WBJEE 2026 Mathematics Question Paper is available for download here. West Bengal Joint Entrance Examinations Board (WBJEEB) conducted WBJEE 2026 Mathematics exam on May 24 from 11:00 am to 1:00 pm. WBJEE 2026 Mathematics Question Paper consists of 75 questions for 100 marks to be attempted in 120 minutes.
- WBJEE Mathematics Paper is divided into 3 question categories containing questions from Calculus, Algebra, Coordinate Geometry, Vectors, 3D Geometry, Probability, etc.
- Category 1 contains 50 questions for 1 mark each and negative marking of 0.25.
- Category 2 contains 15 questions for 2 marks each and negative marking of 0.5.
- Category 3 contains 10 questions for 2 marks each and no negative marking.
Candidates can download WBJEE 2026 Mathematics Question Paper with Answer Key and Solution PDF from the links provided below. According to initial student reactions, WBJEE 2026 Maths paper was of Moderate to tough level.
WBJEE 2026 Mathematics Question Paper with Solutions PDF
| WBJEE Mathematics Question Paper 2026 | Download PDF | Check Solutions |
Question 1:
Given \(P(x)=x^{4}+ax^{3}+bx^{2}+cx+d\) such that \(x=0\) is the only real root of \(P^{\prime}(x)=0\). If \(P(-1)
View Solution
Concept:
The derivative of a polynomial function determines its stationary critical points and interval monotonicity profile. For a fourth-degree polynomial function \(P(x)\) with a positive leading coefficient, the behavior at the absolute limits dictates that \(P(x) \rightarrow \infty\) as \(x \rightarrow \pm\infty\). If its derivative \(P'(x) = 0\) possesses exactly one unique real root, that critical coordinate point must represent the absolute global minimum of the functional curve.
Step 1: Analyze the critical point and monotonicity.
Differentiating the given polynomial function with respect to \(x\): \(P'(x) = 4x^3 + 3ax^2 + 2bx + c\)
We are given that \(x = 0\) is the only real root of \(P'(x) = 0\). This implies that the derivative transforms its sign exclusively at \(x = 0\). Since the polynomial opens upwards globally (\(4 > 0\)), the function must be:
Strictly decreasing on the interval \((-\infty, 0)\)
Strictly increasing on the interval \((0, \infty)\)
Step 2: Evaluate interval boundary conditions on \([-1, 1]\).
Because the curve strictly transitions from decreasing to increasing at the origin, the value \(P(0)\) constitutes the absolute minimum of the function on any interval surrounding zero. Therefore, within the closed domain interval \([-1, 1]\):
The true minimum is located at \(x = 0\), meaning \(P(-1)\) cannot be the minimum value.
Since the function increases continuously as \(x\) moves rightward from \(0 \rightarrow 1\), we have \(P(1) > P(x)\) for all \(x \in [0, 1)\).
Step 3: Reconcile with the given boundary inequality.
The problem states that \(P(-1) < P(1)\). Since the function decreases monotonically on \([-1, 0]\), every single functional value in that negative section satisfies \(P(-1) \ge P(x) \ge P(0)\).
Combining our two boundary bounds shows that \(P(1)\) is strictly greater than all other values distributed inside the set: \(P(1) > P(-1) \ge P(x) \quad \forall x \in [-1, 1)\)
Thus, \(P(1)\) is definitively the absolute maximum element of the function on this interval, while \(P(-1)\) is not the minimum, which aligns with option (B). Quick Tip: When an upward-opening quartic curve has only a single real derivative root, its graph behaves visually like a standard parabola with a single absolute global trough. Sketching a quick asymmetrical U-shape matching \(P(-1) < P(1)\) reveals the boundary properties at a glance!
