Gravitation: Gravitational Force , Field, and Potential Energy

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Gravitation, also known as gravitational attraction, is the attraction of all masses in the universe to one another.

  • Sir Isaac Newton proposed that all particles in the universe attract each other.
  • The force of attraction between any two bodies of this universe is called Gravitation or Gravitational force.
  • Gravity is the force that pulls objects toward the center of a planet or other body.
  • The force of gravity keeps all of the planets in orbit around the sun.
  • Gravity exists in everything that has mass.
  • Gravity is stronger for heavier objects.
  • Gravity gets weaker with distance as well.
  • The stronger the gravitational force between two objects, the closer they are to each other.

Key Terms: Gravitational force, Gravitation, Gravity, Acceleration due gravity, Gravitational field, Gravitational potential energy, Weightlessness, Orbital velocity, Kepler’s law, Law of periods.


Gravitational Force

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Gravitational force, also known as the force of gravity is the force with which the objects with mass attract towards each other.

  • Any object having mass exerts a gravitational force on all other mass objects.
  • For example, there is a gravitational pull between you and all objects in your surroundings.
  • When the masses of two objects are larger, the gravitational force between them is larger.
  • The gravitational force between two objects is also affected by the separation between their centers.
  • The greater the distance between objects, the weaker the force.

Characteristics of Gravitational Force

The following are the characteristics of gravitational force

  • The gravitational force between two bodies forms an action and reaction pair.
  • Gravitational force is a central force i.e. it always acts along the line joining the centers of the two bodies.
  • It is independent of the nature of the intervening medium.
  • It is a long-range force.
  • It is a conservative force.

Gravitation Video Explanation

Gravitation Detailed Video Explanation


History of Gravitational Theory

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The history of the theory of gravitation is given below

  • According to PtolemyThe Sun, the moon, and planets were in uniform motion in circles called epicycles with the fixed earth at the center”.
  • This is known as Geo-centric Theory.
  • According to Aryabhatta, the earth moves around the sun along with the other planets.
  • Copernicus proposed the sun-centered theory according to which the Earth and all other planets move around the sun.
  • This theory is known as the Helio-centric theory.
  • After the acceptance of Copernicus's theory, Tycho Brahe made an accurate measurement of the position of stars and planets.
  • His data was analyzed by Johannes Kepler who concluded that orbits of the planets are not circular, but elliptical.
  • He proposed three laws known as Kepler’s laws.

Gravitation

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Newton’s Law of Gravitation

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Newton’s law of gravitation is also known as the Universal law of gravitation.

According to this law,

Every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of the masses of the particle and inversely proportional to the square of the distance between them.

Mathematically

\(F=G\frac {m_1m_2}{r^2}\)

Where

  • F is the gravitational force
  • m1 and m2 are the masses of the two bodies
  • G is known as the Gravitational constant
  • r is the distance between the two bodies.

This law holds good irrespective of the nature of two objects at all places and at all times throughout the universe.

  • That is why it is known as the Universal law of gravitation.
  • As F varies inversely as a square of distance, it is also known as the inverse square law force.

Gravitational Constant

The Gravitational constant is defined as the force of attraction between two bodies of unit masses separated by unit distance.

  • It is denoted by G.
  • The value of the gravitation constant is G = 6.67 x 10-11 N m2 kg-2
  • The dimension formula of G is [M-1L3T-2].

Newton’s Law of Gravitation in Vector Form

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Consider two bodies of masses m1 and m2 separated by distance r.

Newton’s Law of Gravitation in Vector Form
The force acting on m2 due to m1 is given by
\(\vec F_{21}=G\frac{m_1m_2}{r^2}\hat r_{21}\)
The force acting on m2 due to m1 is given by
\(\vec F_{12}=G\frac{m_1m_2}{r^2}\hat r_{12}\)
Where \(\hat r_{21}\) and \(\hat r_{12}\) are the unit vectors. But \(\hat r_{12} = -\hat r_{21}\) Therefore
\(\vec F_{21} = \vec F_{12}\)

The Gravitational force between two bodies is equal in magnitude but opposite in direction. Hence Gravitational force is Newtonian in nature.

Principle of Superposition of Gravitational Forces

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According to the principle of superposition of gravitational forces

The resultant gravitational force on a point mass due to the number of point masses is the vector sum of the gravitational forces exerted on that point mass due to a number of point masses.

Mathematically

\(\vec F_{net}=\vec F_{12}+\vec F_{13}+\vec F_{14}+......+\vec F_{1n}\)

Where

  • Fnet is the net force acting on particle 1.
  • F12 is the force acting on particle 1 due to particle 2.
  • Similarly, F13, F14, ……, F1n are the forces acting on particle 1 due to particles 2, 3,….n.

Newton's law of gravitation only applies to interactions between two particles; if the system has 'n' particles, the number of such interactions is

n(n - 1)/2


Acceleration Due to Gravity

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The acceleration produced in the motion of the body under the effect of gravity is known as acceleration due to gravity.

  • It is denoted by g.
  • It is a vector quantity.
  • The SI unit of acceleration due to gravity is m/s2.
  • The value of g on the surface of the earth is 9.8 m/s2.

The formula of acceleration due to gravity on the surface of a planet is given by

\(g=\frac{GM_P}{R_P^2}\)

Where

  • G is the Gravitational constant
  • MP is the mass of the planet
  • RP is the radius of the planet.

Gravitational Potential Energy

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When a body of mass (m) is displaced from infinity to a point under the gravitational influence of a source mass (M) without being accelerated, the amount of work done in displacing it into the source field is stored as potential energy.

