NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.2

Education Journalist | Study Abroad Strategy Lead

NCERT Solutions for Class 10 Maths Chapter 2 Polynomials Exercise 2.2 covers different cases of the relationship between Zeroes and Coefficients of a Polynomial. The exercise has 2 questions with 6 cases each.

Download PDF: NCERT Solutions for Class 10 Maths Chapter 2 Exercise 2.2

Check out the solutions of Class 10 Maths NCERT solutions chapter 2 Polynomials Exercise 2.2

Check out other exercise solutions of Class 10 Maths Chapter 2 Polynomials

Class 10 Chapter 2 Polynomials Topics:

Degree of Polynomial	Zeroes of a Polynomial	Polynomials Formula
Vietas Formula	Roots of Polynomials	Cubic Polynomial
Polynomials Revision Notes	Polynomials Important Questions	Parabola Graph

CBSE Class 10 Maths Study Guides:

Math Study Notes	Difference between in Maths	Math MCQs
Calculus	Math Formula	Mensuration
NCERT Solutions for Class 10 Maths	Arithmetic	Trigonometry

CBSE X Related Questions

1.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
View Solution
2.
The line segment joining the points \(P(-4, -2)\) and \(Q(10, 4)\) is divided by y-axis in the ratio
- \(2:5\)
- \(1:2\)
- \(2:1\)
- \(5:2\)
View Solution
3.
Through the mid-point Q of side CD of a parallelogram ABCD, the line AR is drawn which intersects BD at P and produced BC at R. Prove that \(AQ = QR\).
View Solution
4.
In the given figure, \(TP\) and \(TQ\) are tangents to a circle with centre \(M\), touching another circle with centre \(N\) at \(A\) and \(B\) respectively. It is given that \(MQ = 13 \text{ cm}\), \(NB = 8 \text{ cm}\), \(BQ = 35 \text{ cm}\) and \(TP = 80 \text{ cm}\).
(i) Name the quadrilateral MQBN. (1)
(ii) Is MN parallel to PA? Justify your answer. (1)
(iii) Find length TB. (1)
(iv) Find length MN. (2)
View Solution
5.
Which of the following sequence is \(\textit{not }\)an A.P. ?
- \( 2, \frac{5}{2}, 3, \frac{7}{2}, \dots \)
- \( -1.2, -3.2, -5.2, -7.2, \dots \)
- \( \sqrt{2}, \sqrt{8}, \sqrt{18}, \dots \)
- \( 1^2, 3^2, 5^2, 7^2, \dots \)
View Solution
6.
In the adjoining figure, the slant height of the conical part is :
- 4 cm
- 7 cm
- 5 cm
- 25 cm
View Solution