If \(\alpha, \beta\) are the roots of the equation \(x^{2}-px+q=0\) and \(\alpha>0\), \(\beta>0\), then \(\alpha^{\frac{1}{4}}+\beta^{\frac{1}{4}}=(p+6\sqrt{q}+4q^{\frac{1}{4}}\sqrt{p+2\sqrt{q}})^{\kappa}\), where K is:
If \(\sum_{r=1}^{\infty}\tan^{-1}\left(\frac{1}{2r^{2}}\right)=a\), then \(\tan a\) is equal to:
Consider a function \(f(x)\) which has exactly two roots at \(x=a\). If \(\lim_{x\rightarrow a}\left(\frac{\lambda f^{\prime}(x)}{f(x)}-\frac{1}{x-a}\right)=m \ (\ne0)\), then the value of \(\lambda\) is:
A vector given by \(\vec{P}=f(t)\hat{i}+g(t)\hat{j}+\hat{k}\) moves in such a way that it is always parallel to the vector \(\vec{Q}=-f^{\prime\prime}(t)\hat{i}+f^{\prime}(t)\hat{j}+\hat{k}\). The magnitude of \(\vec{P}\) is:
The expression \(\sum_{K=1}^{32}(3K+2)\left\{\sum_{r=1}^{10}\left(\sin\frac{2r\pi}{11}-i \cos\frac{2r\pi}{11}\right)\right\}^{K}\) represents:
\(\theta\) elimination from the equations \(x^{2}+y^{2}=\frac{x \cos 3\theta+y \sin 3\theta}{\cos^{3}\theta}=\frac{y \cos 3\theta-x \sin 3\theta}{\sin^{3}\theta}\) will be:
\(t_{n}\) denotes the nth term of an A.P. and \(t_{p}=\frac{1}{q}, \ t_{q}=\frac{1}{p}\). Then which one of the following options is a root of the equation \((p+2q-3r)x^{2}+(q+2r-3p)x+(r+2p-3q)=0\)?
Consider the sequence of numbers \(\{1, 2, 3, \dots, 13\}\). A person chooses three numbers at random from the sequence. The probability that the chosen three numbers form an A.P. is:
If \(f(x)=\frac{1+x}{1-x}\) and \(A\) is a matrix such that \(A^{3}=0\), then \(f(A) =\)
Which of the following statements is always true?
If \(0<\alpha<\beta<\gamma<\frac{\pi}{2}\) then the equation \(\frac{1}{x-\sin \alpha}+\frac{1}{x-\sin \beta}+\frac{1}{x-\sin \gamma}=0\) has:
On the set \(\mathbb{R}\) of real numbers the relation \(\rho\), defined by \(x\rho y\) \((x,y\in\mathbb{R})\) iff:
If \(\int\frac{\csc^{2}x-2010}{\cos^{2010}x}dx=-\frac{f(x)}{(g(x))^{2010}}+c\), where \(f(\frac{\pi}{4})=1\), then the number of solutions of the equation \(\frac{f(x)}{g(x)}=\{x\}\) in \([0, 2\pi]\) is/are (where \(\{\cdot\}\) represents fractional part function):
If the locus of mid point of any normal chord of the parabola \(y^{2}=4x\) is \(x-\lambda=\frac{\mu}{y^{2}}+\frac{y^{2}}{\nu}\), \(\lambda, \mu, \nu\in \mathbb{N}\), then \((\lambda+\mu+\nu)\) equals to:
The true set of values of 'K' for which \(\sin^{-1}\left(\frac{1}{1+\sin^{2}x}\right)=\frac{K\pi}{6}\) may have a solution is:
A mapping is selected at random from all mappings \(f:A\rightarrow A\) where set \(A=\{1,2,3,\dots,n\}\). If the probability that the mapping is injective is \(\frac{3}{32}\), then the value of \(n\) is:
Let \(A=[a,\infty)\) denotes the domain, then \(f:[a,\infty)\rightarrow B\) which is defined by \(f(x)=2x^{3}-3x^{2}+6\) will have an inverse for the smallest real value of 'a' if:
If \(a=\lim_{n\rightarrow\infty}\cos^{2n}x\), \((x=n\pi)\) and \(b=\lim_{n\rightarrow\infty}\cos^{2n}x\), \((x\ne m\pi)\), then numerical value of the area of the triangle whose vertices are \((a, b)\), \((-2, 1)\) and \((2, 1)\) is:
