NCERT Solutions for Class 10 Maths Chapter 12 Exercise 12.3

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NCERT Solutions for Class 10 Maths Chapter 12 Areas Related to Circles Exercise 12.3 Solutions are based on calculation of areas of some combinations of plane figures which are available in daily life (window designs, bedsheets designs, carpet designs, etc. through some examples.

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CBSE X Related Questions

  • 1.
    Mean and Median of a frequency distribution are 43 and 40 respectively. The value of mode is

      • 34
      • 43
      • 38.5
      • 41.5

    • 2.
      The value of k for which sum of the zeroes of the polynomial \(p(x) = 3x^2 - kx + 6\) is 2, is

        • 2
        • \(-6\)
        • \(-2\)
        • 6

      • 3.
        If \(PQ\) and \(PR\) are tangents to the circle with centre \(O\) and radius \(4 \text{ cm}\) such that \(\angle QPR = 90^{\circ}\), then the length \(OP\) is

          • \(4 \text{ cm}\)
          • \(4\sqrt{2} \text{ cm}\)
          • \(8 \text{ cm}\)
          • \(2\sqrt{2} \text{ cm}\)

        • 4.
          It is given that \(\triangle ABC \sim \triangle EDF\). Which of the following is not true?

            • \(\frac{\text{Perimeter of } \triangle ABC}{\text{Perimeter of } \triangle EDF} = \frac{AB}{ED}\)
            • \(\frac{AB}{ED} = \frac{AC}{EF}\)
            • \(\angle A = \angle D, \angle C = \angle F\)
            • \(\frac{AB + BC}{AC} = \frac{ED + DF}{EF}\)

          • 5.
            Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
            Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

              • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
              • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
              • Assertion (A) is true, but Reason (R) is false.
              • Assertion (A) is false, but Reason (R) is true.

            • 6.
              If the zeroes of the polynomial \(p(x) = 2x^2 - 7x + 6\) are \(\alpha\) and \(\beta\), then the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\) is

                • \(\frac{7}{2}\)
                • \(\frac{6}{7}\)
                • \(\frac{-7}{6}\)
                • \(\frac{7}{6}\)

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