Sequence and Series is an important topic in the Mathematics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.
This article gives you a full set of BITSAT PYQs for Sequence and Series with explanations for effective preparation. Practice of BITSAT Mathematics PYQs including Sequence and Series questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.
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BITSAT PYQs for Sequence and Series with Solutions
1.
For all \( n \in \mathbb{N} \), the sum of \( \frac{n^5}{5} + \frac{n^3}{3} + \frac{7n}{15} \) is:- a negative integer
- a whole number
- a real number
- a natural number
2.
The value of $\frac{3}{4} + \frac{15}{16} +\frac{63}{64} +..... $ upto n terms is- $n - \frac{4^n}{3} - \frac{1}{3}$
- $n + \frac{4^{-n}}{3} - \frac{1}{3}$
- $n + \frac{4^n}{3} - \frac{1}{3}$
- $n - \frac{4^{-n}}{3} + \frac{1}{3}$
3.
If the sum of an infinite GP \( a, ar, ar^2, ar^3, \dots \) is 15 and the sum of the squares of each term is 150, then the sum of the series \( ar^2, a r^4, ar^6, \dots \) is:- \( \frac{5}{2} \)
- \( \frac{1}{2} \)
- \( \frac{25}{2} \)
- \( \frac{9}{2} \)
4.
Let $T(k)$ be the statement $1 + 3 + 5 + ... + (2k - 1)= k^2 +10$ Which of the following is correct?- T(1) is true
- T(k) is true $\Rightarrow$ T(k + 1) is true
- T(n) is true for all n $\in$ N
- All above are correct
5.
$2^{1/4}. 2^{2/8}. 2^{3/16}. 2^{4/32}......\infty$ is equal to-- 1
- 2
- 44622
- 44683
6.
The sum of the infinite geometric series $ S = \frac{a}{1-r} $ is 24, and the sum of the first three terms is 21. Find $ a $ and $ r $.- $ a = 12, r = \frac{1}{2} $
- $ a = 8, r = \frac{2}{3} $
- $ a = 6, r = \frac{3}{4} $
- $ a = 10, r = \frac{4}{5} $
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