BITSAT PYQs for Combinations with Solutions: Practice BITSAT Previous Year Questions

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Shivam Yadav

Updated on - Dec 15, 2025

Combinations is an important topic in the Mathematics section in BITSAT exam. Practising this topic will increase your score overall and make your conceptual grip on BITSAT exam stronger.

This article gives you a full set of BITSAT PYQs for Combinations with explanations for effective preparation. Practice of BITSAT Mathematics PYQs including Combinations questions regularly will improve accuracy, speed, and confidence in the BITSAT 2026 exam.

BITSAT PYQs for Combinations with Solutions

1.
Total number of books is $2n + 1$. One is allowed to select a minimum of the one book and a maximum of $n$ books. If total number of selections if $63$, then value of $n$ is :
- 3
- 6
- 2
- none of these
View Solution
2.
The total number of $4$-digit numbers in which the digits are in descending order, is
- $^{10}C_4 \times 4!$
- $^{10}C_4 $
- $\frac{10!}{4!}$
- None of these
View Solution
3.
A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw?
- 64
- 129
- 84
- None of these
View Solution

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BITSAT PYQs for Combinations with Solutions

1.Total number of books is $2n + 1$. One is allowed to select a minimum of the one book and a maximum of $n$ books. If total number of selections if $63$, then value of $n$ is :

2.The total number of $4$-digit numbers in which the digits are in descending order, is

3.A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw?

Fees Structure

Structure based on different categories

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1.
Total number of books is $2n + 1$. One is allowed to select a minimum of the one book and a maximum of $n$ books. If total number of selections if $63$, then value of $n$ is :

2.
The total number of $4$-digit numbers in which the digits are in descending order, is

3.
A box contains two white balls, three black balls and four red balls. In how many ways can three balls be drawn from the box if at least one black ball is to be included in the draw?