KC+CET PYQs for Law of Chemical Equilibrium and Equilibrium Constant with Solutions: Practice KCET Previous Year Questions

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Yashodeep Mahurkar

Updated on - Feb 16, 2026

Law of Chemical Equilibrium and Equilibrium Constant is an important topic in the Chemistry section in KCET exam. Practising this topic will increase your score overall and make your conceptual grip on KCET exam stronger.

This article gives you a full set of KCET PYQs for Law of Chemical Equilibrium and Equilibrium Constant with explanations for effective preparation. Practice of KCET Chemistry PYQs including Law of Chemical Equilibrium and Equilibrium Constant questions regularly will improve accuracy, speed, and confidence in the KCET 2026 exam.

KCET PYQs for Law of Chemical Equilibrium and Equilibrium Constant with Solutions

1.
At 500 K, for a reversible reaction \(A_{2_{(g)}}+B_{2_{(g)}}⇌2AB_{(g)}\) in a closed container, K_C = 2 × 10^-5. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant K_C in the presence of catalyst at the same temperature is
- 2 × 10^-4
- 2 × 10^-6
- 2 × 10^-10
- 2 × 10^-5
View Solution
2.
Solubility product of CaC₂O₄ at a given temperature in pure water is 4×10^-9 (mol L^-1)². Solubility of CaC₂O₄ at the same temperature is:
- 6.3×10^-5 mol L^-1
- 2×10^-5 mol L^-1
- 2×10^-4 mol L^-1
- 6.3×10^-4 mol L^-1
View Solution
3.
The chemical equilibrium of a reversible reaction is not influenced by :
- concentration of the reactants
- Temperature
- Pressure
- Catalyst
View Solution
4.
1 mole of HI is heated in a closed container of capacity of 2 L. At equilibrium half a mole of HI is dissociated. The equilibrium constant of the reaction is
- 0.25
- 1
- 0.35
- 0.5
View Solution
5.
For the reaction A(g) + B(g) ⇌ C(g) + D(g); ΔH = -QKJ
The equilibrium constant cannot be disturbed by
- Addition of A
- Addition of D
- Increasing of pressure
- Increasing of temperature
View Solution

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KCET PYQs for Law of Chemical Equilibrium and Equilibrium Constant with Solutions

1.At 500 K, for a reversible reaction \(A_{2_{(g)}}+B_{2_{(g)}}⇌2AB_{(g)}\) in a closed container, KC = 2 × 10-5. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant KC in the presence of catalyst at the same temperature is

2.Solubility product of CaC2O4 at a given temperature in pure water is 4×10-9 (mol L-1)2. Solubility of CaC2O4 at the same temperature is:

3.The chemical equilibrium of a reversible reaction is not influenced by :

4.1 mole of HI is heated in a closed container of capacity of 2 L. At equilibrium half a mole of HI is dissociated. The equilibrium constant of the reaction is

5.For the reaction A(g) + B(g) ⇌ C(g) + D(g); ΔH = -QKJThe equilibrium constant cannot be disturbed by

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1.
At 500 K, for a reversible reaction \(A_{2_{(g)}}+B_{2_{(g)}}⇌2AB_{(g)}\) in a closed container, K_C = 2 × 10^-5. In the presence of catalyst, the equilibrium is attaining 10 times faster. The equilibrium constant K_C in the presence of catalyst at the same temperature is

2.
Solubility product of CaC₂O₄ at a given temperature in pure water is 4×10^-9 (mol L^-1)². Solubility of CaC₂O₄ at the same temperature is:

3.
The chemical equilibrium of a reversible reaction is not influenced by :

4.
1 mole of HI is heated in a closed container of capacity of 2 L. At equilibrium half a mole of HI is dissociated. The equilibrium constant of the reaction is

5.
For the reaction A(g) + B(g) ⇌ C(g) + D(g); ΔH = -QKJ
The equilibrium constant cannot be disturbed by