KC+CET PYQs for Limits and Derivatives with Solutions: Practice KCET Previous Year Questions

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Yashodeep Mahurkar

Updated on - Feb 16, 2026

Limits and Derivatives is an important topic in the Mathematics section in KCET exam. Practising this topic will increase your score overall and make your conceptual grip on KCET exam stronger.

This article gives you a full set of KCET PYQs for Limits and Derivatives with explanations for effective preparation. Practice of KCET Mathematics PYQs including Limits and Derivatives questions regularly will improve accuracy, speed, and confidence in the KCET 2026 exam.

KCET PYQs for Limits and Derivatives with Solutions

1.
$ \displaystyle\lim _{n \rightarrow \infty} n \sin \frac{2 \pi}{3 n} \cdot \cos \frac{2 \pi}{3 n}$ is
- $1$
- $\frac {\pi} {3}$
- $\frac {\pi}{6}$
- $\frac {2\pi}{3}$
View Solution
2.
If the function $f(x)$ defined by $\frac {x^{100}}{100}+\frac {x^{99}}{100}+\dots \frac {x^2}{100}+x+1$ then $f'(0)$ is equal to
- $100$
- $-1$
- $100 f'(0)$
- $1$
View Solution
3.
$\displaystyle\lim_{x \to 0} \frac{xe^x - \sin \, x}{x}$ is equal to
- 3
- 1
- 0
- 2
View Solution

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KCET PYQs for Limits and Derivatives with Solutions

1.$ \displaystyle\lim _{n \rightarrow \infty} n \sin \frac{2 \pi}{3 n} \cdot \cos \frac{2 \pi}{3 n}$ is

2.If the function $f(x)$ defined by $\frac {x^{100}}{100}+\frac {x^{99}}{100}+\dots \frac {x^2}{100}+x+1$ then $f'(0)$ is equal to

3.$\displaystyle\lim_{x \to 0} \frac{xe^x - \sin \, x}{x}$ is equal to

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1.
$ \displaystyle\lim _{n \rightarrow \infty} n \sin \frac{2 \pi}{3 n} \cdot \cos \frac{2 \pi}{3 n}$ is

2.
If the function $f(x)$ defined by $\frac {x^{100}}{100}+\frac {x^{99}}{100}+\dots \frac {x^2}{100}+x+1$ then $f'(0)$ is equal to

3.
$\displaystyle\lim_{x \to 0} \frac{xe^x - \sin \, x}{x}$ is equal to