KCET 2022 Biology D-3 Question Paper with Answer Key pdf is available for download. The exam was conducted by Karnataka Examination Authority (KEA) on June 16, 2022. In terms of difficulty level, KCET Biology was of Easy to Moderate level. The question paper comprised a total of 60 questions.
KCET 2022 Biology (D-3) Question Paper with Answer Key
| KCET Biology (D-3) Question Paper 2022 with Answer Key | Check Solution |
Example for Non-Mendelian disorder:
View Solution
Step 1: Mendelian disorders → single gene mutations (autosomal/X-linked).
Step 2:
- Thalassemia, Cystic fibrosis, Haemophilia → gene mutations → Mendelian.
- Down's syndrome → trisomy 21 → chromosomal aneuploidy → non-Mendelian.
Hence, (D) is correct. Quick Tip: - Mendelian: Sickle cell, CF, Haemophilia - Non-Mendelian: Down’s, Turner’s, Klinefelter’s (chromosomal)
Gynecomastia is a symptom of
View Solution
Step 1: Klinefelter’s syndrome → XXY male.
Step 2: Symptoms:
- Tall, sterile, gynecomastia (breast development due to estrogen excess).
Step 3: Turner’s (XO) → female; others → no gynecomastia.
Hence, (D) is correct. Quick Tip: - Klinefelter’s (XXY): Male + gynecomastia - Turner’s (XO): Female, webbed neck
The affected male in the pedigree chart is symbolized by:
View Solution
Step 1: Standard pedigree symbols:
- Male → square
- Female → circle
- Affected → shaded/filled
Step 2: Affected male → shaded square (■).
Hence, (A) is correct. Quick Tip: - Pedigree: – Male normal: □ – Male affected: ■ – Female normal: ○ – Female affected: ●
The given diagram represents:
View Solution
Step 1: Diagram shows DNA wrapped around histone core.
Step 2: This is "beads on a string" → nucleosome (basic chromatin unit).
Step 3:
- Mesosome: Bacterial
- Chromosome: Condensed
- Ribosome: Protein synthesis
Hence, nucleosome. Quick Tip: - Nucleosome: DNA + histone octamer (2 each H2A, H2B, H3, H4) - 11 nm fiber
Which of the following hormones is not secreted by human placenta?
View Solution
Step 1: Placental hormones:
- hCG, hPL, progesterone, estrogen, relaxin.
Step 2: FSH → anterior pituitary → stimulates follicles.
Hence, not secreted by placenta. Quick Tip: - Placenta: hCG, Progesterone, Relaxin - Pituitary: FSH, LH
Which of the following is correctly matched?
View Solution
Step 1:
- Bulbil: Vegetative bud → Agave (correct).
- Gemmules: Sponges
- Conidia: Fungi (Penicillium)
- Spores: Ferns, fungi
Hence, only (A) is correct. Quick Tip: - Bulbil: Agave, Onion - Gemmule: Sponge - Conidia: Aspergillus
The technique advised by a doctor to overcome the problem of infertility:
View Solution
Step 1:
- ART → Assisted Reproductive Technology (IVF, IUI, ZIFT, GIFT).
- RCH: Program
- MTP: Abortion
- RTI: Infection
Step 2: For infertility → ART.
Hence, (D). Quick Tip: - Infertility: ART (IVF, ICSI) - Contraception: MTP
Amniocentesis is a process to:
View Solution
Step 1: Amniocentesis → amniotic fluid sampling (16–18 weeks).
Step 2: Fetal cells → karyotyping → sex determination, genetic disorders.
Step 3: Heart/brain → ultrasound; culture → secondary.
Hence, primary → sex & genetics. Quick Tip: - Amniocentesis: Fetal karyotype - Banned for sex selection in India
The first human like being is
View Solution
Step 1: Homo habilis (2.4–1.4 mya) → first in Homo genus.
Step 2: "Handy man" → used stone tools.
Step 3:
- H. erectus: Fire, upright
- H. sapiens: Modern
Hence, first human-like → H. habilis. Quick Tip: - Evolution: Australopithecus → H. habilis → H. erectus → H. sapiens
XO type of sex determination and XY type of sex determination are the examples of
View Solution
Step 1:
- XY: Male = XY (heterogametic)
- XO: Male = XO (heterogametic)
Step 2: In both, male produces two gamete types (X/Y or X/O).