The position vectors of two adjacent sides of a rectangle \(OACB\) are \(\vec{a}\) and \(\vec{b}\) respectively, where \(O\) is the origin. If \(16|\vec{a}\times\vec{b}|=3(|\vec{a}|+|\vec{b}|)^{2}\) and \(\theta\) be the acute angle between the diagonals \(OC\) and \(AB\), then the value of \(\tan(\frac{\theta}{2})\) is:
The point of intersection of \(\vec{r}\times\vec{a}=\vec{b}\times\vec{a}\) and \(\vec{r}\times\vec{b}=\vec{a}\times\vec{b}\), where \(\vec{a}=\hat{i}+\hat{j}\) and \(\vec{b}=2\hat{i}-\hat{k}\) is:
Let \(a_{1},a_{2},a_{3},...\) are in G.P. such that \(n > m\), \(a_{n}>a_{m}\) and \(a_{1}+a_{n}=66\), \(a_{2}\cdot a_{n-1}=128\). If \(\sum_{r=1}^{n}a_{r}=126\), then \(n\) is:
The minimum length of intercept on any tangent to the ellipse \(\frac{x^{2}}{4}+\frac{y^{2}}{9}=1\) cut by the circle \(x^{2}+y^{2}=25\) is:
Intercepts of the plane \(\vec{r}\cdot\vec{n}=d \ (\ne0)\) on the coordinate axes respectively are:
The general solution of the equation \(\sin^{100}x-\cos^{100}x=1\) is:
If \(\vec{a}=\hat{i}+\hat{j}+\hat{k}\), \(\vec{b}=\hat{i}-\hat{j}+\hat{k}\), \(\vec{c}=\hat{i}+2\hat{j}-\hat{k}\) then the value of \(\left|\begin{matrix}\vec{a}\cdot\vec{a}&\vec{a}\cdot\vec{b}&\vec{a}\cdot\vec{c}
\vec{b}\cdot\vec{a}&\vec{b}\cdot\vec{b}&\vec{b}\cdot\vec{c}
\vec{c}\cdot\vec{a}&\vec{c}\cdot\vec{b}&\vec{c}\cdot\vec{c}\end{matrix}\right|\) is equal to:
Number of elements in the range set of \(f(x)=\left[\frac{x}{15}\right]\left[-\frac{15}{x}\right]\), for all \(x \in (0,90)\); (where \([\cdot]\) denotes the greatest integer function) is:
Let 10 Bags \(B_{1},B_{2},...,B_{10}\) which contain 21, 22, ..., 30 different articles respectively. Then the total number of ways to bring out 10 articles from a Bag is:
Let domain and range of \(f(x)\) and \(g(x)\) is \([0, \infty)\). If \(f(x)\) is an increasing function, \(g(x)\) is a decreasing function, \(h(x)=f\{g(x)\}\), \(h(0)=0\) and \(p(x)=h(x^{3}-2x^{2}+2x)-h(4)\) then for all \(x\in(0,2)\):
Consider the following ellipse: \(\frac{x^{2}}{f(K^{2}+2K+5)}+\frac{y^{2}}{f(K+11)}=1\), where \(f(x)\) is a positive decreasing function. Then the value (values) of K for which the major axis coincides with x-axis is:
The solution of the differential equation \(2x^{2}y\frac{dy}{dx}=\tan(x^{2}y^{2})-2xy^{2}\),
given \(y(1)=\sqrt{\frac{\pi}{2}}\) is:
The value of the integral \(\int\frac{(\sqrt[3]{x+\sqrt{2-x^{2}}})(\sqrt[6]{1-x\sqrt{2-x^{2}}})}{\sqrt[3]{1-x^{2}}}\,dx\) for \(x\in(0,1)\) is:
Consider the function \(y=f(x)\) defined implicitly by the equation \(y^{3}-3y+x=0\) on the interval \((-\infty,-2)\cup(2,\infty)\). The area of the region bounded by the curve \(y=f(x)\), the x-axis and the lines \(x=a,x=b\), where \(-\infty
The total number of polynomials of the form \(x^{3}+ax^{2}+bx+c\) which are divisible by \(x^{2}+1\), where \(a,b,c\in\{1,2,3,...,10\}\) is:
The term independent of x in the expansion of \(\left(\frac{x+1}{x^{\frac{2}{3}}-x^{\frac{1}{3}}+1}-\frac{x-1}{x-x^{\frac{1}{2}}}\right)^{15}\) is equal to:
