NCERT Solutions for class 11 Physics Chapter 13: Kinetic Theory

NCERT Solutions for Class 11 Physics Chapter 13: Kinetic Theory deals with the behaviour of gas molecules and ideal gas. An ideal gas is a gas that follows Boyle's law, Charles' law, Gay Lussac's law, and Avogadro’s law.

Class 11 Physics Chapter 13 Kinetic Theory belongs to Unit 9 Behaviour of Perfect Gases and Kinetic Theory of Gases. Along with Unit 7 and Unit 8, Unit 9 has a weightage of 20 marks. The NCERT Solutions for Chapter 13 deals with the molecular nature of matter and specific heat capacity.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 13


NCERT Solutions for Class 11 Physics Chapter 13

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Class 11 Physics Chapter 13 – Concepts Covered

  • Boyle’s Law: According to this law, the volume (V) of a fixed mass of a gas is inversely proportional to the pressure (P) of that gas, given that the temperature of the gas is kept constant.
V ∝ 1/P or PV = constant
  • Charle’s Law: The volume (V) of a given mass of a gas is directly proportional to the temperature of the gas, given that the pressure of the gas remains constant.
V ∝ T or VT = constant
V1T= V2T2
  • Gay Lussac’s Law: The pressure P of a given mass of gas is directly proportional to its absolute temperature T, given that the volume V of the gas remains constant.
P ∝ T or PT = constant
P1T= P2T2
  • Equation of State of An Ideal Gas: The relation between pressure, volume, and absolute temperature of a gas is known as its equation of state. 

PV = nRT

n is the number of moles of the gas and R is the molar gas constant which is equal to 8.315 JK-1mol-1

  • Dalton’s Law of Partial Pressures states that the net pressure applied by a mixture of non-interacting gases is equivalent to the sum of their pressures.

P = P1 + P2 + ------- + Pn

CBSE CLASS XII Related Questions

  • 1.
    An electron in Bohr model of hydrogen atom makes a transition from energy level \(-1.51 \, \text{eV}\) to \(-3.40 \, \text{eV}\). Calculate the change in the radius of its orbit. The radius of orbit of electron in its ground state is \(0.53 \, \text{\AA}\).


      • 2.
        A wire of resistance \( X \, \Omega \) is gradually stretched till its length becomes twice its original length. If its new resistance becomes 40 \( \Omega \), find the value of \( X \).


          • 3.

            Two slits 0.1 mm apart are arranged 1.20 m from a screen. Light of wavelength 600 nm from a distant source is incident on the slits. How far apart will adjacent bright interference fringes be on the screen? 


              • 4.
                Two infinitely long conductors kept along XX' and YY' axes are carrying current \( I_1 \) and \( I_2 \) along -X axis and -Y axis respectively. Find the magnitude and direction of the net magnetic field produced at point P(X, Y).


                  • 5.
                    In the figure, curved lines represent equipotential surfaces. A charge \( Q \) is moved along different paths A, B, C, and D. The work done on the charge will be maximum along the path:
                     curved lines represent equipotential surfaces

                      • A
                      • B
                      • C
                      • D

                    • 6.
                      The distance of an object from the first focal point of a biconvex lens is \( X_1 \) and distance of the image from second focal point is \( X_2 \). The focal length of the lens is:

                        • \( X_1 X_2 \)
                        • \( \sqrt{X_1 + X_2} \)
                        • \( \sqrt{X_1 X_2} \)
                        • \( \frac{X_2}{X_1} \)
                      CBSE CLASS XII Previous Year Papers

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