MHT CET 2026 May 21 Shift 2 PCM Question Paper is available for download here. Maharashtra State CET Cell conducted MHT CET 2026 PCM Exam on May 21 in Shift 2 from 2 PM to 5 PM in CBT mode.
- The MHT CET 2026 PCM Question Paper consists of 150 multiple-choice questions (MCQs) totalling 200 marks divided into 3 sections: Physics, Chemistry, and Mathematics, with 50 questions in each subject.
- Physics and Chemistry questions carry 1 mark each while Mathematics questions carry 2 marks each.
- There is no negative marking for incorrect answers.
Download MHT CET 2026 May 21 Shift 2 PCM Question Paper with Solutions PDF from the links provided below.
MHT CET 2026 May 21 Shift 2 PCM Question Paper PDF Download
| MHT CET 2026 May 21 Shift 2 Question Paper | Download PDF | Check Solution |
If
y = y(x)
satisfies the differential equation \[ \left(\frac{2+\sin x}{1+y}\right)\frac{dy}{dx}=-\cos x \]
and \( y(0)=2 \), then \( y\left(\frac{\pi}{2}\right) \) is equal to:
The ratio of areas bounded by the curves \[ y=\cos x \]
and \[ y=\cos 2x \]
between \[ x=0,\qquad x=\frac{\pi}{3} \]
and the \(x\)-axis is:
If \[ (2+\sin x)\frac{dy}{dx}+(y+1)\cos x=0 \]
and \[ y(0)=1, \]
then find the value of \[ y\left(\frac{\pi}{2}\right). \]
If \[ \left(\frac{2+\sin x}{1+y}\right)\frac{dy}{dx}=-\cos x \]
and \[ y(0)=2, \]
then find the value of \[ y\left(\frac{\pi}{2}\right). \]
If \[ (2+\sin x)\frac{dy}{dx}+(y+1)\cos x=0 \]
and \( y(0)=1 \), then \( y\left(\frac{\pi}{2}\right) \) is equal to:
Solve for \(x\): \[ x+\log_{15}(5+3^x)=x\log_{15}5+\log_{15}24 \]
For \(n\in\mathbb{N}\), if \[ y=ax^{n+1}+bx^{-n}, \]
then \[ x^2\frac{d^2y}{dx^2} \]
is equal to:
Solve for \(x\): \[ x+\log_{15}(5+3^x)=x\log_{15}5+\log_{15}24 \]
For \(n\in\mathbb{N}\), if \[ y=ax^{n+1}+bx^{-n}, \]
then \[ x^2\frac{d^2y}{dx^2} \]
is equal to:
Let \[ f(x)=\int_{1}^{4}\log[x]\ dx, \]
where \([x]\) denotes the greatest integer function. Then the value of \(f(x)\) is:
MHT CET PCM Exam Pattern 2026
| Parameter | Details |
|---|---|
| Conducting Body | Maharashtra Common Entrance Test Cell (Maharashtra CET Cell) |
| Exam Mode | Online (Computer-Based Test) |
| Duration | 180 minutes (3 hours) |
| Groups / Subjects | PCM (Physics, Chemistry, Mathematics) for Engineering |
| Total Questions |
150 |
| Total Marks | 200 |
| Question Type | Multiple Choice Questions (MCQs) |
| Marks Distribution |
|
| Negative Marking | No |
| Syllabus Weightage |
|








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