Magnetic Field is an important topic in the Physics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.
This article gives you a full set of BITSAT PYQs for Magnetic Field with explanations for effective preparation. Practice of BITSAT Physics PYQs including Magnetic Field questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.
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BITSAT PYQs for Magnetic Field with Solutions
1.
Two parallel conductors carry current in opposite directions as shown in figure. One conductor carries a current of $10.0\, A$. Point $C$ is a distance $\frac{d}{2}$ to the right of the $10.0\, A$ current. If $d =18\, cm$ and $I$ is adjusted so that the magnetic field at $C$ is zero, the value of the current $I$ is- 10.0 A
- 30.0A
- 8.0A
- 18.0A
2.
A conducting loop of radius \( \frac{10}{\sqrt{\pi}} \) cm is placed perpendicular to a uniform magnetic field of 0.5T. The magnetic field is decreased to zero in 0.5 s at a steady rate. The induced emf in the circular loop at 0.25s is:- emf = 1 mV
- emf = 10 mV
- emf = 100 mV
- emf = 5 mV
3.
The cyclotron frequency of an electron grating in a magnetic field of $1 \,T$ is approximately- 28 MHZ
- 280 MHZ
- 2.8 GHZ
- 28 GHZ
4.
Two concentric coils of $10$ turns each are placed in the same plane. Their radii are $20\, cm$ and $40\, cm$ and carry $0.2\, A$ and $0.3\, A$. current respectively in opposite directions. The magnetic induction (in tesla) at the center is- $\frac{3}{4} \mu_0$
- $\frac{5}{4} \mu_0$
- $\frac{7}{4} \mu_0$
- $\frac{9}{4} \mu_0$
5.
A charged particle moving in a uniform magnetic field and losses $4\%$ of its kinetic energy. The radius of curvature of its path changes by- 2%
- 4%
- 10%
- 12%
6.
The free space inside a current carrying toroid is filled with a material of susceptibility \( \chi = 2 \times 10^{-2} \). The percentage increase in the value of magnetic field inside the toroid will be:2%
0.2%
0.1%
1%
7.
An infinitely long straight conductor is bent into the shape as shown below. It carries a current of $I$ ampere and the radius of the circular loop is $R$ metre. Then, the magnitude of magnetic induction at the centre of the circular loop is -- $\frac{\mu _0I}{2 \pi R}$
- $\frac{\mu _nI}{2 R}$
- $\frac{\mu _0I}{2 \pi R} \pi + 1 $
- $\frac{\mu _0I}{2 \pi R } \pi -1 $
8.
A charged particle is moving in a uniform magnetic field \( \mathbf{B} = 2\hat{i} + 3\hat{j} \) T. If it has an acceleration of \( \mathbf{a} = \alpha\hat{i} - 4\hat{j} \) m/s², then the value of \( \alpha \) will be:- \( 3 \)
- \( 6 \)
- \( 12 \)
- \( 2 \)
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