NCERT Solutions For Class 7 Science Chapter 15 : Visualizing Solid Shapes

NCERT Solutions for class 7 Mathematics Chapter 15 Visualizing Solid Shapes are provided in the article below. Plane shapes have two measurements like length and breadth which are called dimensions of a plane and therefore they are called two-dimensional shapes whereas a solid object has three measurements like length, breadth, height or depth. Hence, they are called three-dimensional shapes or 3-D shapes. Some of the important topics in this chapter include:

Download: NCERT Solutions for Class 7 Mathematics Chapter 15 pdf

NCERT Solutions for Class 7 Mathematics Chapter 15

NCERT Solutions for Class 7 Mathematics Chapter 15 Visualizing Solid Shapes are given below.

NCERT Solution class 7 mathematics chapter 15

Class 7 Maths Chapter 15 Visualising Solid Shapes – Important Topics

Three dimensional figure: Three-dimensional figures are those which consist of length, breadth and height.

Some of the important three dimensional figures include:

Cube
Cuboid
Cone
Cylinder
Pyramid

Volume of Cube – a³

Volume of Cuboid – length x breadth x height

Volume of Cone – 1/3 \(\pi\)r²h

Volume of Cylinder – \(\pi\)r²h

NCERT Solutions for Class 7 Maths Chapter 15 Exercises

NCERT Solutions for Class 7 Maths Chapter 15 Visualising Solid Shapes Exercises are given below.

Read More:

Visualising Solid Shapes MCQ	Measurement of Objects	Isomeric Sketch
Rectangular Pyramid	3D Shapes	Hexagon Formula

Read More:

NCERT Solutions for Class 7 Maths	Number System	Geometry
Arithmetics	Basic Maths	Maths Formulas

CBSE X Related Questions

1.
\(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals
- \(\frac{21}{4} \text{ cm}\)
- \(\frac{28}{3} \text{ cm}\)
- \(\frac{12}{7} \text{ cm}\)
- \(5.5 \text{ cm}\)
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2.
The natural number 1 is :
- a prime number.
- a composite number.
- prime as well as composite.
- neither prime nor composite.
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3.
If the pair of linear equations : \( a_1x + b_1y + c_1 = 0 \) and \( a_2x + b_2y + c_2 = 0 \) is consistent and dependent, then
- \( \frac{a_1}{a_2} \neq \frac{b_1}{b_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2} \)
- \( \frac{a_1}{a_2} = \frac{b_1}{b_2} = \frac{c_1}{c_2} \)
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4.
The graph of \(y = f(x)\) is given. The number of zeroes of \(f(x)\) is :
- 0
- 1
- 3
- 2
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5.
In the figure given above, \(\triangle ABC \sim \triangle XYZ\), then find the values of \(x\) and \(y\).
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6.
The HCF of 960 and 432 is :
- 48
- 54
- 72
- 36
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