B in the following circuit is
![Electric circuit of Resistors](https://images.collegedunia.com/public/qa/images/content/2024_03_20/image_c1a3ed761710903861035.png)
![Electric circuit of Resistors](https://images.collegedunia.com/public/qa/images/content/2024_03_20/image_c1a3ed761710903861035.png)
- 5.5 Ω
- 0.05 Ω
- 5 Ω
- 0.5 Ω
2. Ten identical cells each emf 2V and internal resistance 1Ω are connected in series with two cells wrongly connected. A resistor of 10Ω is connected to the combination. What is the current through the resistor?
- 2.4 A
- 0.6 A
- 1.2 A
- 1.8 A
3. Five capacitors each of value 1 μF are connected as shown in the figure. The equivalent capacitance between A and B is
![Five capacitors each of value 1 μF](https://images.collegedunia.com/public/qa/images/content/2024_03_20/image_18ba01c71710903256816.png)
![Five capacitors each of value 1 μF](https://images.collegedunia.com/public/qa/images/content/2024_03_20/image_18ba01c71710903256816.png)
- 1 μF
- 2 μF
- 5 μF
- 3 μF
4. The modulus of the complex number \(\frac{(1+i)^2(1+3i)}{(2-6i)(2-2i)}\) is
- \(\frac{1}{\sqrt2}\)
- \(\frac{4}{\sqrt2}\)
- \(\frac{\sqrt2}{4}\)
- \(\frac{2}{\sqrt2}\)
5. A stretched wire of a material whose Young's modulus Y = 2 × 1011 Nm-2 has Poisson's ratio of 0.25. Its lateral strain εl = 10-3. The elastic energy density of the wire is
- 1 × 105 Jm-3
- 4 × 105 Jm-3
- 8 × 105 Jm-3
- 16 × 105 Jm-3
*The article might have information for the previous academic years, which will be updated soon subject to the notification issued by the University/College.
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