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Mechanical properties of solids define the various characteristics of solids such as their resistance to deformation and their strength.
- Resistance to deformation is the resistance that is offered by an object to change its shape.
- Whereas strength elaborates on the ability of an object to resist the applied stress.
- When a solid is deformed, the atoms or molecules are displaced from their equilibrium position.
- This causes a change in interatomic distance.
- When the deforming force is removed, the intermolecular forces tend to drive them back to their original position.
- Thus the body regains its original shape and size.
Table of Content |
Key Terms: Stress, Strain, Interatomic force, Strength, Elasticity, Plasticity, Ductility, Stress-strain curve, Hooke’s law, Young’s modulus of elasticity, Poisson's ratio, Elastic after effect, Elastic fatigue
Mechanical Properties of Solids
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Mechanical properties of solids focus on qualities such as deformation resistance and strength.
- Strength is the capacity of an object to endure applied stress, or how far it can withstand the force.
- The resistance to deformation of an object is its resistance to changing shape.
- If the object's resistance to deformation is low, it can quickly change shape and vice versa.
The following are the mechanical properties of solids
Elasticity
Elasticity is defined as the property of an object by which the object regains its original shape and size after the removal of the applied force.
For example: If we stretch the rubber band to some extent and leave it then it will regain its original shape.
Perfectly Elastic Body
A Perfectly Elastic Body is defined as a body that recovers its original shape and size completely and immediately after the deforming force is removed.
For example: Phosphor bronze and Quartz fiber.
Plasticity
Plasticity is the property of an object in which the object changes its shape when deforming force is applied and never comes back to its original shape after the deforming force is removed.
It is the property of permanent deformation.
For example: All plastic objects.
Ductility
Ductility is the property of an object in which it can be pulled in thin wires, plates, or sheets.
For example: Gold and Silver
Strength
The ability to hold out against applied stress without any failure is known as strength. Compared to others, many objects have higher or more strength.
Resistance to Deformation
Solid materials have a definite size and shape.
- An external force is required to change the size and shape of the solid object.
- The shape of an object can be easily changed if the resistance to deformation is less.
- Mechanical properties are those properties of solids that define their solidity.
- These properties include plasticity, elasticity, strength, and ductility.
Stress
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Under the action of an external force, if a body gets deformed then an internal force is framed at each and every section of the body that tends to restore the body to its original state.
- This internal force is known as Stress.
- In simple words, stress is the internal restoring force per unit area.
- The magnitude of both internal and external forces is equal.
- The dimensional formula of stress is [ML-1T-2].
- Its SI unit is N/m² or Pascal.
If A is the cross-section area of the body and the force applied is F, then the stress will be
Stress = F/A
Types of Stress
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Stress is divided into three types
- Longitudinal Stress
- Shearing or Tangential Stress
- Bulk or Hydraulic Stress
Longitudinal Stress
When the deforming force of the cylindrical body is applied normally to the area of the cross-section, it is said to be Longitudinal Stress.
In longitudinal stress, a change takes place in the length of an object.
Longitudinal Stress is divided into two types
- Tensile Stress
- Compressional stress
Tensile stress
Under the applied force effect, if there is an increase in the length of an object, then it is termed Tensile stress.
Compressional stress
Under the applied force effect, if there is a decrease in the length of an object, then it is termed Compressional stress.
Shearing or Tangential Stress
Tangential stress is the restoring force per unit area when the force applied is parallel to the cross-sectional area of the body. The deforming force produces changes in the shape of the body when it is applied tangentially.
Bulk or Hydraulic Stress
Hydraulic stress is the restoring force applied per unit area on the body or object by a fluid like water.
Strain
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Strain is defined as a change in the size and shape of a body when a deforming force acts on the body. Simply, strain is the ratio of change in shape or size to the original shape or size. It is just a number and has no dimensions.
Types of Strain
There are three types of strain
- Shearing strain
- Longitudinal strain
- Volume strain
Shearing Strain
Shearing strain is the measurement of the relative displacement on the opposite faces of the body due to the shearing stress. It is represented by tanθ.
Longitudinal Strain
Due to the applied longitudinal stress, there is a change of length in the original length of the body.
