Expected Percentile for MHT CET April 17, 2026 Shift 2

Candidates scoring between 130-150 marks in MHT CET 2026, April 17, 2026, shift 2 are expected to secure a percentile of 98.00 to 99.49. The exam is expected to maintain a moderate difficulty level as per the previous shifts.

A score of 130-150 marks in the MHT CET 2026 exam is likely to get you a percentile of 98.00-99.49, placing candidates in the ranks of 1800 to 7000
130-150 marks are considered to be highly competitive for top-tier colleges.
The expected percentile for MHT CET April 17, 2026, Shift 2 may vary slightly due to shift-wise difficulty levels.
Normalisation plays an important role in ensuring fairness across different shifts.
To get in the top 100 rank, a candidate needs to score more than 180 marks, for which the expected percentile would be 99.5+.

Also Read:

Expected Percentile for MHT CET April 17, 2026 Shift 2 — Score 130-150 Marks

Key Summary

Candidates can get admission in decent colleges and branches with 130-150 marks in MHT CET 2026 exam but getting top colleges or CSE in top colleges will still be difficult.
Candidate with 160+ marks are expected to get percentile of 99.5, which can get admission in top colleges in Maharashtra.
In MHT CET 2026 exam the 130-150 marks range is highly competitive, where even a few marks can shift ranks by thousand.
With 130-150 marks in MHT CET 2026 exam you can get admission in COEP Pune, VJTI Mumbai, PICT Pune and VIT Pune.

MHT CET April 17, 2026 Shift 2: Marks vs Percentile

Candidates with 130-150 marks in MHT CET 2026 are expected to get in percentile range 98.00-99.49.
The percentile for 130-150 marks may vary depending on the difficulty level of the specific MHT CET exam 2026 exam shift.
Candidates who scores 160+ marks in MHT CET 2026 will get an expected percentile of 99.5+., which will get them admission in top colleges in Maharashtra.
95-97.99 percentile is expected in marks range between 100 to 129 marks in MHT CET 2026 exam.
Candidates get below 70 percentile in MHT CET 2026 exam for marks below 50.

Marks (Out of 200)	Expected Percentile
180 - 200	99.9 - 100
160 - 179	99.50 - 99.89
130 - 150	98.00 - 99.49
100 - 129	95.00 - 97.99
80 - 99	90.00 - 94.99
60 - 79	80.00 - 89.99
50 - 59	70.00 - 79.99
Below 50	Below 70.00

MHT CET April 17, 2026 Shift 2: Marks vs Percentile

Also Read:

Ques: What would be the percentile for 150 marks in MHT CET April 17,2026 shift 2?

Ans. The expected percentile for MHT CET 2026 with 130-150 marks would be 98-99.49 percentile , which will give candidates rank from 1800 to 7000 in MHT CET 2026.

Ques. With 98 percentile in MHT CET April 17,2026 shift 2, will it be enough to get admission in COEP Pune for CSE?

Ans. No, with 98 percentile in MHT CET 2026 exam candidates cannot get admission in COEP Pune for CSE branch, but they can get admission in mechanical, civil and electrical engineering branches.

MHT CET April 17, 2026 Shift 2: Marks vs Rank

Candidates with 130-150 marks in MHT CET Exam 2026 will get expected rank between 1800 to 7000.
Candidates can get into top 100 ranks in MHT CET 2026 exam with 190+ marks.
Candidates who scored 100-129 marks are expected to get rank between 7000 to 20000, this rank range is very competitive category where even small difference can cause a thousand rank jump.
Candidates’s expected rank will be 70000 when the marks is below 50 in MHT CET April 17,2026 Shift 2 exam

Marks (Out of 200)	Expected Rank
180 - 200	1 - 100
160 - 179	100 - 1800
130 - 150	1800 - 7000
100 - 129	7000 - 20000
80 - 99	20000 - 40000
60 - 79	40000 - 55000
50 - 59	55000 - 70000
Below 50	Above 70000

MHT CET April 17, 2026 Shift 2: Marks vs Rank

Also check:

100 Marks in MHT CET Percentile	120 Marks in MHT CET Percentile
130 Marks in MHT CET Percentile	140 Marks in MHT CET 2026 Percentile
135 Marks in MHT CET Percentile	150 marks in MHT CET Percentile

Ques. Which colleges can candidate get admission with 130-150 marks in MHT CET 2026 exam?

Ans. With 130-150 marks in MHT CET 2026, candidates can expect a rank with 1800 to 7000. With this rank range you can get admission in COEP Pune, VJTI Mumbai and top autonomous institutes, depending on branch choice.

Ques. What will be expected rank for 160 marks in MHT CET 2026 exam?

Ans. The expected rank for 160 marks in MHT 2026 exam would be from 500 to 1800.

College Options with 130-150 marks MHT CET 2026

Candidates with 130-150 marks in MHT CET 2026 can get expected rank 1800-7000 which is not enough to get admission in the top colleges for Maharashtra.
With 130-150 marks, candidates get a percentile range of 98.00 to 99.49 which gets them a seat in top colleges like COEP Pune, VJTI Mumbai and ICT Mumbai for branches Mechanical, Civil and Electrical.
Even with 98 and above percentile, candidates can get admission in top private colleges like PICT Pune, MIT Pune, MKSSS's Cummins College of Engineering for Women Pune and VIT Pune .
For government colleges like COEP Pune, VJTI Mumbai, ICT Mumbai and SPCE Mumbai the percentile cutoff is 99.4, 98.2, 99.47 and 99.05.
For private colleges like Sardar Patel Institute of Technology (SPIT), PICT Pune, MIT Pune and MKSSS's Cummins College of Engineering for Women Pune, the percentile cutoff is 99.8, 99.1, 96.18 and 98.91.

