NCERT Solutions for class 11 Physics Chapter 15: Waves

NCERT Solutions for Class 11 Physics Chapter 15: Waves deals with the concepts of wave and wave motion. Wave motion is referred to as the energy and momentum movement from one point to another in a medium instead of actually transferring the substances between the places.

Class 11 Physics Chapter 15 Waves is a part of Unit 10 Oscillations and Waves which has a weightage of 10 marks in the Class 11 Physics Examination. The chapter covers concepts of transverse and longitudinal waves, the principle of superposition of waves, and the Doppler effect.

Download PDF: NCERT Solutions for Class 11 Physics Waves

NCERT Solutions for Class 11 Physics Chapter 15

The NCERT Solutions for Chapter 15 of Class 11 Physics are as given below –

Class 11 Physics Chapter 15 – Concepts Covered

A wave is a disturbance that travels through a material medium as a result of the repeated periodic motion of the particles of the medium about their mean positions without any actual transportation of matter.

The particles of the medium traversed by a wave have relatively small vibrations about their mean positions. However, the particles are not displaced permanently in the direction of propagation of the wave.

Mechanical waves can be propagated or produced only in a material medium.

These waves work on Newton’s laws of motion. For example, waves on strings, waves on the water surface, sound waves etc.

Electromagnetic Waves are waves that do not require any material medium for their production and propagation. They can pass through a vacuum or any other material medium.

Some examples of electromagnetic waves are visible light, ultraviolet light, microwaves, radio waves, etc.

Wave velocity is the time rate of propagation of wave motion in a given medium. It depends upon the nature of the medium.

Wave velocity (υ) = frequency (v) x wavelength (λ)

Matter waves are associated with moving particles of matter, like protons, electrons, neutrons etc.

Class 11 Physics Chapter 15 Related Guides:

Beats	Unit of Wavelength	Laplace Correction
Wave Speed	Gravity Waves	Types of Waves
Amplitude Formula	Intensity Formula	Gravity Waves

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Class 11 Physics Notes	Derivations in Physics
Relation between articles in Physics	Difference between in Physics	SI Units in Physics
Physics Study Notes	Physics Constants	Physics Formula

CBSE CLASS XII Related Questions

1.
Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it.
Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.
- Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of Assertion (A)
- Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of Assertion (A).
- Assertion (A) is true, but Reason (R) is false.
- Assertion (A) is false and Reason (R) is also false.
View Solution
2.
The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:
- \( E = 0, \quad V = 0 \)
- \( E = 0, \quad V = V_0 \text{ (a constant)} \)
- \( E \ne 0, \quad V \ne 0 \)
- \( E = E_0 \text{ (a constant)}, \quad V = 0 \)
View Solution
3.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).
View Solution
4.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?
View Solution
5.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:
- \( X_1 X_2 \)
- \( \sqrt{X_1 + X_2} \)
- \( \sqrt{X_1 X_2} \)
- \( \frac{X_2}{X_1} \)
View Solution
6.
A wire of resistance \( X \, \Omega \) is gradually stretched till its length becomes twice its original length. If its new resistance becomes 40 \( \Omega \), find the value of \( X \).
View Solution

View All

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NCERT Solutions for class 11 Physics Chapter 15: Waves

NCERT Solutions for Class 11 Physics Chapter 15

Class 11 Physics Chapter 15 – Concepts Covered

CBSE CLASS XII Related Questions

1.
Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it.
Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

2.
The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

3.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

4.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?

5.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

6.
A wire of resistance \( X \, \Omega \) is gradually stretched till its length becomes twice its original length. If its new resistance becomes 40 \( \Omega \), find the value of \( X \).

Similar Physics Concepts

Comments

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NCERT Solutions for class 11 Physics Chapter 15: Waves

NCERT Solutions for Class 11 Physics Chapter 15

Class 11 Physics Chapter 15 – Concepts Covered

CBSE CLASS XII Related Questions

1.Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it. Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

2.The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

3.A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

4.Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?

5.The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

6.A wire of resistance \( X \, \Omega \) is gradually stretched till its length becomes twice its original length. If its new resistance becomes 40 \( \Omega \), find the value of \( X \).

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Assertion (A): The deflection in a galvanometer is directly proportional to the current passing through it.
Reason (R): The coil of a galvanometer is suspended in a uniform radial magnetic field.

2.
The electric field (\( \vec{E} \)) and electric potential (\( V \)) at a point inside a charged hollow metallic sphere are respectively:

3.
A current carrying circular loop of area A produces a magnetic field \( B \) at its centre. Show that the magnetic moment of the loop is \( \frac{2BA}{\mu_0} \sqrt{\frac{A}{\pi}} \).

4.
Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen?

5.
The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

6.
A wire of resistance \( X \, \Omega \) is gradually stretched till its length becomes twice its original length. If its new resistance becomes 40 \( \Omega \), find the value of \( X \).