Kelvin Planck Statement: Examples, Carnot’s Cycle, Heat Engine

Collegedunia Team logo

Collegedunia Team

Content Curator

The Kelvin-Planck statement is derived from two different statements given by Lord Kelvin and Planck. The statement is also known as Kelvin’s statement and Planck’s statement.

  • Kelvin Planck's statement talks about an ideal heat engine that extracts heat and transforms it into work.
  • According to Kelvin-Planck’s statement, no process is possible whose sole result is the transfer of heat from a cooler object to a hotter object.
  • Based on Kelvin Planck's second law of thermodynamics, a thermal reservoir can never give a positive net amount of work.

Key Terms: Heat engine, Carnot engine, Kelvin statement, Second law of thermodynamics, First law of thermodynamics, Work, Energy, Efficiency.


Kelvin-Planck’s Statement

[Click Here for Sample Questions]

Kelvin-Planck's statement is an ideal case of the second law of thermodynamics.

  • Kelvin Planck's Statement states that we cannot build any device like the heat engine that runs on a cycle, absorbs heat energy, and completely transforms that energy into equal work.
  • Some of the heat is released into the atmosphere.
  • Practically it is impossible for any device to have 100% thermal efficiency.
  • Thus, Kelvin Planck's statement talks about an ideal heat engine that extracts heat and transforms it into work by violating the second law of thermodynamics.

The diagram below shows the practical operation of a heat engine:

.Kelvin Planck’s Statement in Detail 

Kelvin Statement- Planck Statement

Kelvin’s statement stated that:

It is not possible to derive a mechanical effect from any matter by cooling it below the maximum cooling temperature of the surrounding objects.

Planck’s statement states that:

The reversible system remains constant for the total sum of entropies. By combining both these statements the Kelvin-Planck statement was derived.

To decide whether a given process authorized by the first law should take place or not, the first law of thermodynamics needed the law of nature. So, the second law of thermodynamics can be stated in several ways, of which we will study Kelvin-Planck's statement of the second law of thermodynamics.


Kelvin Statement of Second Law of Thermodynamics

[Click Here for Sample Questions]

Kelvin-Planck's Second Law of Thermodynamics states that a reservoir never provides a net amount of positive work from the heat extracted from a heat reservoir. 

  • It is impossible to have a heat engine that runs between the two temperature levels and has no heat rejection.
  • It is also not possible to get a continuous supply of work from a body by cooling it to the lowest temperature.
  • The heat engine absorbs heat from the source (higher temperature) and turns it into useful work by releasing some amount of heat in the sink (surrounding).
  • This means that the heat sink is essential for the continuous supply of work by converting heat into equivalent work. 

Suppose that the source and the sink are at the same temperature; in this case,

  • The thermal efficiency of the heat engine becomes zero.
  • Also, we cannot do any work because the engine cools below the radiator's temperature. 
  • Therefore, the form of this law implies that no heat engine can convert the entire amount of heat extracted from the source into equivalent work.
  • It just means that not all heat can turn into work although the reverse is possible, we can convert all amounts of work into thermal energy. 
  • So, in real life, we cannot build a perfect 100% thermally efficient heat engine.

Planck’s Statement

[Click Here for Sample Questions]

Planck’s statement states that it is impossible to construct a heat engine that runs in a cycle, extracts heat from the reservoir, and performs an equal amount of work.

Planck’s statement has a huge role in various applications: 

  • Chemical reactions
  • Thermoelectricity
  • Electric cells
  • The study of solutions 
  • Change of states

Kelvin-Planck Statement Example

[Click Here for Sample Questions]

Kelvin Planck's Second Law of Thermodynamics states that practically a reservoir never provides a net amount of positive work from the heat extracted from a heat reservoir. So, it is impossible to operate a heat engine in between.

  • A Russian-German chemist and philosopher named Friedrich Wilhelm Ostwald introduced a theoretical concept of a "perpetual motion machine of the second kind, abbreviated as PMMSK or PMM2".
  • The PMMSK was a device capable of doing work only by absorbing heat from the body.
  • Such a device completely follows the first law of thermodynamics.
  • However, Kelvin Planck's statement indicates that it is practically impossible to construct PMMSK.

