NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

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NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Exercise 12.1 Solutions are based on Perimeter And Area Of A Circle.

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Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

Also check other Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.2 Solutions

NCERT Solutions For Class 10 Maths Chapter 12 Exercise 12.3 Solutions

Also Check:

Chapter Related Topics
Circumference of Circle	Areas Related to Circles Formula	Areas Related to Circles Revision Notes
Area of Sector	Sector Of A Circle	Area of Segment of a Circle
Circle Formula	Area of a Circle Formula	Arc Length Formula
Mathematics diameter formula	Central Angle of a Circle Formula	Radius of a Circle

Also Check:

Math Study Guides
Maths Important Formulas	Maths MCQs	Comparison Articles in Maths
Difference Between Topics in Maths	Math Study Material	Arithmetic
Class 10 Maths Notes	Permutations and Combinations	Mensuration
Trigonometry	Number Systems	Geometry
Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?
- 144
- 2
- 420
- 272
View Solution
2.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is
- 34
- 43
- 38.5
- 41.5
View Solution
3.
If for a data, median is 5 and mode is 4, then mean is equal to :
- 7
- 11
- $\frac{11}{2}$
- $\frac{14}{3}$
View Solution
4.
If the zeroes of the polynomial $p(x) = 2x^2 - 7x + 6$ are $\alpha$ and $\beta$, then the value of $\frac{1}{\alpha} + \frac{1}{\beta}$ is
- $\frac{7}{2}$
- $\frac{6}{7}$
- $\frac{-7}{6}$
- $\frac{7}{6}$
View Solution
5.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is
- $55^\circ$
- $20^\circ$
- $35^\circ$
- $70^\circ$
View Solution
6.
If $PQ$ and $PR$ are tangents to the circle with centre $O$ and radius $4 \text{ cm}$ such that $\angle QPR = 90^{\circ}$, then the length $OP$ is
- $4 \text{ cm}$
- $4\sqrt{2} \text{ cm}$
- $8 \text{ cm}$
- $2\sqrt{2} \text{ cm}$
View Solution

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Areas Related to Circles Revision Notes

NCERT Solutions For Class 10 mathematics Chapter 12: Areas Related to Circles

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.2

NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.3

CBSE X Syllabus

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Circles: Definition, Properties, Parts, Theorems

Constructions Revision Notes

Pair of Linear Equations In Two Variables Important Questions

Circles Revision Notes: Theorems of Tangent to the Circle

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Euclid's Division Lemma: Proof, Finding HCF & Examples

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Real Numbers: Definition, Properties and Examples

Events in Probability: Definition, Types, Examples

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NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

3.
If for a data, median is 5 and mode is 4, then mean is equal to :

4.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

5.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Similar Mathematics Concepts

Comments

dOGVmW

NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.1

Exercise Solutions of Class 10 Maths Chapter 12 Areas Related to Circles

CBSE X Related Questions

1.There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

3.If for a data, median is 5 and mode is 4, then mean is equal to :

4.If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

5.In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

6.If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

Similar Mathematics Concepts

Comments

dOGVmW

1.
There are two sections A and B of Grade X. There are 28 students in Section A and 30 students in Section B. What is the minimum number of books you will acquire for the class library so that they can be distributed equally among students of Section A or Section B ?

2.
Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

3.
If for a data, median is 5 and mode is 4, then mean is equal to :

4.
If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

5.
In the given figure, $PQ$ is tangent to the circle with centre $O$. $S$ is a point on the circle such that $\angle SQT = 55^\circ$. The $m\angle QPS$ is

6.
If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is