KC+CET PYQs for Hyperbola with Solutions: Practice KCET Previous Year Questions

Updated on - Feb 16, 2026

Hyperbola is an important topic in the Mathematics section in KCET exam. Practising this topic will increase your score overall and make your conceptual grip on KCET exam stronger.

This article gives you a full set of KCET PYQs for Hyperbola with explanations for effective preparation. Practice of KCET Mathematics PYQs including Hyperbola questions regularly will improve accuracy, speed, and confidence in the KCET 2026 exam.

KCET PYQs for Hyperbola with Solutions

1.
The equation to the normal to the hyperbola $\frac {x^2}{16}- \frac {y^2}{9}=1$ at $(-4,0)$ is
- 2x - 3y = 1
- x = 0
- x = 1
- y = 0
View Solution
2.
The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt{2}$. Its equation is
- $x^2 - y^2 = 32$
- $\frac{x^2}{4} - \frac{y^2}{9} = 1 $
- $2x^2 - 3y^2 = 7 $
- $y^2 - x^2 = 32 $
View Solution
3.
The equation of the director circle of the hyperbola $\frac {x^{2}} {16}-\frac{y^{2}} {4}=1$ is given by .............
- $x^2 + y^2 = 16$
- $x^2 + y^2 = 4$
- $x^2 + y^2 = 20$
- $x^2 + y^2 = 12$
View Solution
4.
The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt2$. Its equation is
- 2x² - 3y² = 7
- x² - y² = 32
- y² - x² = 32
- $\frac{x^2}{4}-\frac{y^2}{9}=1$
View Solution

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KCET PYQs for Hyperbola with Solutions: Practice KCET Previous Year Questions

KCET PYQs for Hyperbola with Solutions

1.
The equation to the normal to the hyperbola $\frac {x^2}{16}- \frac {y^2}{9}=1$ at $(-4,0)$ is

2.
The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt{2}$. Its equation is

3.
The equation of the director circle of the hyperbola $\frac {x^{2}} {16}-\frac{y^{2}} {4}=1$ is given by .............

4.
The distance between the foci of a hyperbola is 16 and its eccentricity is \(\sqrt2\). Its equation is

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KCET PYQs for Hyperbola with Solutions

1.The equation to the normal to the hyperbola $\frac {x^2}{16}- \frac {y^2}{9}=1$ at $(-4,0)$ is

2.The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt{2}$. Its equation is

3.The equation of the director circle of the hyperbola $\frac {x^{2}} {16}-\frac{y^{2}} {4}=1$ is given by .............

4.The distance between the foci of a hyperbola is 16 and its eccentricity is \(\sqrt2\). Its equation is

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1.
The equation to the normal to the hyperbola $\frac {x^2}{16}- \frac {y^2}{9}=1$ at $(-4,0)$ is

2.
The distance between the foci of a hyperbola is 16 and its eccentricity is $\sqrt{2}$. Its equation is

3.
The equation of the director circle of the hyperbola $\frac {x^{2}} {16}-\frac{y^{2}} {4}=1$ is given by .............

4.
The distance between the foci of a hyperbola is 16 and its eccentricity is \(\sqrt2\). Its equation is