Carnot’s Engine

[Click Here for Sample Questions]

Any heat engine does not have 100% efficiency. French engineer and physicist named Nicolas Léonard Sadi Carnot introduced a hypothetical, ideal heat engine that has the maximum possible efficiency.

  • Carnot has advanced the study of the second law of thermodynamics by stating Carnot's rule which satisfies all the limitations on the maximum efficiency that the heat engine can achieve.
  • For maximum efficiency of the heat engine, the process should be reversible.

“A reversible heat engine operating between two temperatures is called Carnot Engine and the sequence of steps constituting one cycle is called the Carnot Cycle.”

Carnot Engine Video Explanation


Heat Engine

[Click Here for Sample Questions]

Any device that transforms heat partly into work or mechanical energy is called a Heat engine.

  • A quantity of matter inside the heat engine undergoes expansion or compression by absorbing or releasing heat is called the working substance of the heat engine.
  • For example, a mixture of fuel vapour and air in a gasoline or diesel engine or steam in a steam engine is the working substance.
  • The working substance undergoes a cyclic process, i.e. a sequence of processes that brings the substance to the same state in which it started.

A heat engine is made up of three basic parts:

  • Source
  • Working substance
  • Sink

If Q1 is the amount of heat absorbed by the working substance from the source at temperature T1, and Q2 is the amount of heat rejected to the heat sink at temperature T2. If W is the total amount of external work done by the active substance. Then, the net amount of heat absorbed is given by:

 dQ = Q1 - Q2

Since Q1 is at a higher temperature and Q2 is at a lower temperature, therefore, Q> Q2.

Here, we consider an ideal case of an engine, i.e. the Carnot engine, so the net amount of heat absorbed by the system is equal to the external work done by the system. 

So, applying the first law of thermodynamics:

dQ = dU + dW 

Here, dQ = dW (the functional substance returns to its initial state, then changes internal energy, i.e. dU = 0).

Or, 

W = Q1 - Q2

With this, we can also calculate the thermal efficiency of the engine. 

Thermal Efficiency

Thermal efficiency is indicated by the symbol η and written as: 

Thermal Efficiency = net work done per cycle (W) / the total amount of heat absorbed by the working substance in one cycle (Q1)

η = (Q1 - Q2) /Q1

For a 100% thermally efficient engine, this is unity. However, a certain amount of heat is always pushed back to the radiator, i.e. Q2 ≠ 0, so in this case, it is always less than 1.


Things To Remember

  • The Kelvin-Planck statement is derived from two different statements given by Lord Kelvin and Planck. 
  • Kelvin Planck's statement gives an overview of an ideal heat engine that extracts heat and transforms it into work.
  • Kelvin-Planck's statement is an ideal case of the second law of thermodynamics. 
  • Kelvin-Planck's Second Law of Thermodynamics states that a reservoir never provides a net amount of positive work from the heat extracted from a heat reservoir. 
  • Carnot gives the statement of a 100% thermally efficient engine.
  • Formula to calculate the work done by a heat engine: 

W = Q1 - Q2

  • The Thermal Efficiency of a heat engine can be calculated by the following formula:

η = (Q1 - Q2) /Q1


Sample Questions 

Ques. What do you mean by Kelvin -Planck's statement? (2 marks)

Ans. We cannot construct a heat engine that runs on a cycle, absorbs heat energy, and completely transforms that energy into equal work. Some of the heat is always released into the atmosphere.

Ques. What is the Kelvin Planck Statement about? (2 marks)

Ans. Kelvin Planck's statement deals with the conversion of work to heat, the conservation of work, the conservation of heat, and the conversion of heat to work.

Ques. What is H in Planck’s equation? (2 marks)

Ans. The energy in Planck’s equation is transferred as quanta and it is denoted by H. The value of H is 6.63 x 10-34 J/s.

Ques. Give a hypothetical example of the Kelvin-Planck Statement. (2 marks)

Ans. A hypothetical machine discovered by Wilhelm Ostwald was made for the sole purpose to transfer heat into work without causing any other effects.

