MHT CET 2026 May 21 Shift 2 PCM Question Paper is available for download here. Maharashtra State CET Cell conducted MHT CET 2026 PCM Exam on May 21 in Shift 2 from 2 PM to 5 PM in CBT mode.

  • The MHT CET 2026 PCM Question Paper consists of 150 multiple-choice questions (MCQs) totalling 200 marks divided into 3 sections: Physics, Chemistry, and Mathematics, with 50 questions in each subject.
  • Physics and Chemistry questions carry 1 mark each while Mathematics questions carry 2 marks each.
  • There is no negative marking for incorrect answers.

Download MHT CET 2026 May 21 Shift 2 PCM Question Paper with Solutions PDF from the links provided below.

MHT CET 2026 May 21 Shift 2 PCM Question Paper PDF Download

MHT CET 2026 May 21 Shift 2 Question Paper Download PDF Check Solution

Question 1:

If
y = y(x)
satisfies the differential equation \[ \left(\frac{2+\sin x}{1+y}\right)\frac{dy}{dx}=-\cos x \]
and \( y(0)=2 \), then \( y\left(\frac{\pi}{2}\right) \) is equal to:

  • (1) \(3\)
  • (2) \(4\)
  • (3) \(2\)
  • (4) \(1\)

Question 2:

The ratio of areas bounded by the curves \[ y=\cos x \]
and \[ y=\cos 2x \]
between \[ x=0,\qquad x=\frac{\pi}{3} \]
and the \(x\)-axis is:

  • (A) \(2:1\)
  • (B) \(1:2\)
  • (C) \(1:1\)
  • (D) \(1:3\)

Question 3:

If \[ (2+\sin x)\frac{dy}{dx}+(y+1)\cos x=0 \]
and \[ y(0)=1, \]
then find the value of \[ y\left(\frac{\pi}{2}\right). \]

  • (A) \(-\frac23\)
  • (B) \(-\frac13\)
  • (C) \(\frac43\)
  • (D) \(\frac13\)

Question 4:

If \[ \left(\frac{2+\sin x}{1+y}\right)\frac{dy}{dx}=-\cos x \]
and \[ y(0)=2, \]
then find the value of \[ y\left(\frac{\pi}{2}\right). \]

  • (1) \(3\)
  • (2) \(4\)
  • (3) \(2\)
  • (4) \(1\)

Question 5:

If \[ (2+\sin x)\frac{dy}{dx}+(y+1)\cos x=0 \]
and \( y(0)=1 \), then \( y\left(\frac{\pi}{2}\right) \) is equal to:

  • (1) \( -\dfrac{2}{3} \)
  • (2) \( -\dfrac{1}{3} \)
  • (3) \( \dfrac{4}{3} \)
  • (4) \( \dfrac{1}{3} \)

Question 6:

Solve for \(x\): \[ x+\log_{15}(5+3^x)=x\log_{15}5+\log_{15}24 \]

  • (1) \(2\)
  • (2) \(1\)
  • (3) \(5\)
  • (4) \(8\)

Question 7:

For \(n\in\mathbb{N}\), if \[ y=ax^{n+1}+bx^{-n}, \]
then \[ x^2\frac{d^2y}{dx^2} \]
is equal to:

  • (1) \((n-1)y\)
  • (2) \(n(n-1)y\)
  • (3) \(n(n+1)y\)
  • (4) \((n+1)y\)

Question 8:

Solve for \(x\): \[ x+\log_{15}(5+3^x)=x\log_{15}5+\log_{15}24 \]

  • (A) \(2\)
  • (B) \(1\)
  • (C) \(5\)
  • (D) \(8\)

Question 9:

For \(n\in\mathbb{N}\), if \[ y=ax^{n+1}+bx^{-n}, \]
then \[ x^2\frac{d^2y}{dx^2} \]
is equal to:

  • (1) \((n-1)y\)
  • (2) \(n(n-1)y\)
  • (3) \(n(n+1)y\)
  • (4) \((n+1)y\)

Question 10:

Let \[ f(x)=\int_{1}^{4}\log[x]\ dx, \]
where \([x]\) denotes the greatest integer function. Then the value of \(f(x)\) is:

  • (A) \(\log 2\)
  • (B) \(\log 3\)
  • (C) \(\log 5\)
  • (D) \(\log 6\)

MHT CET PCM Exam Pattern 2026

Parameter Details
Conducting Body Maharashtra Common Entrance Test Cell (Maharashtra CET Cell)
Exam Mode Online (Computer-Based Test)
Duration 180 minutes (3 hours)
Groups / Subjects PCM (Physics, Chemistry, Mathematics) for Engineering
Total Questions

150

Total Marks 200
Question Type Multiple Choice Questions (MCQs)
Marks Distribution
  • Mathematics – 2 marks/question
  • Physics and Chemistry – 1 mark/question
Negative Marking No
Syllabus Weightage
  • Class 12 – 80%
  • Class 11 – 20%

MHT-CET 2026 Paper Analysis