Step 3: Female → XX (homogametic).
Hence, male heterogamety. Quick Tip: - Male heterogamety: XY, XO - Female heterogamety: ZW (birds)
One of the side-effects of the use of anabolic steroids in females
View Solution
Step 1: Anabolic steroids → synthetic testosterone.
Step 2: In females → androgenic effects:
- Deep voice
- Facial hair
- Enlarged clitoris → masculinisation.
Step 3: Liver damage possible, but masculinisation is primary in females.
Hence, (B). Quick Tip: - Females + steroids: Virilization (masculinisation) - Males: Gynecomastia, infertility
Which one of the following is an opiate narcotics?
View Solution
Step 1: Opiates → from opium poppy.
Step 2:
- Morphine, Heroin, Codeine → opiates.
- Amphetamines: Stimulants
- LSD: Hallucinogen
- Barbiturates: Sedatives
Hence, morphine. Quick Tip: - Opiates: Morphine, Heroin - Cannabinoids: THC - Cocaine: Stimulant
The large holes in ‘Swiss – Cheese’ are made by a
View Solution
Step 1: Swiss cheese → Propionibacterium shermanii.
Step 2: Ferments lactate → propionic acid + CO₂.
Step 3: CO₂ bubbles → large holes (eyes).
Step 4: Not methane, fungus, or machine.
Hence, (A). Quick Tip: - Swiss cheese eyes: CO₂ from Propionibacterium - Roquefort: Penicillium (blue veins)
Which vitamin is increased by ‘LAB’ in curd?
View Solution
Step 1: LAB → Lactobacillus in curd.
Step 2: Synthesizes Vitamin B₁₂ (cobalamin) during fermentation.
Step 3:
- Vitamin C → destroyed by heat
- Vitamin E → not microbial
- Vitamin B → vague
Hence, B₁₂. Quick Tip: - Curd: ↑ B₁₂, B₂, folate - Yogurt: Probiotic + vitamins
Enzyme which is useful to remove the oily stains in laundry?
View Solution
Step 1: Oily stains → lipids.
Step 2: Lipase → hydrolyzes fats → glycerol + fatty acids.
Step 3:
- Amylase: Starch
- Renin: Milk clotting
- Protease: Proteins
Hence, lipase. Quick Tip: - Detergent enzymes: – Lipase → Oil – Protease → Blood – Amylase → Food
DNA replicates semicontinuously was first shown in:
View Solution
Step 1: Meselson & Stahl (1958) → E. coli.
Step 2: \(^{15}\)N → \(^{14}\)N → hybrid DNA.
Step 3: Okazaki fragments → lagging strand → semicontinuous.
Hence, E. coli. Quick Tip: - Semiconservative: Meselson-Stahl - Semicontinuous: Okazaki (lagging strand)
A series of experiments were conducted by Frederick Griffith in 1928, on transforming principle with:
View Solution
Step 1: Griffith → S (smooth) and R (rough) strains.
Step 2: Heat-killed S + live R → virulent mice.
Step 3: Transforming principle → DNA.
Hence, S. pneumoniae. Quick Tip: - Griffith (1928): Transformation - Avery (1944): DNA is genetic material
The number of codons effective in coding twenty amino acids:
View Solution
Step 1: Total codons = \(4^3 = 64\).
Step 2:
- 3 stop codons: UAA, UAG, UGA
- 61 sense codons → 20 amino acids (degenerate).
Hence, 61. Quick Tip: - 64 total - 61 code aa - 3 stop - AUG: Start + Met
Which aspect forms the basis of DNA finger-printing?
View Solution
Step 1: DNA fingerprinting → VNTRs (Variable Number Tandem Repeats).
Step 2: Satellite DNA → highly repetitive, variable repeats.
Step 3: Unique pattern per individual.
Hence, (A). Quick Tip: - VNTRs/Minisatellites → DNA fingerprinting - Alec Jeffreys (1984)
Identify the most infectious and fatal type of malarial parasite:
View Solution
Step 1: P. falciparum → cerebral malaria, high parasitemia.
Step 2: Causes blackwater fever, organ failure.
Step 3: Most fatal (WHO).
Hence, (A). Quick Tip: - P. falciparum: Malignant tertian, fatal - P. vivax: Benign tertian, relapsing
The type of antibodies produced during the allergic reaction
View Solution
Step 1: Allergic reaction → Type I hypersensitivity.