  • This is referred to as gravitational potential energy.
  • Gravitational potential energy is the energy associated with the position of the particle.
  • In the work, energy, and power chapter, U = mgh, is valid only when the particle is near the surface of the earth.
  • Gravitational potential energy (U) is a scalar quantity and is measured in joules.

The formula of Gravitational potential energy for a system of two masses separated by distance r is given by

\(U=-G\frac {m_1m_2}{r^2}\)


Derivation of Newton’s Law of Gravitation From Kepler’s Law

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Assume a test mass rotates around a source mass in a nearly circular orbit with radius 'r' and constant angular speed (ω). The centripetal force acting on the test mass causes circular motion is given by

F = mrω2

But ω = 2π/T

Where T is the period of the revolution.

⇒ F = mr (2π/T)2

⇒ F = mr (4π2/T2)    ….(i)

According to Kepler’s Third law, we have

T2 ∝ r3

⇒ T2 = kr3

Where k = 4π2/GM

Using the above equation in equation (i), we get

F = mr (4π2/kr3)

F = GMm/r2


Things to Remember

  • Gravitation is the attraction of all masses in the universe to one another.
  • It is also known as gravitational attraction.
  • The force of gravity is the force with which the objects with mass attract towards each other.
  • According to Newton’s law of gravitation, F = G (m1m2/r2).
  • Gravitational potential energy is the energy associated with the position of the particle.
  • The formula of Gravitational potential energy is U = – G (m1m2/r).
  • The acceleration produced in the motion of the body under the effect of gravity is known as acceleration due to gravity.
  • The value of g on the surface of the earth is 9.8 m/s2.
  • The value of the gravitation constant is G = 6.67 x 10-11 N m2 kg-2

Sample Questions

Ques. A boy sitting on a chair in a satellite feels weightless because
(a) The earth doesn’t attract objects in the satellite. 
(b) The normal force by the chair of the person balances the gravity of the earth. 
(c) The normal force is zero. 
(d) A person in the satellite is not accelerating. (2 Marks)

Ans. The correct option is C.

Explanation: When the boy sits on a chair, he will feel two forces - one is gravity and the other is the force of the chair. Because of this normal force, the person sitting on the satellite chair will feel weightless.

Ques. The gravitational potential difference between the surface of a planet and a point 30 m above the surface is 3 joule/Kg. If the gravitational field is uniform then the work carrying a 4 Kg body to a height of 5m above the surface is:
(a) 2 Joule
(b) 20 Joule
(c) 40 Joule
(d) 10 Joule (2 Marks)

Ans. The correct option is A.

Explanation: As the gravitational field is uniform,

Total work is done = Mass × distance × potential gradient = 4 x 5 x 0.1 = 2 Joule.

Ques. At what height above the surface of the earth value of acceleration due to gravity is reduced to one-fourth of its value on the surface of the earth? (2 Marks) 

Ans. g h = g/4 = g (R/R+h)2

(R/R+h) = 14 = 12

R = h

2R - R = h

Ques. What are the two factors which determine whether a planet has an atmosphere or not? (2 Marks)

Ans. Two such factors are:

  1. Acceleration due to gravity at the surface of the planet. 
  2. Surface Temperature of the planet.

Ques. A body is weightless at the center of the earth. Why? (2 Marks)

Ans. At the center of the earth, g = 0

Therefore, w = mg = 0

Ques. Define Gravitational Field. (2 Marks)

Ans. The gravitational field intensity or gravitational field at a point in space is defined as the gravitational force experienced by a test mass placed at that point divided by its mass.

Ques. Define Orbital velocity. (2 Marks)

Ans. The minimum velocity required to put a satellite (or any object) in orbit around the Earth is called orbital velocity. The formula of orbital velocity is given by

\(v_o= \sqrt{\frac {GM}{R}}\)

Ques. What will be the orbital speed from a planet of mass 1030 kg and a radius of 10m? (3 Marks)

Ans. We know, the formula of orbital velocity is given by

\(v_o= \sqrt{\frac {GM}{R}}\)

On substituting the values, we get

\(v_o= \sqrt{\frac {6.67 \times 10^{-11} \times 10^{30}}{10^{8}}} = 8.1 \times 10^{5} m/s\)

Ques. What is a geostationary satellite? (1 Mark)

Ans. The satellite that appears at a fixed position and at a definite height to an observer on earth, is called a geostationary satellite.

Ques. What will be the mass of an object under free fall, if on earth’s surface, it weighs 100 N? (2 Marks)

Ans. At free fall weight becomes zero but mass remains unchanged.

Therefore, mg = 100 N

m = 100/g = 10 kg


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CBSE CLASS XII Related Questions

1.

Three capacitors each of capacitance 9 pF are connected in series. 

(a) What is the total capacitance of the combination? 

(b) What is the potential difference across each capacitor if the combination is connected to a 120 V supply?

      2.
      A capillary tube of radius r is dipped inside a large vessel of water. The mass of water raised above water level is M. If the radius of capillary is doubled, the mass of water inside capillary will be

        • 5M
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        • \(\frac M4\)

        • M

        3.

        A parallel plate capacitor made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s−1.

        1. What is the rms value of the conduction current?
        2. Is the conduction current equal to the displacement current?
        3. Determine the amplitude of B at a point 3.0 cm from the axis between the plates.
        A parallel plate capacitor made of circular plates

            4.
            A boy of mass 50 kg is standing at one end of a, boat of length 9 m and mass 400 kg. He runs to the other, end. The distance through which the centre of mass of the boat boy system moves is

              • 0
              • 1 m

              • 2 m

              • 3 m

              5.
              Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the to charges is the electric potential zero? Take the potential at infinity to be zero.

                  6.
                  A series LCR circuit with R = 20 W, L = 1.5 H and C = 35 μF is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?

                      CBSE CLASS XII Previous Year Papers

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