Area and Perimeter: Definition, Formulas & Examples

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Area and Perimeter is a branch of geometry that deals with the calculation of the length, height and volume of a particular geometric shape. These formulas can be used for any object, whether it is regular object or irregular object.

  • Both area and perimeter are two-dimensional in nature.
  • Each geometrical shape has a unique area and perimeter. 
  • Area is the measurement of a surface that is covered by a closed figure.
  • The SI unit of area is square meter.
  • Perimeter is the length of the boundary of a closed figure. 
  • The SI unit of perimeter is meter.
  • Formulas can be used to find the area and perimeter of various geometrical figure. 
  • These formulas are used in everyday life such as measuring the area of a swimming pool.

Read More: Difference between Area and Volume

Key Terms: Area, Perimeter, Volume, Radius, Rectangle, Triangle, Circle, Square, Rhombus, Parallelogram, Trapezoid


Area

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Area is defined as a two-dimensional space occupied by any object. The formula depends upon the dimensions and properties of a figure. Let's assume that you are asked to paint a door of your house. 

  • Now, you need to know the area of the door first to determine the amount of paint required to paint that door. 
  • Different shapes occupy different areas. 
  • The area occupied by a triangle is different to the area occupied by a circle. 
  • If two objects have the same shape, then their area will be equal if their dimensions are equal.
  • The area of these objects is calculated in square units (sq units). 

Area

Area

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Area of Various Shapes

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The formulas of area for different objects with different shapes are as follows:

Shapes Area Formulas Variables
Triangle ½×b×h b = base h = height
Rectangle l×w l = length w = width
Square a = sides of the square
Semicircle ½πr² π = 22/7 or 3.1416 r = radius of the circle
Circle πr² π = 22/7 or 3.1416 r = radius of the circle
Trapezoid ½(a+b) h a = base 1 b = base 2 h = vertical height
Rhombus a×h a = side of the rhombus h = height
Parallelogram b×h b = base h = height

Read More: Section Formula


Perimeter

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Perimeter is the length of the boundary covered by any object. The length of a book is its perimeter. Now, depending upon the shape and length of the objects, perimeter changes.

  • We have to know certain measurements of an object to calculate its perimeter.
  • Depending upon its shape, the measurements change. 
  • For any curved shape, perimeter is known as circumference.
  • Perimeter value of a circular wheel calculate the distance covered in one revolution.
  • Some real-life example of perimeter includes length of a lawn and size of a photo-frame.

Perimeter 

Read More: Frequency Polygons


Perimeter of Various Shapes

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The formulas of perimeter for different objects with different shapes are tabulated below.

Shapes Perimeter Formula Variables
Triangle Sum of the length of all sides (a+b+c)  a, b, c are the length of the sides. 
Rectangle 2 (l+w)  l = length w = width
Square 4a a = length of a side
Semicircle πr+2r r = radius of the circle
Circle 2πr r = radius of the circle
Trapezoid Sum of all sides (a+b+c+d)  a, b, c, d being the lengths of the sides of the trapezoid. 
Rhombus 4a  a = side of the rhombus
Parallelogram 2(a+b)  a = side of the parallelogram b = base of the parallelogram

Read More: Lines and Angles 


Things to Remember

  • Area and Perimeter are two important concept used in the branch of mensuration.
  • Area is measurement of amount of space occupied by any object.
  • It is used to determine the space in the floor of a room.
  • Perimeter is the measurement of the boundary within a shape enclosed.
  • It can be calculated by tying a thread or string around the required object.

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Sample Questions

Ques: Find the perimeter of a square with the length of its one side 7 cm. (2 Marks)

Ans: Given, Length of the side, a = 7 cm

We know that, Perimeter of a square = 4a

Here, The perimeter of the square will be, 

= 4a

= 4×7 cm

= 28 cm

Ques: Find the area of a square with the length of its one side 7 cm. (2 Marks)

Ans: Given, Length of the side, a = 7 cm

We know that, Area of a square = a²

Here, The area of the square will be, 

= a²

= (7 cm)²

= 49 cm²

Ques: What will be the length of the sides of a square if the area of the square is 81 cm². (2 Marks)

Ans: Given, Area of the square = 81 cm²

We know that, Area of a square = a²

→ 81 cm² = a²

→ a = √81 cm²

→ a = 9 cm

Here, the length of the sides of the square is 9 cm. 

Ques: The radius of a circle is 14 cm. Find the perimeter of the circle. (Take π=22/7)  (2 Marks)

Ans: Given, Radius of the circle, r = 14 cm

We know that, Perimeter of a circle = 2πr

Here, The perimeter of the circle will be, 

= 2πr

= 2 × 22/7 × 14 cm

= 2 × 22 × 2 cm

= 88 cm

Ques: The radius of a circle is 14 cm. Find the area of the circle. (Take π=22/7) (3 Marks)

Ans: Given, Radius of the circle, r = 14 cm

We know that, Area of a circle = πr²

Here, The area of the circle will be, 

= πr²

= 22/7 × (14 cm)²

= 22/7 × 196 cm²

= 22 × 28 cm²

= 616 cm²

Ques: Find the area of a rectangle with length of 8 cm and width of 4 cm. (3 Marks)

Ans: Given, 

Length = 8 cm

Width = 4 cm

We know that, Area of a rectangle = l×w

Here, The area of the rectangle will be, 

= l×w

= (8 cm × 4 cm) 