Longitudinal strain = change in length /original length
Volume strain
Volume strain is a strain that is produced by hydraulic pressure. It is defined as the ratio of change in volume to the original volume.
Hooke's Law
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According to Hooke's Law, strain and stress are corresponding to each other within the elastic limit.
Thus,
Stress ∝ Strain
⇒ Stress/Strain = K
Here, K is the proportionality constant known as the modulus of elasticity.
- Hooke's law is said to be empirical law and is valid for most materials.
- Some materials like human muscle, rubber, etc do not obey Hooke's law.
Stress-Strain Curve
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A curve drawn between stress and strain is called the stress-strain curve.
- When stress and stress are drawn along the y-axis and x-axis respectively, a linear graph is formed in the ideal situation of Hooke’s law.
- However, when actual experiments are drawn, a curve is formed known as the stress-strain curve.
- To understand the tensile strength of a material, a stress-strain curve is very useful.
- This curve varies from material to material.
The stress-strain curve is shown in the below diagram.
- The curve OA is a straight line. It indicates that stress is proportional to strain.
- Hooke’s law is obeyed up to point A. Point A is the proportional limit.
- After point A, stress is not proportional to strain. AB curved portion is obtained.
- Once the load is removed, the body recovers its original dimension.
- Point B is the elastic limit or yield point.
- The corresponding stress to point B is said to be the yield strength.
- Beyond B, the curve shows plastic deformation.
- Here, the strain increases more quickly than stress.
- Point D on the curve indicates the tensile strength of a material.
- The length of the wire increases without any additional load in the region between B and D.
- This region is said to be the plastic region.
Elastic Moduli
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The modulus of elasticity or Elastic Moduli is the ratio of strain and stress. It is one of the basic characteristics of the material.
Elastic Moduli can be of three types
- Young’s modulus
- Shear modulus
- Bulk modulus.
Young's Modulus of Rigidity
Young's Modulus of Rigidity is defined as the ratio of longitudinal stress to the longitudinal strain within the elastic limit.
- The symbol of Young's Modulus is Y.
- In comparison to other materials, the Young Modulus of metals has high values.
Y= Normal Stress / Longitudinal Strain
Bulk Modulus of Rigidity
The ratio of normal stress to volumetric strain within the elastic limit is known as the Bulk Modulus of Rigidity. It is represented by B.
B = Normal Stress / Volumetric Strain
Bulk Moduli of Materials
Materials | Bulk moduli |
---|---|
Solids | |
Aluminum | 72 |
Brass | 61 |
Copper | 140 |
Glass | 37 |
Iron | 100 |
Nickel | 260 |
Steel | 160 |
Liquids | |
Water | 2.2 |
Ethanol | 0.9 |
Carbon disulfide | 1.56 |
Glycerine | 4.76 |
Mercury | 25 |
Gases | |
Air (at STP) | 1.0 × 10–4 |
Modulus of Rigidity or Shear Modulus
The ratio of shearing stress to shearing strain is known as the Modulus of Rigidity or Shear Modulus. It is represented by G.
G = Shearing Stress / Shearing Strain
Shear Moduli of a Few Common Materials
Material | Shear moduli |
---|---|
Aluminum | 25 |
Brass | 36 |
Copper | 42 |
Glass | 23 |
Iron | 70 |
Lead | 5.6 |
Nickel | 77 |
Steel | 84 |
Tungsten | 150 |
Wood | 10 |
Poisson's Ratio
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Poisson's Ratio is defined as the ratio of lateral or transverse strain to longitudinal or axial strain.
- It is the ratio of two strains.
- It has no dimension or unit.
- The theoretical range of Poisson's Ratio is between – 1 to 0.5
- Its practical range is between 0 to 0.5.
- It is represented by σ.
σ = Lateral strain / Longitudinal strain
Relation Between Young’s Modulus, Bulk Modulus, Shear Modulus, and Poisson’s Ratio
- Y = 3B (1-2σ)
- Y = 2G (1+σ)
- σ = 3D-2G2G+6B
- 9Y = 1B + 3G
Elastic Fatigue
Under the action of repeating alternate deforming force, the property of an elastic body in which its behavior becomes less elastic is known as Elastic Fatigue.