College	College Options	Branches	Percentile Cutoff
Top Government Colleges	COEP Pune	Mechanical, Civil, Electrical	99.4
	VJTI Mumbai	Electronics, Mechanical, Electrical	98.2
	ICT Mumbai	Chemical Engineering	99.47
	WCE Sangli	CSE, IT, Electronics	99.3
	SPCE Mumbai	Mechanical, Civil, Electrical	99.05
Top Private Colleges	Sardar Patel Institute of Technology (SPIT)	CS, IT	99.8
	PICT Pune	CSE, IT, AI-DS, ECE	99.1
	MIT Pune	CSE, IT, AI-DS, ECE, Mechanical, Civil, Electrical	96.18
	VIT Pune	CSE, IT, AI-DS, ECE, Mechanical, Civil, Electrical	98.9
	PCCOE Pune	CSE, IT, AI-DS, ECE, Mechanical, Civil, Electrical	98.6
	DY Patil Pune	CSE, IT, AI-DS, ECE, Mechanical, Civil, Electrical	98.1
	MKSSS's Cummins College of Engineering for Women Pune	IT, ECE, Mechanical	98.91

College Options with 130-150 marks MHT CET 2026

Also Read:

Ques. Is the 130-150 marks is the most competitive range in MHT CET 2026?

Ans. Yes, 130-150 marks is the most competitive range in which rank range is from 1800-7000 in MHT CET 2026 exam.

Ques. Is 130 marks sufficient for admission into a government engineering college in MHT CET 2026?

Ans. Yes, with 130 marks in MHT CET 2026 exam you can get admission in government engineering colleges. But in COEP Pune and VJIT you can get Mechanical, Civil and Electrical branches.

Expected Percentile for MHT CET April 17, 2026 Shift 2 — Score 130-150 Marks

Key Summary

MHT CET April 17, 2026 Shift 2: Marks vs Percentile

MHT CET April 17, 2026 Shift 2: Marks vs Rank

College Options with 130-150 marks MHT CET 2026

4ADFK1

1.
Determine the equivalent capacitance of an infinite circuit formed by repeating identical capacitors of capacitance \(C\).

2.
If \( \vec{a} = 2\hat{i} - \hat{j} + \hat{k} \) and \( \vec{b} = \hat{i} + 2\hat{j} - 3\hat{k} \), find the unit vector perpendicular to both \( \vec{a} \) and \( \vec{b} \).

3.
Which of the following compounds will undergo a Cannizzaro reaction:
\( \text{CH}_3\text{CHO},\ \text{C}_6\text{H}_5\text{CHO},\ \text{CH}_3\text{COCH}_3 \)?

4.
At what temperature will the r.m.s. velocity of a hydrogen molecule be equal to that of an oxygen molecule at \(47^\circ\text{C}\)?

5.
Evaluate the definite integral: \( \displaystyle \int_{3}^{5} |x-4|\,dx \).

6.
If \( y = \sin^{-1}(3x - 4x^3) \), find the derivative \( \dfrac{dy}{dx} \) in its standard form.

Comments

dOGVmW

Key Summary

MHT CET April 17, 2026 Shift 2: Marks vs Percentile

MHT CET April 17, 2026 Shift 2: Marks vs Rank

College Options with 130-150 marks MHT CET 2026

4ADFK1

1.Determine the equivalent capacitance of an infinite circuit formed by repeating identical capacitors of capacitance \(C\).

2.If \( \vec{a} = 2\hat{i} - \hat{j} + \hat{k} \) and \( \vec{b} = \hat{i} + 2\hat{j} - 3\hat{k} \), find the unit vector perpendicular to both \( \vec{a} \) and \( \vec{b} \).

3.Which of the following compounds will undergo a Cannizzaro reaction: \( \text{CH}_3\text{CHO},\ \text{C}_6\text{H}_5\text{CHO},\ \text{CH}_3\text{COCH}_3 \)?

4.At what temperature will the r.m.s. velocity of a hydrogen molecule be equal to that of an oxygen molecule at \(47^\circ\text{C}\)?

5.Evaluate the definite integral: \( \displaystyle \int_{3}^{5} |x-4|\,dx \).

6.If \( y = \sin^{-1}(3x - 4x^3) \), find the derivative \( \dfrac{dy}{dx} \) in its standard form.

Comments

dOGVmW

1.
Determine the equivalent capacitance of an infinite circuit formed by repeating identical capacitors of capacitance \(C\).

2.
If \( \vec{a} = 2\hat{i} - \hat{j} + \hat{k} \) and \( \vec{b} = \hat{i} + 2\hat{j} - 3\hat{k} \), find the unit vector perpendicular to both \( \vec{a} \) and \( \vec{b} \).

3.
Which of the following compounds will undergo a Cannizzaro reaction:
\( \text{CH}_3\text{CHO},\ \text{C}_6\text{H}_5\text{CHO},\ \text{CH}_3\text{COCH}_3 \)?

4.
At what temperature will the r.m.s. velocity of a hydrogen molecule be equal to that of an oxygen molecule at \(47^\circ\text{C}\)?

5.
Evaluate the definite integral: \( \displaystyle \int_{3}^{5} |x-4|\,dx \).

6.
If \( y = \sin^{-1}(3x - 4x^3) \), find the derivative \( \dfrac{dy}{dx} \) in its standard form.