NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

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NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Exercise 12.2 Solutions are based on the Perimeter And Area Of A Circle.

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Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

Also check other Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.1 Solutions

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.3 Solutions

Also Check:

Chapter Related Topics
Circumference of Circle	Areas Related to Circles Formula	Areas Related to Circles Revision Notes
Area of Sector	Sector Of A Circle	Area of Segment of a Circle
Circle Formula	Area of a Circle Formula	Arc Length Formula
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Also Check:

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Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).
View Solution
2.
Using prime factorisation, find the HCF of 144, 180 and 192.
View Solution
3.
Find length and breadth of a rectangular park whose perimeter is \(100 \, \text{m}\) and area is \(600 \, \text{m}^2\).
View Solution
4.
Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?
View Solution
5.
The sum of a number and its reciprocal is \(\frac{13}{6}\). Find the number.
View Solution
6.
In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]
View Solution

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NCERT Solutions For Class 10 mathematics Chapter 12: Areas Related to Circles

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.3

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.
Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).

2.
Using prime factorisation, find the HCF of 144, 180 and 192.

3.
Find length and breadth of a rectangular park whose perimeter is \(100 \, \text{m}\) and area is \(600 \, \text{m}^2\).

4.
Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?

5.
The sum of a number and its reciprocal is \(\frac{13}{6}\). Find the number.

6.
In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]

Similar Mathematics Concepts

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).

2.Using prime factorisation, find the HCF of 144, 180 and 192.

3.Find length and breadth of a rectangular park whose perimeter is \(100 \, \text{m}\) and area is \(600 \, \text{m}^2\).

4.Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?

5.The sum of a number and its reciprocal is \(\frac{13}{6}\). Find the number.

6.In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).

2.
Using prime factorisation, find the HCF of 144, 180 and 192.

3.
Find length and breadth of a rectangular park whose perimeter is \(100 \, \text{m}\) and area is \(600 \, \text{m}^2\).

4.
Find the sum of first 20 terms of an A.P. whose n\(^{th}\) term is given by \(a_n = 5 + 2n\). Can 52 be a term of this A.P. ?

5.
The sum of a number and its reciprocal is \(\frac{13}{6}\). Find the number.

6.
In a trapezium \(ABCD\), \(AB \parallel DC\) and its diagonals intersect at \(O\). Prove that \[ \frac{OA}{OC} = \frac{OB}{OD} \]