Step 2: Mediated by IgE bound to mast cells/basophils.
Step 3: Allergen → cross-links IgE → histamine release → allergy.
Step 4:
- IgG, IgM: Immunity
- IgA: Mucosal
Hence, IgE. Quick Tip: - Allergy: IgE → Mast cell degranulation - Anaphylaxis: Severe IgE reaction
ADA deficiency can be cured by
View Solution
Step 1: ADA deficiency → SCID (no T/B cells).
Step 2: Bone marrow → source of hematopoietic stem cells → produce healthy lymphocytes.
Step 3: First gene therapy → ADA gene into lymphocytes.
Hence, bone-marrow transplantation. Quick Tip: - ADA deficiency: SCID - Cure: Bone marrow transplant / Gene therapy
Average natality rate in our village is 25, average mortality is 24, immigration 2 and emigration 3 and the net increase in population is :
View Solution
Step 1: Population change = (Births + Immigration) – (Deaths + Emigration)
Step 2:
- Births = 25
- Immigration = 2
- Deaths = 24
- Emigration = 3
Step 3: \[ \Delta P = (25 + 2) - (24 + 3) = 27 - 27 = 0 \]
Hence, net increase = 0. Quick Tip: - Population growth: \(\Delta P = (B + I) - (D + E)\) - Zero growth: \(B + I = D + E\)
The term “Molecular Scissors” refers to
View Solution
Step 1: Molecular scissors → cut DNA at specific sites.
Step 2: Restriction enzymes (e.g., EcoRI) → recognize palindromes → cleave.
Step 3: Used in cloning.
Step 4: Polymerases → synthesize, not cut.
Hence, restriction enzyme. Quick Tip: - Restriction enzyme → "Molecular scissors" - DNA ligase → "Molecular glue"
What does the sample of given base sequence represent ? 5' – GAATTC – 3' 3' – CTTAAG – 5'
View Solution
Step 1: Sequence: \(5'\)-GAATTC-\(3'\) \(3'\)-CTTAAG-\(5'\)
Step 2: Reads same on complementary strand in reverse → palindrome.
Step 3: Recognized by EcoRI.
Hence, palindromic sequence. Quick Tip: - Palindrome: 5'-GAATTC-3' = 3'-CTTAAG-5' - EcoRI cuts between G and A
Gel electrophoresis is used for
View Solution
Step 1: Agarose gel → DNA migrates to anode (negative charge).
Step 2: Smaller fragments move faster.
Step 3:
- Cutting → restriction enzyme
- Joining → ligase
- Isolation → extraction
Hence, separation by size. Quick Tip: - Gel electrophoresis: – Small DNA → far – Large DNA → near well
An antibiotic resistance gene in a vector usually helps in the selection of
View Solution
Step 1: Vector → ampᵣ gene.
Step 2: Only transformed cells grow on ampicillin.
Step 3: Non-recombinants also grow → use insertional inactivation.
Hence, first selects transformants. Quick Tip: - Selectable marker: ampᵣ → transformants - Blue-white: X-gal → recombinants (white)
Silencing of specific mRNA in RNAi is by
View Solution
Step 1: RNAi → dsRNA introduced.
Step 2: Dicer → cuts → siRNA.
Step 3: RISC → degrades target mRNA.
Step 4: SSRN → not a term.
Hence, dsRNA. Quick Tip: - RNAi: dsRNA → Dicer → siRNA → RISC → mRNA cleavage
Cry-IAC effectively controls,
View Solution
Step 1: Cry-IAC → Bt toxin.
Step 2: Targets lepidopteran larvae (moths/butterflies).
Step 3: Cotton bollworm (Helicoverpa) → lepidopteran.
Step 4:
- Cry-IIAB: Nematodes
- Corn borer: Different Cry gene
Hence, cotton bollworms. Quick Tip: - Cry-I: Lepidoptera (bollworm) - Cry-II: Diptera + Lepidoptera - Cry-III: Coleoptera
Particulates of phantom{abcde} size pose greatest risk to human health.
View Solution
Step 1: PM₂.₅ → particles < 2.5 μm in diameter.
Step 2: Small size → penetrate deep into lungs → alveoli → enter bloodstream.
