Magnetic Force is an important topic in the Physics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.
This article gives you a full set of BITSAT PYQs for Magnetic Force with explanations for effective preparation. Practice of BITSAT Physics PYQs including Magnetic Force questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.
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BITSAT PYQs for Magnetic Force with Solutions
1.
A proton enters a uniform magnetic field $\vec{B} = 0.5 \hat{k} \ \text{T}$ with velocity $\vec{v} = 10^6 \hat{i} \ \text{m/s}$. The magnitude of the magnetic force on the proton is:- $8.0 \times 10^{-14}$ N
- $1.6 \times 10^{-13}$ N
- $8.0 \times 10^{-13}$ N
- 0
2.
A charged particle moves through a magnetic field perpendicular to its direction, then
- kinetic energy changes but the momentum is constant
the linear momentum changes but the kinetic energy is constant
- both momentum and kinetic energy of the particle are not constant
- both momentum and kinetic energy of the particle are constant
3.
Two very long, straight, parallel wires carry steady currents $ I$ and $-I$ respectively. The distance between the wires is $d$. At a certain instant of time, a point charge $q$ is at a point equidistant from the two wires, in the plane of the wires. Its instantaneous velocity $v$ perpendicular to this plane. The magnitude of the force due to the magnetic field acting on the charge at this instant is- $\frac{\mu_{0} I q v}{2 \pi d}$
- $\frac{\mu_{0} I q v}{\pi d}$
- $\frac{2 \mu_{0} I q v}{\pi d}$
- $0$
4.
Electron of mass $m$ and charge $q$ is travelling with a speed $v$ along a circular path of radius $r$ at right angles to a uniform magnetic field of intensity $B$. If the speed of the electron is doubled and the magnetic field is halved the resulting path would have a radius:- $2r$
- $4r$
- $r / 4$
- $r / 2$
5.
An electron moves at right angle to a magnetic field of $1.5 \times 10^{-2} T$ with a speed of $6 \times 10^{7} m / s$. If the specific charge of the electron is $1.7 \times 10^{11} C / kg$. The radius of the circular nath will he- 2.9 cm
- 3.9 cm
- 2.35 cm
- 2 cm
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