Statements is an important topic in the Mathematics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.
This article gives you a full set of BITSAT PYQs for Statements with explanations for effective preparation. Practice of BITSAT Mathematics PYQs including Statements questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.
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BITSAT PYQs for Statements with Solutions
1.
Consider the following statements:
\( A \): Rishi is a judge.
\( B \): Rishi is honest.
\( C \): Rishi is not arrogant.
The negation of the statement "If Rishi is a judge and he is not arrogant, then he is honest" is:- \( B \rightarrow (A \vee C) \)
- \( (\neg B) \wedge (A \wedge C) \)
- \( B \rightarrow ((\neg A) \vee (\neg C)) \)
- \( B \rightarrow (A \wedge C) \)
2.
If
\( p \): It is raining today,
\( q \): I go to school,
\( r \): I shall meet my friends,
and \( s \): I shall go for a movie, then which of the following represents:
"If it does not rain or if I do not go to school, then I shall meet my friend and go for a movie?"- \( \neg (p \wedge q) \Rightarrow (r \wedge s) \)
- \( \neg (p \wedge \neg q) \Rightarrow (r \wedge s) \)
- \( \neg (p \wedge q) \Rightarrow (r \vee s) \)
- None of these
3.
Consider the following two propositions: $$ P_1: \neg (p \rightarrow \neg q) $$ $$ P_2: (p \wedge \neg q) \wedge ((\neg p) \vee q) $$ If the proposition $p \rightarrow ((\neg p) \vee q)$ is evaluated as FALSE, then:- \( P_1 \) is TRUE and \( P_2 \) is FALSE
- \( P_1 \) is FALSE and \( P_2 \) is TRUE
- Both \( P_1 \) and \( P_2 \) are FALSE
- Both \( P_1 \) and \( P_2 \) are TRUE
4.
Let \( p, q, r \) be three logical statements. Consider the compound statements: \[ S_1: (\neg p \vee q) \vee (\neg p \vee r) \] \[ S_2: p \rightarrow (q \vee r) \] Which of the following is NOT true?- If \( S_2 \) is true, then \( S_1 \) is true
- If \( S_2 \) is false, then \( S_1 \) is false
- If \( S_2 \) is false, then \( S_1 \) is true
- If \( S_1 \) is false, then \( S_2 \) is false
5.
In the truth table for the statement $(p \wedge q) \rightarrow(q \vee \sim p)$, the last column has the truth value in the following order is- TTFF
- FTTT
- TFTT
- TTTT




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