For a real number y, consider \([y]\) denotes the greatest integer less than or equal to y. If \(f(x)=\frac{\tan(\pi[x-\pi])}{1+[x]^{2}}\), then:
If \(\int_{0}^{1}\left(\sum_{r=1}^{2013}\frac{x}{x^{2}+r^{2}}\right)\left(\prod_{r=1}^{2013}(x^{2}+r^{2})\right)dx=\frac{1}{2}\left[\left(\prod_{r=1}^{2013}(1+r^{2})\right)-K\right]\), then K is:
The least positive value of 'a' for which the equation \(\int_{0}^{x}(t^{2}-8t+13)dt=x \sin\frac{a}{x}\) has a solution is:
Let all the points on the curve \(x^{2}+y^{2}-10x=0\) are reflected about the line \(y=x+3\). If the locus of the reflected points is in the form \(x^{2}+y^{2}+gx+f+c=0\), then the value of \((g+f+c)\) is:
The equation \(|x+1|^{\log_{x+1}(3+2x-x^{2})}=(x-3)|x|\) has:
If the domain of \(f(x)\) is \((0,1)\), then the domain of \(y=f(e^{x})+f(\ln|x|)\) is:
The number of 3-digit numbers of the form \(xyz\) with \(x
Suppose A is denoted the set of all numbers between 1 and 700 which are divisible by 3 and let B is denoted the set of all numbers between 1 and 300 which are divisible by 7. If \(C=\{(a,b)|a\in A,b\in B, a\ne b \text{ and } a+b=\text{even number}\}\), then order of C is:
Let us define the power of a matrix \(A\) as the maximum \(m\in \mathbb{Z}^{+}\) such that \(A^{m}=I\). For two matrices \(A\) and \(B\) if \(A^{5}=I\) and \(ABA^{-1}=B^{2}\), then the power of the matrix \(B\) is between:
If for two real numbers \(a, b\) with \(|a|\le1\) and \(|b|\le1\), \(\frac{1}{3}+\frac{\sin^{-1}a+\sin^{-1}b}{4}+\frac{(\sin^{-1}a+\sin^{-1}b)^{2}}{16}+\frac{(\sin^{-1}a+\sin^{-1}b)^{3}}{64}+...=\frac{2(8-3\pi)}{3(16+3\pi)}\), then the value of \(\sin^{-1}(a\sqrt{1-b^{2}}+b\sqrt{1-a^{2}})\) is:
Let \(\det A=\left|\begin{matrix}l&m&n
p&q&r
1&1&1\end{matrix}\right|\). If \((l-m)^{2}+(p-q)^{2}=9\), \((m-n)^{2}+(q-r)^{2}=16\), \((n-l)^{2}+(r-p)^{2}=25\), then the value of \((\det A)^{2}\) is:
Let \(f:(0,1)\rightarrow(0,1)\) be a bijective differentiable function such that \(f^{\prime}(x)\ne0 \ \forall x\in(0,1)\) and \(f\left(\frac{1}{2}\right)=\frac{\sqrt{3}}{2}\). Suppose for all \(x\), \[ \lim_{t\rightarrow x} \frac{\int_{0}^{t}\sqrt{1-(f(s))^{2}}\,ds - \int_{0}^{x}\sqrt{1-(f(s))^{2}}\,ds}{f(t)-f(x)} = f(x) \]
Then the value of \(f\left(\frac{1}{4}\right)\) belongs to:
If 'a' is an integer lying in \([-5, 30]\), then the probability that the graph of \(y=x^{2}+2(a+4)x-5a+64\) lies above the x-axis is:
Consider a square \(ABCD\) of diagonal length \(2a\). The square is folded along the diagonal \(AC\) so that the plane of \(\Delta ABC\) is perpendicular to the plane of \(\Delta ADC\). In this case the shortest distance between \(AB\) and \(CD\) is:
If \(\int\frac{(1-x^{2})\,dx}{\sqrt{x}\sqrt{(1+x^{2})^{3}}}=\alpha\frac{x^{\beta}}{(1+x^{2})^{\gamma}}+C\), \(\alpha, \beta, \gamma\in\mathbb{R}\) and \(C\) is constant of integration, then \(\alpha:\beta:\gamma\) will be:
Let \(\vec{r}=\sin x(\vec{a}\times\vec{b})+\cos y(\vec{b}\times\vec{c})+2(\vec{c}\times\vec{a})\), where \(\vec{a},\vec{b}\) and \(\vec{c}\) are three non-coplanar vectors. It is given that \(\vec{r}\) is perpendicular to \((\vec{a}+\vec{b}+\vec{c})\). Then the possible value(s) of \((x^{2}+y^{2})\) is/are:
