NCERT Solutions for Class 7 Mathematics Chapter 14: Symmetry

NCERT Solutions for class 7 Mathematics Chapter 14 Symmetry are provided in the article below. If two or more parts of a figure are identical after folding or flipping then it is said to be symmetry. To be symmetrical the two halves of a shape must be of same shape and size. If the shape is not symmetrical then it is said to be asymmetrical. Some of the important topics in Symmetry chapter include:

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NCERT Solutions for Class 7 Mathematics Chapter 14

NCERT Solutions for Class 7 Mathematics Chapter 14 Symmetry is given below.

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NCERT Solutions for Class 7 Mathematics

Symmetry: A figure is said to be symmetrical if one half of the figure is a mirror image of the other.

Depending on the lines of symmetry, symmetrical figures can be classified into:

  • No Line of Symmetry (for the asymmetrical figure)
  • One Line of Symmetry 
  • Two Line of Symmetry 
  • Multiple (more than 2) Line of Symmetry
  • Infinite Line of Symmetry

NCERT Solutions for Class 7 Maths Chapter 14 Exercises

NCERT Solutions for Class 7 Maths Chapter 14 Symmetry Exercises is given below.

Read More:

Class 7 Maths Guide:

CBSE X Related Questions

  • 1.
    The HCF of 960 and 432 is :

      • 48
      • 54
      • 72
      • 36

    • 2.
      Two water taps together can fill a tank in $8\frac{8}{9}$ hours. The tap of larger diameter takes 4 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.


        • 3.
          The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :

            • 0
            • 1
            • 3
            • 2

          • 4.
            Prove that :
            \(\frac{\tan \theta}{1 - \cot \theta} + \frac{\cot \theta}{1 - \tan \theta} = 1 + \tan \theta + \cot \theta\).


              • 5.
                \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

                  • \(\frac{21}{4} \text{ cm}\)
                  • \(\frac{28}{3} \text{ cm}\)
                  • \(\frac{12}{7} \text{ cm}\)
                  • \(5.5 \text{ cm}\)

                • 6.
                  If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).

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