KC+CET PYQs for Magnetic Field Due to a Current Element, Biot-Savart Law with Solutions: Practice KCET Previous Year Questions

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Yashodeep Mahurkar

Updated on - Feb 16, 2026

Magnetic Field Due to a Current Element, Biot-Savart Law is an important topic in the Physics section in KCET exam. Practising this topic will increase your score overall and make your conceptual grip on KCET exam stronger.

This article gives you a full set of KCET PYQs for Magnetic Field Due to a Current Element, Biot-Savart Law with explanations for effective preparation. Practice of KCET Physics PYQs including Magnetic Field Due to a Current Element, Biot-Savart Law questions regularly will improve accuracy, speed, and confidence in the KCET 2026 exam.

KCET PYQs for Magnetic Field Due to a Current Element, Biot-Savart Law with Solutions

1.
A current I flows in the anticlockwise direction through a square loop of side a lying in the xoy plane with its center at the origin. The magnetic induction at the center of the square loop is
- $\frac{2 \sqrt{2} \mu_0 I}{\pi a }\hat{e}_x$
- $\frac{2 \sqrt{2} \mu_0 I}{\pi a }\hat{e}_z$
- $\frac{2 \sqrt{2} \mu_0 I}{\pi a^2 }\hat{e}_z$
- $\frac{2 \sqrt{2} \mu_0 I}{\pi a^2 }\hat{e}_x$
View Solution
2.
ABCD is a square loop made of an uniform conducting wire. The current enters the loop at A and leaves at D. The magnetic field is
- Zero at all points outside the loop
- Zero at all points inside the loop
- Zero only at the centre of the loop
- Maximum at the centre of the loop.
View Solution
3.
The correct Biot-Savart law in vector form is
- $d \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I\left(d \vec{l} \times \vec{r} \right)}{r^{2}} $
- $d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I\left(d \vec{l} \times \vec{r} \right)}{r^{3}}$
- $d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I d \vec{l} }{r^{2}} $
- $d \, \vec{B} = \frac{\mu_{0}}{4 \pi} \frac{I d \vec{l} }{r^{3}} $
View Solution
4.
Two concentric coils each of radius equal to $2\, \pi$ cm are placed right angles to each other.If $3\,A$ and $4\,A$ are the currents flowing through the two coils respectively. The magnetic induction $(in\, Wb\, m^{-2})$ at the centre of the coils will be
- $12\times 10^{-5}$
- $10\times 10^{-5}$
- $5\times 10^{-5}$
- $7 \times 10^{-5}$
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KCET PYQs for Magnetic Field Due to a Current Element, Biot-Savart Law with Solutions

1.A current I flows in the anticlockwise direction through a square loop of side a lying in the xoy plane with its center at the origin. The magnetic induction at the center of the square loop is

2.ABCD is a square loop made of an uniform conducting wire. The current enters the loop at A and leaves at D. The magnetic field is

3.The correct Biot-Savart law in vector form is

4.Two concentric coils each of radius equal to $2\, \pi$ cm are placed right angles to each other.If $3\,A$ and $4\,A$ are the currents flowing through the two coils respectively. The magnetic induction $(in\, Wb\, m^{-2})$ at the centre of the coils will be

Fees Structure

Structure based on different categories

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1.
A current I flows in the anticlockwise direction through a square loop of side a lying in the xoy plane with its center at the origin. The magnetic induction at the center of the square loop is

2.
ABCD is a square loop made of an uniform conducting wire. The current enters the loop at A and leaves at D. The magnetic field is

3.
The correct Biot-Savart law in vector form is

4.
Two concentric coils each of radius equal to $2\, \pi$ cm are placed right angles to each other.If $3\,A$ and $4\,A$ are the currents flowing through the two coils respectively. The magnetic induction $(in\, Wb\, m^{-2})$ at the centre of the coils will be