Step 3: Cause cardiovascular disease, lung cancer, COPD.
Step 4: PM₁₀ (>2.5 μm) → trapped in upper airways.
Hence, < 2.5 μm → greatest risk. Quick Tip: - PM₂.₅: < 2.5 μm → alveoli + blood - PM₁₀: < 10 μm → nose/throat - WHO: PM₂.₅ < 10 μg/m³ (annual mean)
Maintenance of constant internal environment is called as
View Solution
Step 1: Homeostasis → maintaining stable internal conditions (pH, temperature, ions, glucose).
Step 2:
- Thermoregulation: Temperature
- Osmoregulation: Water/salt balance
- Metastasis: Cancer spread
Step 3: Homeostasis encompasses all.
Hence, homeostasis. Quick Tip: - Homeostasis → "Same standing" (Walter Cannon) - Negative feedback: Most common
The animals which are active during day time :
View Solution
Step 1:
- Diurnal: Active during day (e.g., humans, eagles).
- Nocturnal: Night (owls)
- Crepuscular: Dawn/dusk (rabbits)
Step 2: Vesporal, Cresporal, Auroral → not standard terms.
Hence, diurnal. Quick Tip: - Diurnal → Day - Nocturnal → Night - Crepuscular → Twilight
Which of the following statement is incorrect related to biomes ?
View Solution
Step 1: Deserts: High temperature + very low rainfall (<25 cm/year).
Step 2: (D) says more rainfall + low temperature → incorrect.
Step 3:
- (A): Grasslands → moderate rain, warm
- (B): Tundra → cold, low precipitation
- (C): Temperature + precipitation → biome distribution
Hence, (D) is incorrect. Quick Tip: - Desert: Hot, arid - Tundra: Cold, arid - Rainforest: Hot, wet
The amount of Photosynthetically active radiation captured by plants is
View Solution
Step 1: PAR (400–700 nm) → ~50% of solar radiation.
Step 2: Plants capture 2–10% of PAR for GPP.
Step 3: Most energy lost: reflection, heat, transmission.
Step 4: NPP → ~1–2% of solar energy.
Hence, 2–10%. Quick Tip: - PAR: 50% solar - GPP: 2–10% of PAR - NPP: 0.2–2% solar
The given graph represents
View Solution
Step 1: Equation: \( S = cA^Z \)
- \( S \): Species richness
- \( A \): Area
- \( c, Z \): Constants
Step 2: Species-area relationship (Alexander von Humboldt).
Step 3: Log form: \(\log S = \log c + Z \log A\) → straight line.
Hence, species-area relationship. Quick Tip: - \( S = cA^Z \) → Species-area curve - Z: 0.1–0.2 (mainland), 0.6–1.0 (islands)
Cuscuta is an example of
View Solution
Step 1: Cuscuta (dodder) → yellow, leafless vine.
Step 2: Attaches externally to host stem → haustoria penetrate → absorb nutrients.
Step 3:
- Ectoparasite: Lives outside host
- Endoparasite: Inside
- Brood parasitism: Cuckoo
Hence, ectoparasitism. Quick Tip: - Cuscuta: Stem holoparasite → ectoparasite - Rafflesia: Root endoparasite
Cell theory was formulated by
View Solution
Step 1: Cell Theory (1838–1839):
- M.J. Schleiden → all plants made of cells.
- Theodor Schwann → all animals made of cells.
Step 2: Postulates:
1. All living organisms composed of cells.
2. Cell is basic unit of life.
Step 3: Virchow (1855): "Omnis cellula-e-cellula".
Hence, Schleiden and Schwann. Quick Tip: - Cell Theory: – Schleiden (1838): Plants – Schwann (1839): Animals – Virchow: Cell division
The type of Polysaccharide present in a cotton fibre
View Solution
Step 1: Cotton fiber → seed hair of Gossypium.
Step 2: >90% cellulose (β-1,4-glucan).
Step 3:
- Glycogen: Animal storage
- Starch: Plant storage
- Inulin: Fructan (dahlia)
Hence, cellulose. Quick Tip: - Cotton: Cellulose (95%) - Wool: Protein - Jute: Lignin + cellulose
Enzyme involved in crossing over
View Solution
Step 1: Crossing over → pachytene of meiosis.
Step 2: Recombinase (Spo11, RAD51) → forms Holliday junction.
