NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

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NCERT Solutions for Class 7 Mathematics Chapter 10 Practical Geometry are provided in the article below. Practical geometry is an important branch of geometry which deals with the study of the size, positions, shapes as well as dimensions of objects. Whether you have to draw a line segment or measure it, draw a circle or arcs, draw an angle, etc. it can easily be possible with the help of geometrical tools. Some of the important topics in Practical Geometry chapter are:

Download: NCERT Solutions for Class 7 Mathematics Chapter 10 pdf

NCERT Solutions for Class 7 Mathematics Chapter 10

NCERT Solutions for Class 7 Mathematics Chapter 10 Practical Geometry is given below.

Class 7 Maths Chapter 10 Practical Geometry – Important Topics

Practical Geometry: It is the practical study of constructing geometrical figures.

Perpendicular Bisector: It is the line that is constructed by the use of angles to bisect a line segment into two equal halves.

Angle Bisector: It is a line that is constructed to bisect an angle into two equal halves.

Example: Make a line AB and place a point P on the outside of it. Draw a line CD that runs parallel to AB and passes through point P.

Ans.

Draw an AB line.
Join PQ with a point Q on AB and a point P outside AB.
Draw on the arc to cut AB at X and PQ at Z with Q as the centre and any radius.
Draw an arc cutting QP at Y with P as the centre and the same radius.
Draw an arc to cut the preceding arc at E, with Y as the centre and the radius equal to XZ.
To get the desired line, join PE and produce it on both sides.

NCERT Solutions for Class 7 Maths Chapter 10 Exercises

NCERT Solutions for Class 7 Maths Chapter 10 Practical Geometry Exercises are given below.

Read More:

Construction of Rhombus	Perpendicular Lines	ASA Triangles Construction
SAS Triangles Construction	RHS Triangles Construction	Perimeter two angles constructing triangles

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NCERT Solutions for Class 7 Maths	Number System	Geometry
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CBSE X Related Questions

1.
Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is
- 8 cm
- $4\sqrt{5}$ cm
- $2\sqrt{5}$ cm
- 12 cm
View Solution
2.
The system of equations $2x + 1 = 0$ and $3y - 5 = 0$ has
- unique solution
- two solutions
- no solution
- infinite number of solutions
View Solution
3.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.
View Solution
4.
Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]
View Solution
5.
Given that $\sin \theta + \cos \theta = x$, prove that $\sin^4 \theta + \cos^4 \theta = \dfrac{2 - (x^2 - 1)^2}{2}$.
View Solution
6.
The number of red balls in a bag is three more than the number of black balls. If the probability of drawing a red ball at random from the given bag is $\dfrac{12}{23}$, find the total number of balls in the given bag.
View Solution

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NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

Download: NCERT Solutions for Class 7 Mathematics Chapter 10 pdf

NCERT Solutions for Class 7 Mathematics Chapter 10

Class 7 Maths Chapter 10 Practical Geometry – Important Topics

NCERT Solutions for Class 7 Maths Chapter 10 Exercises

CBSE X Related Questions

1.
Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is

2.
The system of equations $2x + 1 = 0$ and $3y - 5 = 0$ has

3.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

4.
Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]

5.
Given that $\sin \theta + \cos \theta = x$, prove that $\sin^4 \theta + \cos^4 \theta = \dfrac{2 - (x^2 - 1)^2}{2}$.

6.
The number of red balls in a bag is three more than the number of black balls. If the probability of drawing a red ball at random from the given bag is $\dfrac{12}{23}$, find the total number of balls in the given bag.

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NCERT Solutions for Class 7 Mathematics Chapter 10: Practical Geometry

Download: NCERT Solutions for Class 7 Mathematics Chapter 10 pdf

NCERT Solutions for Class 7 Mathematics Chapter 10

Class 7 Maths Chapter 10 Practical Geometry – Important Topics

NCERT Solutions for Class 7 Maths Chapter 10 Exercises

CBSE X Related Questions

1.Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is

2.The system of equations $2x + 1 = 0$ and $3y - 5 = 0$ has

3.In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

4.Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]

5.Given that $\sin \theta + \cos \theta = x$, prove that $\sin^4 \theta + \cos^4 \theta = \dfrac{2 - (x^2 - 1)^2}{2}$.

6.The number of red balls in a bag is three more than the number of black balls. If the probability of drawing a red ball at random from the given bag is $\dfrac{12}{23}$, find the total number of balls in the given bag.

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Two identical cones are joined as shown in the figure. If radius of base is 4 cm and slant height of the cone is 6 cm, then height of the solid is

2.
The system of equations $2x + 1 = 0$ and $3y - 5 = 0$ has

3.
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.

4.
Prove that: \[ \frac{\cos \theta - 2 \cos^3 \theta}{\sin \theta - 2 \sin^3 \theta} + \cot \theta = 0 \]

5.
Given that $\sin \theta + \cos \theta = x$, prove that $\sin^4 \theta + \cos^4 \theta = \dfrac{2 - (x^2 - 1)^2}{2}$.

6.
The number of red balls in a bag is three more than the number of black balls. If the probability of drawing a red ball at random from the given bag is $\dfrac{12}{23}$, find the total number of balls in the given bag.