- It takes place when a body comes under repeated deforming forces or strains, even within the elastic limit.
- Under such circumstances, the body loses its elasticity property.
Things to Remember
- In a solid, atoms or molecules are bound together by interatomic or intermolecular forces.
- The force that produces a change in the normal positions of the molecules is known as the deforming force.
- The property due to which a body regains its original configuration is known as elasticity.
- The property due to which a body does not regain its original configuration is known as elasticity.
- The restoring force developed per unit area in a body is called stress.
- The strain is the relative change in the dimensions of a body resulting from external forces.
- According to Hooke’s law, stress is directly proportional to strain.
Sample Questions
Ques. Two different types of rubber are found to have the stress-strain curves as shown in the figure
(a)In what ways do these curves suffer from the stress- strain curve of a metal wire?
(b)Which of the two rubbers A and B would you prefer to be installed in the working of a heavy machinery
(c)Which of these two rubbers would you choose for a car tyre? (5 marks)
Ans. Stress-strain curve of two different type of rubbers:
1) For both the curves, Hooke’s law is not obeyed as the curves are not in a straight line. Hence such types of curves are called elastic hysteresis as the materials do not retrace curves during restoration.
2) For heavy machinery, rubber B is preferable because the area of loop B is more than that of A which shows more absorption power for vibrations. The absorption power for vibrations is useful in machinery.
3) Since hysteresis loop is a direct measure of heat dissipation. So, to minimize the heating in the car tyres rubber A is preferred over B.
Ques. Which is more elastic rubber or steel? Explain. (2 marks)
Ans. Steel, since a body is said to be more elastic based on how quickly it returns to its original shape once an external (deforming) force is removed. When a force is applied to steel, it gets deformed, yet it rapidly returns to its original shape within a fraction of a second, but rubber does not.
Ques. The stress-strain graphs for materials A and B are shown in figure.
The graphs are drawn to the same scale.
(a) Which of the materials has the greater Young’s modulus?
(b) Which of the two is the stronger material? (3 marks)
Ans.
(a) From the two graphs we note that for a given strain, stress for A is more than that of B. Hence Young’s modulus of material A is greater than that of material B.
(b) Strength of a material is determined by the amount of stress required to change its shape. This stress corresponds to the point of change in shape. The stress corresponding to the point of change in shape in A is more than for B. So, material A is stronger than material B.
Ques. Two wires of diameter 0.25 cm, one made of steel and other made of brass are loaded as shown in figure. The unloaded length of steel wire is 1.5 m and that of brass wire is 1.0 m.Young’s modulus of steel is 2.0 x 1011 Pa. Compute the elongations of steel and brass wires. (1 Pa = 1 N m2). (5 marks)
Ans.
Ques. Four identical hollow cylindrical columns of mild steel support a big structure of mass 50,000 kg. The inner and outer radii of each column are 30 cm and 60 cm respectively. Assuming the load distribution to be uniform, calculate the compressional strain of each column. Young’s modulus, Y = 2.0 x 1011 Pa. (5 marks)
Ans.
Ques. A piece of copper having a rectangular cross-section of 15.2 mm x 19.1 mm is pulled in tension with 44,500 N force, producing only elastic deformation. Calculate the resulting strain. The shear modulus of elasticity of copper is 42 x 109 N/m2. (3 marks)
Ans. Here,
Ques. Define Hooke’s law. (2 marks)
Ans. Hooke’s law states that the extension produced in the wire is directly proportional to the load applied within the elastic limit.
Acc to Hooke’s law,
Stress α Strain
Stress = K x Strain
K = Modulus of elasticity
Ques. Explain why the stretching of a coil spring is determined by its shear modulus. (2 marks)
Ans. When a coil spring is stretched, neither its length nor its volume changes, there is only the change in its shape. Therefore, the stretching of a coil spring is determined by shear modulus.
Ques. What is elastic fatigue? (1 mark)
Ques. Why are Railway tracks laid on large-sized Wooden sleepers? (2 marks)
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