Step 3:
- Endonuclease → cuts
- Ligase → joins
- Polymerase → fills
But recombinase initiates.
Hence, recombinase. Quick Tip: - Crossing over: – Synaptonemal complex → Recombinase → Chiasma
Kranz anatomy can be seen in
View Solution
Step 1: Kranz anatomy → C4 plants.
Step 2:
- Bundle sheath with chloroplasts
- Mesophyll radial
Step 3: Maize → C4; others → C3.
Hence, maize. Quick Tip: - Kranz: C4 (maize, sugarcane) - C3: Pea, tomato, potato
Respiratory quotient of glucose is
View Solution
Step 1: RQ = \(\frac{CO_2}{O_2}\)
Step 2: Glucose: \[ C_6H_{12}O_6 + 6O_2 \rightarrow 6CO_2 + 6H_2O \]
Step 3: \[ RQ = \frac{6}{6} = 1.0 \]
Hence, 1.0. Quick Tip: - RQ: – Carbs: 1.0 – Fats: 0.7 – Proteins: 0.9 – Anaerobic: ∞
A person suddenly starts coughing while swallowing food. This coughing would have been due to improper movement of
View Solution
Step 1: Epiglottis → flap over larynx.
Step 2: Closes during swallowing → food to esophagus.
Step 3: If fails → food in trachea → cough reflex.
Hence, epiglottis. Quick Tip: - Swallowing: – Epiglottis closes larynx – Peristalsis → esophagus
Binomial nomenclature is introduced by
View Solution
Step 1: Binomial → Genus + species.
Step 2: Linnaeus → "Species Plantarum" (1753), "Systema Naturae" (1758).
Step 3:
- Bentham & Hooker → classification
- John Ray → early binomial
Hence, Linnaeus. Quick Tip: - Binomial: Linnaeus - ICBN/ICZN: Rules - Homo sapiens: Linnaeus
Bovine spongiform encephalopathy is caused by
View Solution
Step 1: BSE → Mad Cow Disease.
Step 2: Caused by prions → misfolded PrP.
Step 3: No nucleic acid → resistant.
Step 4: vCJD in humans.
Hence, prions. Quick Tip: - Prions: – BSE, CJD, Kuru, Scrapie – Protein only
Phycocrythrin and Floridean starch is found in
View Solution
Step 1: Red algae (Rhodophyta):
- Phycoerythrin (red pigment)
- Floridean starch (storage)
Step 2:
- Brown: Fucoxanthin
- BGA: Phycocyanin
- Green: Chlorophyll a,b
Hence, red algae. Quick Tip: - Red algae: – Phycoerythrin – Floridean starch – Agar, carrageenan
Different types of respiratory organs like gills, book gills, book lungs and trachea are present in
View Solution
Step 1: Arthropods:
- Gills: Crabs
- Book gills: Horseshoe crab
- Book lungs: Scorpions
- Trachea: Insects
Step 2: Others lack diversity.
Hence, arthropods. Quick Tip: - Arthropod respiration: – Gills, book gills, book lungs, trachea
Which of the following plant is used to extract Colchicine?
View Solution
Step 1: Colchicine → from Colchicum autumnale (autumn crocus).
Step 2: Inhibits spindle → polyploidy.
Hence, Colchicum. Quick Tip: - Colchicine: Colchicum autumnale - Use: Polyploidy, gout
Rows of S-shaped setae in the body of earthworm are present in all the segments, except
View Solution
Step 1: Setae → locomotion.
Step 2: Absent in:
- 1st segment
- Last segment
- Clitellum (14–16)
Step 3: Clitellum → cocoon formation.
Hence, first, last, clitellum. Quick Tip: - Earthworm setae: – Absent: 1st, last, 14–16 – S-shaped, 4 pairs/segment
The ovule of angiosperm is technically known as:
View Solution
Step 1: Ovule → integumented megasporangium.
Step 2:
- Megasporangium → produces megaspores.
- Megaspore mother cell → diploid cell inside.
- Megaspore → haploid product.
- Megasporophyll → carpel.
Step 3: Ovule = megasporangium + integuments.
