BITSAT PYQs for Reaction Mechanism with Solutions: Practice BITSAT Previous Year Questions

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Shivam Yadav

Updated on - Dec 12, 2025

Reaction Mechanism is an important topic in the Chemistry section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.

This article gives you a full set of BITSAT PYQs for Reaction Mechanism with explanations for effective preparation. Practice of BITSAT Chemistry PYQs including Reaction Mechanism questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.

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BITSAT PYQs for Reaction Mechanism with Solutions

BITSAT PYQs for Reaction Mechanism with Solutions

  • 1.
    The product/s of the reaction, is/are: $Na _{2} CO _{3}+ CO _{2}+ H _{2} O \rightarrow$

      • $2 NaOH + CO _{2}$
      • $Na _{2} CO _{3}+ H _{2} CO _{3}$
      • $2 NaHCO _{3}$
      • None of these

    • 2.
      Le-Chatelier's principle is not applicable to

        • \({H}_2(g) + {I}_2(g) \rightleftharpoons 2 {HI}(g)\)
        • \({Fe}(s) + {S}(s) \rightleftharpoons {FeS}(s)\)
        • \({N}_2(g) + 3 {H}_2(g) \rightleftharpoons 2 {NH}_3(g)\)
        • \({N}_2(g) + {O}_2(g) \rightleftharpoons 2 {NO}(g)\)

      • 3.
        Hyperconjugation involves

          • $\sigma - \pi$ conjugation
          • $\sigma - \pi$ delocalisation
          • No bond resonance
          • All

        • 4.
          Which of the following is strongest nucleophile

            • $Br^{-}$
            • $: OH^{-}$
            • $: CN^{-}$
            • $C_2 H_5 \bar{O}$

          • 5.
            Which of the following compounds will react with two moles of $CH_3MgBr$ ?

              • $C_2H_5COOH $
              • $CH_3COOH $
              • $CH _{3} C \equiv CCH _{3}$
              • $HC \equiv C - CH _{2} OH$

            • 6.
              The ratio \( \frac{K_p}{K_c} \) for the reaction \[ {CO}(g) + \frac{1}{2} {O}_2(g) \rightleftharpoons {CO}_2(g) \] is:

                • \( (RT)^{1/2} \)
                • \( RT \)
                • 1
                • \( \frac{1}{\sqrt{RT}} \)

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