NCERT Solutions for class 11 Physics Chapter 8: Gravitation

NCERT Solutions for Class 11 Physics Chapter 8: Gravitation covers concepts of Kepler’s Planetary Laws of Motion, Newton’s Law of Gravitation, Acceleration Due to Gravity, and its variation. Gravity, also known as Gravitational Force, is the universal force of attraction that helps to keep things together.

Class 11 Physics Chapter 8 Gravitation along with Unit 4 Work, Energy, and Power and Unit 5 Motion of System of Particles and Rigid Body has a weightage of 17 marks in the Class 11 Physics Examination. Gravity is the force that holds us onto the Earth and does not let us fly up into space. Although we barely think about it in our daily lives Gravity is essential to keep the systems operating on the Earth and the Universe.

Download PDF: NCERT Solutions for Class 11 Physics Gravitation

NCERT Solutions for Class 11 Physics Chapter 8

Class 11 Physics Chapter 8 – Basic Concepts

Kepler’s Laws of Planetary Motion: Kepler formulated three laws to describe planetary motion – Law of Orbits, Law of areas, and Law of periods.

1. Law of orbits: All the planets revolve around the sun in an elliptical orbit with the sun being at one of the foci of the ellipse.
2. Law of areas: The speed of a planet varies such that its radius, the vector drawn from the sun to the planet sweeps out equal areas in equal intervals of times.
3. Law of Periods: The square of the time period of revolution of a planet is proportional to the cube of the semi-major axis of the elliptical orbit. \(T^2 \propto r^3\)

Newton’s law of gravitation states that each particle in the universe attracts another particle with a force that is directly proportional to the product of their masses. It is also inversely proportional to the square of the distance that exists between them.

\(F_g = {Gm_1m_2 \over r^2}\)

The gravitational potential is the amount of work done in bringing a body with unit mass from infinity to a point in the gravitational field of a body.

V = \(-GM \over R\)

Escape Velocity is the minimum velocity that is required to project a body vertically upward from the surface of the Earth so that it comes out of its gravitational field.

\(v_{escape} = \sqrt{2GM \over R}\)

Orbital velocity is the minimum velocity required to put a satellite into a given orbit around the Earth.

\(v_{orbital} = \sqrt{GM \over R}\)

Class 11 Physics Chapter 8 Related Guides:

Gravitational Potential Energy	Escape Speed	Earth satellites
Weightlessness	Neptune	Specific Gravity
Value of gravitational constant	Motion of celestial bodies in space	Value of g on moon
Relation between G and g	Specific gravity formula	Universal gravitation formula

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CBSE CLASS XII Related Questions

1.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:
- \( X_1 X_2 \)
- \( \sqrt{X_1 + X_2} \)
- \( \sqrt{X_1 X_2} \)
- \( \frac{X_2}{X_1} \)
View Solution
2.
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.
View Solution
3.
An electron in Bohr model of hydrogen atom makes a transition from energy level \(-1.51 \, \text{eV}\) to \(-3.40 \, \text{eV}\). Calculate the change in the radius of its orbit. The radius of orbit of electron in its ground state is \(0.53 \, \text{\AA}\).
View Solution
4.
In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:
- A
- B
- C
- D
View Solution
5.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).
View Solution
6.
A current-carrying coil is placed in an external uniform magnetic field. The coil is free to turn in the magnetic field. What is the net force acting on the coil? Obtain the orientation of the coil in stable equilibrium. Show that in this orientation the flux of the total field (field produced by the loop + external field) through the coil is maximum.
View Solution

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NCERT Solutions for class 11 Physics Chapter 8: Gravitation

NCERT Solutions for Class 11 Physics Chapter 8

Class 11 Physics Chapter 8 – Basic Concepts

CBSE CLASS XII Related Questions

1.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

2.
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

3.
An electron in Bohr model of hydrogen atom makes a transition from energy level \(-1.51 \, \text{eV}\) to \(-3.40 \, \text{eV}\). Calculate the change in the radius of its orbit. The radius of orbit of electron in its ground state is \(0.53 \, \text{\AA}\).

4.
In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:

5.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

Similar Physics Concepts

Comments

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NCERT Solutions for class 11 Physics Chapter 8: Gravitation

NCERT Solutions for Class 11 Physics Chapter 8

Class 11 Physics Chapter 8 – Basic Concepts

CBSE CLASS XII Related Questions

1.The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

2.Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

3.An electron in Bohr model of hydrogen atom makes a transition from energy level \(-1.51 \, \text{eV}\) to \(-3.40 \, \text{eV}\). Calculate the change in the radius of its orbit. The radius of orbit of electron in its ground state is \(0.53 \, \text{\AA}\).

4.In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:

5.A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

2.
Three batteries E1, E2, and E3 of emfs and internal resistances (4 V, 2 \(\Omega\)), (2 V, 4 \(\Omega\)) and (6 V, 2 \(\Omega\)) respectively are connected as shown in the figure. Find the values of the currents passing through batteries E1, E2, and E3.

3.
An electron in Bohr model of hydrogen atom makes a transition from energy level \(-1.51 \, \text{eV}\) to \(-3.40 \, \text{eV}\). Calculate the change in the radius of its orbit. The radius of orbit of electron in its ground state is \(0.53 \, \text{\AA}\).

4.
In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:

5.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).