Hence, megasporangium. Quick Tip: - Ovule = Megasporangium - Nucellus = Megasporangium tissue
Typical mature embryosac of angiosperm is
View Solution
Step 1: Polygonum type (common):
- 3 antipodals
- 2 synergids
- 1 egg cell
- 1 central cell (2 polar nuclei → fuse → 1 nucleus)
Step 2: Total 8 cells, 7 nuclei.
Hence, 7 nucleated, 8 celled. Quick Tip: - Embryosac: – 8 cells – 7 nuclei (central cell: 2n → 1 nucleus)
One of the 2000 years old viable seed, discovered during the archeological excavation at King Herod’s near dead sea.
View Solution
Step 1: Date palm (Phoenix dactylifera) seed → ~2000 years old.
Step 2: Excavated at Masada, Israel → germinated in 2005.
Step 3: Named "Methuselah".
Hence, Phoenix dactylifera. Quick Tip: - Oldest viable seed: Date palm (2000 yrs) - Lupin: Arctic (10,000 yrs, unconfirmed)
The testis are situated outside the abdominal cavity in scrotum as it helps to
View Solution
Step 1: Spermatogenesis requires 2–3°C below body temperature (35°C).
Step 2: Scrotum → thermoregulation via pampiniform plexus, cremaster muscle.
Step 3: Hormone, storage, release → not primary reason.
Hence, low temperature. Quick Tip: - Scrotum: 35°C for sperm - Cryptorchidism: Undescended → infertility
Identify the odd one from the following:
View Solution
Step 1: Infundibulum, Fimbriae, Isthmus → parts of fallopian tube.
Step 2: Labia minora → external genitalia (vulva).
Hence, labia minora is odd. Quick Tip: - Fallopian tube: – Fimbriae → Infundibulum → Ampulla → Isthmus
In which month of gestation, the first movement of foetus and appearance of hair on its head is observed?
View Solution
Step 1: Quickening → first fetal movement → 18–20 weeks (~5th month).
Step 2: Lanugo (fine hair) → appears on head → 5th month.
Step 3: 4th month → limbs form; 8th → fat deposition.
Hence, 5th month. Quick Tip: - 5th month: Quickening + Lanugo - 7–8th month: Lanugo sheds
The most abundant type of WBC cells
View Solution
Step 1: WBC differential:
- Neutrophils: 50–70%
- Lymphocytes: 20–40%
- Monocytes: 2–8%
- Eosinophils: 1–4%
- Basophils: 0.5–1%
Step 2: Neutrophils → first responders.
Hence, most abundant. Quick Tip: - WBC order: Neutrophils > Lymphocytes > Monocytes > Eosinophils > Basophils ("Never Let Monkeys Eat Bananas")
Filtration of blood during urine formation takes place in
View Solution
Step 1: Ultrafiltration → glomerulus (Bowman’s capsule).
Step 2: High pressure → plasma filters → filtrate.
Step 3:
- PCT/DCT → reabsorption
- Collecting duct → concentration
Hence, glomerulus. Quick Tip: - Glomerulus: Filtration - PCT: 65% reabsorption - Loop of Henle: Concentration
Corpus Callosum connects the
View Solution
Step 1: Corpus callosum → white matter bundle.
Step 2: Connects left and right cerebral hemispheres.
Step 3: Allows interhemispheric communication.
Hence, two cerebral hemispheres. Quick Tip: - Corpus callosum: Left ↔ Right cerebrum - Split-brain: Severed → no communication
Menstrual cycle is exhibited by:
View Solution
Step 1: Menstrual cycle → uterine bleeding if no pregnancy.
Step 2: Seen in higher primates: humans, apes, Old World monkeys.
Step 3: Others → estrous cycle (no bleeding).
Hence, apes.
An example of dioecious plant:
View Solution
Step 1: Dioecious → male and female flowers on separate plants.
Step 2: Papaya → male, female, hermaphrodite plants.
Step 3: Others → monoecious or bisexual.
Hence, papaya. Quick Tip: - Dioecious: Papaya, Date palm - Monoecious: Cucurbita, Coconut
Stalk of the Stamen is:
View Solution
Step 1: Stamen = anther + filament.
Step 2: Filament → stalk supporting anther.
Step 3:
- Petiole: Leaf stalk
- Peduncle: Inflorescence stalk
- Pedicel: Flower stalk
Hence, filament. Quick Tip: - Stamen: Filament (stalk) + Anther - Pollen sac → inside anther






Comments