Let \(A_{1},A_{2},...,A_{6}\) are six sets, each with four elements and \(B_{1},B_{2},...,B_{n}\) are \(n\) sets, each with two elements. Let \(S=A_{1}\cup A_{2}\cup...\cup A_{6}=B_{1}\cup B_{2}\cup...\cup B_{n}\). Given that each element of \(S\) belongs to exactly four of the \(A\)'s and to exactly three of the \(B\)'s. Then \(n\) is:
A figure is bounded by the curves \(y=x^{2}+1\), \(y=0\), \(x=0\) and \(x=1\). The point at which a tangent should be drawn to the curve \(y=x^{2}+1\) for it to cut off a trapezium of the greatest area from the figure is:
The ends \(A, B\) of a straight line segment of constant length \(c\) slide upon the fixed rectangular axes \(OX, OY\) respectively. If the rectangle \(OAPB\) is completed, then the locus of the foot of the perpendicular drawn from \(P\) to \(AB\) is:
Let \(1\) lies between the roots of the equation \(y^{2}-my+1=0\) and \([x]\) denotes the greatest integer function. Then the value of \(\left[\left(\frac{4|x|}{x^{2}+16}\right)^{m}\right]\) is:
Let \(f(x)\) be a twice differentiable function in \([1,3]\) and \(f(1)=f(3)\). Further if \(|f^{\prime\prime}(x)|\le2\), then for all \(x\) in \([1, 3]\):
The quantities \(a_{1},a_{2},a_{3},......\) form an infinite decreasing G.P. If \(a_{1}=1\), then the common ratio of the progression for which the expression \(6a_{5}-16a_{4}-3a_{3}+12a_{2}\) is at a maximum is:
If \(f\) be a real valued function defined for all real numbers \(x\) such that for some fixed \(a>0,\) it satisfies \(f(x+a)=\frac{1}{2}+\sqrt{f(x)-(f(x))^{2}}\ \forall x\>, then \(f(x)\) is periodic with period:
Four natural numbers selected at random are multiplied together, then the probability that the digit in the unit's place in the product be 1, 3, 7 or 9 is:
Let \(f(x)\) be a real valued function which is monotonic and differentiable. Then for any reals \(a\) and \(b,\int_{f(a)}^{f(b)}2x\{b-f^{-1}(x)\}dx=\)
Tangent at a point \(P_{1}\) (other than \((0, 0)\)) on the curve \(y=x^{3}\) meets the curve again at \(P_{2}\). The tangent at \(P_{2}\) meets the curve at \(P_{3}\) and so on. Then the abscissae of \(P_{1},P_{2},P_{3},...,P_{n}\) form:
The equation \(x^{3}+5x^{2}+px+q=0\) and \(x^{3}+7x^{2}+px+r=0\) have two roots in common. If the third root of each equation is represented by \(x_{1}\) and \(x_{2}\) respectively, then GCD of \(x_{1}\), \(x_{2}\) will be:
Let \(a, b, c\) be non-zero real numbers, such that \(\int_{0}^{1}(1+\cos^{8}x)(ax^{2}+bx+c)dx=\int_{0}^{2}(1+\cos^{8}x)(ax^{2}+bx+c)dx\). Then \(ax^{2}+bx+c=0\) has:
Let \(Z_{1}, Z_{2}\) be the roots of the equation \(Z^{2}+pZ+q=0\), where the coefficients \(p\) and \(q\) may be complex numbers and also let \(A, B\) represent \(Z_{1}, Z_{2}\) respectively in the complex plane. If \(\angle AOB=\alpha\ne0\) and \(OA=OB\), where \(O\) is the origin, then the value of \(\frac{p^{2}}{q}\sec^{2}\frac{\alpha}{2}\) will be:
