BITSAT PYQs for Functions with Solutions: Practice BITSAT Previous Year Questions

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Shivam Yadav

Updated on - Dec 12, 2025

Functions is an important topic in the Mathematics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.

This article gives you a full set of BITSAT PYQs for Functions with explanations for effective preparation. Practice of BITSAT Mathematics PYQs including Functions questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.

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BITSAT PYQs for Functions with Solutions

BITSAT PYQs for Functions with Solutions

  • 1.
    With the usual notation $\displaystyle \int_1^2 ([x^2]-[x]^2)dx$ is equal to

      • $4+\sqrt{2}-\sqrt{3}$
      • $4-\sqrt{2}+\sqrt{3}$
      • $4-\sqrt{2}-\sqrt{3}$
      • none of these

    • 2.
      The function $f(x) = \tan x - 4x$ is strictly decreasing on

        • $\left( - \frac{\pi}{3} , \frac{\pi}{3} \right)$
        • $\left( \frac{\pi}{3} , \frac{\pi}{2} \right)$
        • $\left( - \frac{\pi}{3} , \frac{\pi}{2} \right)$
        • $\left( \frac{\pi}{2} ,\pi \right)$

      • 3.
        Let the function $ f(x) = \sqrt{\log_e(1 - x^2)} $. Then the domain of $ f(x) $ is:

          • \( (-1, 0) \cup (0, 1) \)
          • \( (-1, 1) \)
          • \( (-1, 1) \setminus \{0\} \)
          • \( \left(-1, -\frac{1}{\sqrt{e}} \right) \cup \left( \frac{1}{\sqrt{e}}, 1 \right) \)

        • 4.
          IF $f\left(z\right) = \frac{7-z}{1-z^{2}} $ , where $z = 1 + 2i$, then $|f(z)|$ is equal to :

            • $\frac{|z|}{2}$
            • $| z |$
            • $2| z |$
            • None of these

          • 5.
            Let $f (x) = \frac{ax+ b}{cx + d} $ , then $fof(x) = x$, provided that :

              • d = - a
              • d = a
              • a = b = 1
              • a = b = c = d = 1

            • 6.
              Let $f : R \to R$ be a function defined by $f(x) = \frac{x -m}{x-n}$ , where $m \neq n$, then

                • f is one-one onto
                • f is one-one into
                • f is many-one onto
                • f is many-one into

              • 7.
                For the function $f\left(x\right)= \frac{x^{100}}{100} + \frac{x^{99}}{99} + ... \frac{x^{2}}{2} + x + 1 , $ f ' (1) = mf' (0), where m is equal to

                  • 50
                  • 0
                  • 100
                  • 200

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