Ques. During a cyclic process, a heat engine absorbs 500 J of heat from a hot reservoir, does work, and ejects an amount of heat 300 J into the surroundings (cold reservoir). Calculate the efficiency of the heat engine. (3 marks)

Ans. The efficiency of a heat engine is given by

μ =1- Q2/Q1 

= 1 - 300/500

μ = 1 – 0.6 

= 0.4

The heat engine has 40% efficiency. It implies that this heat engine converts only 40% of the input heat into work.

Ques. Which is the working fluid in Carnot’s cycle? Write the steps involved in the Carnot cycle. (2 marks)

Ans. The working fluid in a Carnot cycle is Ideal gas. 

The steps that are involved in a Carnot cycle are isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression.

Ques. (i) What is a Carnot heat engine? (2 marks)
(ii) What are the important parts of the Carnot heat engine?

Ans.

  1. A Carnot heat engine is a heat engine that operates on a reversible Carnot cycle and has the maximum efficiency that a heat engine can have. It is also known as a theoretical engine.
  2. The important parts of the Carnot heat engine are a cylinder, a reservoir, a heat-insulating stand, and a sink.

Ques. List the types of heat engines with their application and example. (2 marks)

Ans. Practically there are two types of heat engines:

  1. External combustion engines: In these engines, the heat is produced by burning fuel outside the main body (cylinder-piston arrangement) of the engine For Example - a steam engine
  2. Internal combustion engine: In these engines, the heat is produced by burning the fuel inside the main body. Example - Four-stroke Petrol and diesel engines

Ques. There are two Carnot engines A and B operating in two different temperature regions. For Engine, A the temperatures of the two reservoirs are 150°C and 100°C. For engine B the temperatures of the reservoirs are 350°C and 300°C. Which engine has lesser efficiency? (3 marks)

Ans. The efficiency for engine A = 1 − 373/423 = 0.11. 

So, engine A has an 11% efficiency

The efficiency for engine B = 1 - 573/623 = 0.08

So, engine B has only 8% efficiency.

The differences between the temperature of hot and cold reservoirs in both engines are the same but their efficiencies are different. The efficiency does not depend on the difference in the temperature but it depends on the ratio of the two temperatures. The engine which operates at a lower temperature has the highest efficiency.


Also Read:

CBSE CLASS XII Related Questions

1.
(a) A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60° with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning. 
(b) Would your answer change, if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered.)

      2.
      A circular disc is rotating about its own axis at uniform angular velocity \(\omega.\) The disc is subjected to uniform angular retardation by which its angular velocity is decreased to \(\frac {\omega}{2}\) during 120 rotations. The number of rotations further made by it before coming to rest is

        • 120
        • 60
        • 40
        • 20

        3.
        A closely wound solenoid of \(2000 \) turns and area of cross-section \(1.6 × 10^{-4}\  m^2\), carrying a current of \(4.0 \ A\), is suspended through its centre allowing it to turn in a horizontal plane. 
        (a) What is the magnetic moment associated with the solenoid?
        (b) What is the force and torque on the solenoid if a uniform horizontal magnetic field of \(7.5 × 10^{-2}\  T\) is set up at an angle of \(30º\) with the axis of the solenoid?

            4.

            A parallel plate capacitor made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V ac supply with a (angular) frequency of 300 rad s−1.

            1. What is the rms value of the conduction current?
            2. Is the conduction current equal to the displacement current?
            3. Determine the amplitude of B at a point 3.0 cm from the axis between the plates.
            A parallel plate capacitor made of circular plates

                5.

                In a parallel plate capacitor with air between the plates, each plate has an area of 6 × 10–3 m2 and the distance between the plates is 3 mm. Calculate the capacitance of the capacitor. If this capacitor is connected to a 100 V supply, what is the charge on each plate of the capacitor?

                    6.
                    A boy of mass 50 kg is standing at one end of a, boat of length 9 m and mass 400 kg. He runs to the other, end. The distance through which the centre of mass of the boat boy system moves is

                      • 0
                      • 1 m

                      • 2 m

                      • 3 m

                      CBSE CLASS XII Previous Year Papers

                      Comments



                      No Comments To Show