= 32 cm²

= 32 cm²

Ques: What will be the perimeter of a triangle with the side lengths of 3 cm, 6 cm and 9 cm.  (3 Marks)

Ans: Given, 

a = 3 cm

b = 6 cm 

c = 9 cm

We know that, The perimeter of a triangle = a + b + c

Now, The perimeter of the given triangle will be, 

= a + b + c

= (3 + 6 + 9) cm

= 18 cm

Ques: What will be the area of a triangle with the base length of 6 cm and height of 8 cm. (3 Marks)

Ans: Given, 

b = 6 cm

h = 8 cm

We know that, The area of a triangle = ½ (b×h) 

Now, The area of the given triangle will be, 

= ½ (b×h) 

= ½ (6×8) cm²

= ½ × 48 cm²

= 24 cm²

Ques: What will be the length of a rectangle if the perimeter and width of the rectangle is 48 cm and 8 cm respectively. (3 Marks)

Ans: Given, 

Perimeter of the rectangle = 48 cm

Width of the rectangle (w) = 8 cm

We know that, Perimeter of a rectangle = 2 (l+w) 

=> 48 = 2(l+8) 

=> l+8 = 24

=> l = 24-8

=> l = 16 cm

So, the length of the rectangle is 16 cm. 

Ques: Find the perimeter of a rectangle with length of 8 cm and width of 4 cm. (3 Marks)

Ans: Given, 

Length = 8 cm

Width = 4 cm

We know that, Perimeter of a rectangle = 2 (l+w) 

Here, The perimeter of the rectangle will be, 

= 2(l+w) 

= 2(8 cm + 4 cm) 

= 2×12 cm

= 24 cm

Ques: What is the difference between area and perimeter of any geometric shape. (3 Marks)

Ans: The difference between the area an perimeter of any geometric shape is as follows:

Area Perimeter
Area is used to calculate the space occupied within the surface of a shape. Perimeter is defined in the calculation of space ariund the boundary of an object.
It is expressed in terms of square units. It is expressed in terms of unit.
The area of a rectangle is length x breadth. The perimeter of a rectangle is 2 (length + breadth).

Ques: A rectangular field has length 13 m and breadth 11 m. What will be the area as well as the perimeter of that field. (2 Marks)

Ans: Length of the rectangular field = 13 m

Breadth of the rectangular field = 11 m

Therefore, area of the field = l×b =13 × 11

=143 m2

And perimeter = 2(l+b) = 2(13+11)

=48m

Ques: If a rhombus has base and height 17 cm and 18 cm respectively, calculate its area. (2 Marks)

Ans: With regards to the question base = 17 cm

  • Height = 8 cm
  • Therefore, the area of rhombus =
  • b×h
  • 17 x 18
  • 306 cm2

Ques: If the length of the side of a square is 15 cm. Then find its area and also find the total length of its boundary. (2 Marks)

Ans:  Given, length of the side, a = 15 cm

Area = a= 15= 225 sq.cm

Total length of its boundary,

Perimeter = 4a = 4 x 15 = 60 sq.cm.

Ques: The length of a rectangular carpet is 22 units. Its area is 484 square units. Find the width of the carpet and the perimeter of the carpet. (2 Marks)

Ans: Area of a rectangle = (length × width) square units.

  • Given, length of the rectangular carpet = 22 units
  • Area = 484 square units
  • 22 × width = 484
  • width = 484/22.
  • Thus, the width of the rectangular carpet= 22 units.

Now,

  • Perimeter of a rectangle = 2(length + width) units.
  • Given: length of the rectangular carpet = 22 units
  • Width of the rectangular carpet = 22 units.
  • Substituting the values of length and width in the formula.
  • Perimeter = 2 (22 + 22) = 2 (44) = 88 units.
  • Therefore, the perimeter of the rectangular carpet = 88 units.

Ques: A circular-shaped garden has a radius of 30 units has to be fenced. Find the cost of fencing the circular garden if it takes $10 to fence one unit. (Use the value of π as 22/7) (3 Marks)

Ans: To calculate the cost of fencing the garden, we first have to find the outer boundary length of the garden.

  • To find that let us find the perimeter of the circular garden with a radius of 50 units.
  • For a circle, the circumference = 2πr units.
  • Given: radius = 30 units.
  • Therefore, circumference = 2 × (22/7) × 30 = 188.571 units.
  • The cost of fencing 1 unit of the garden = $10.
  • Therefore, the cost of fencing 188.571 units of the garden = 188.571 × 10 = $1885.71

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CBSE X Related Questions

  • 1.

    In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.


      • 2.

        Find the mean and mode of the following data:

        Class15--2020--2525--3030--3535--4040--45
        Frequency1210151175


          • 3.
            The system of equations $2x + 1 = 0$ and $3y - 5 = 0$ has

              • unique solution
              • two solutions
              • no solution
              • infinite number of solutions

            • 4.
              Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]


                • 5.
                  The given figure shows a circle with centre O and radius 4 cm circumscribed by \(\triangle ABC\). BC touches the circle at D such that BD = 6 cm, DC = 10 cm. Find the length of AE.
                   BC touches the circle at D such that BD = 6 cm


                    • 6.

                      Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is

                        • 8 cm
                        • \(4\sqrt{5}\) cm
                        • \(2\sqrt{5}\) cm
                        • 12 cm

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