Let \(g(x)=ax+b\), where \(a<0\) and \(g\) is defined from \([1, 3]\) onto \([0, 2]\). Then the value of \(\cot(\cos^{-1}(|\sin x|+|\cos x|)+\sin^{-1}(-|\cos x|-|\sin x|))\) is equal to:
If \(\sum_{r=0}^{2n}a_{r}(x-2)^{r}=\sum_{r=0}^{2n}b_{r}(x-3)^{r}\) and \(a_{k}=1\ \forall k\ge1\), then the value of \(\frac{b_{n}}{{}^{2n+1}C_{n+1}}\) is:
If \(f(x)\) is differentiable for all \(x\in\mathbb{R}\) and satisfies the relation \(x=\lim_{n\rightarrow\infty}\frac{[1^{2}(f(x))^{x}]+[2^{2}(f(x))^{x}]+\dots+[n^{2}(f(x))^{x}]}{n^{3}}\), where \([\cdot]\) denotes the greatest integer function, then \(f^{\prime}(x)\) is equal to:
If a differentiable function satisfies \[ (x-y)f(x+y) - (x+y)f(x-y) = 2(x^2y-y^3), \qquad \forall x,y\in\mathbb{R} \]
and \(f(1)=2\), then:
Let \(f(x)>0\) for all \(x\in\mathbb{R}\) and \(f(x)\) is bounded. If \(\lim_{n\rightarrow\infty}\sum_{r=1}^{n}a^{r-1}\int_{(r-1)a}^{ra}\frac{f(x)dx}{f(x)+f(2ra-a-x)}=\frac{3}{5}\), where \(0
Consider the curve \(x=1-3t^{2}, y=t-3t^{3}\). The tangent to the curve at the point is inclined at an angle \(\phi\) to \(OX\) and the tangent at \(P(-2,2)\) meets the curve again at \(Q\). Then:
If \(f(x)=x(1331x^{2}-3630x+3300)\), then for \(a=\cos^{2}(\tan^{-1}(\sin(\cot^{-1}3)))\):
Let \(\vec{r}=\sin x(\vec{a}\times\vec{b})+\cos y(\vec{b}\times\vec{c})+2(\vec{c}\times\vec{a})\), where \(\vec{a},\vec{b}\) and \(\vec{c}\) are three non-coplanar vectors. It is given that \(\vec{r}\) is perpendicular to \((\vec{a}+\vec{b}+\vec{c})\). Then the possible value(s) of \((x^{2}+y^{2})\) is/are:
The parabola \(y=4-x^{2}\) has vertex \(P\). It intersects the \(x\)-axis at \(A\) and \(B\). If the parabola is translated from its initial position to a new position by moving its vertex along the line \(y=x+4,\) so that it intersects the \(x\)-axis at \(B\) and \(C\), then the abscissa of \(C\) will be:
If \(A_{1},A_{2},A_{3},...,A_{1006}\) be independent events such that \(P(A_{i})=\frac{1}{2i}\) \((i=1,2,...,1006)\) and the probability that none of the events occurs be \(\frac{\alpha!}{2^{\alpha}{(\beta!)}^{2}}\), then:
If \((4^{\sec^{2}\alpha})x^{2}+2x+(\beta^{2}-\beta+\frac{1}{2})=0\) has real roots, then the value/values of \((\cos\alpha+\cos^{-1}\beta)\) is/are:
WBJEE Exam Pattern 2026
| Aspect | Details |
|---|---|
| Exam Name | West Bengal Joint Entrance Examination (WBJEE) 2026 |
| Conducting Body | West Bengal Joint Entrance Examinations Board (WBJEEB) |
| Exam Level | State-Level Entrance Exam |
| Mode of Exam | Offline (OMR-Based) |
| Papers | Paper I – Mathematics Paper II – Physics & Chemistry (Combined) |
| Eligibility for Courses | Both Papers: Engineering, Technology, Architecture, Pharmacy Only Paper II: Pharmacy (except Jadavpur University) Only Paper I: Not eligible for admission |
| Total Marks | 200 Marks |
| Question Type | Multiple Choice Questions (MCQs) |
| Marking Scheme | Category 1: 1 mark/question, -0.25 for wrong Category 2: 2 marks/question, -0.5 for wrong Category 3: 2 marks/question, one or more correct, no negative marking |
| Total Duration | 4 Hours (2 Hours per Paper) |
| Exam Timing | Paper I (Mathematics): 11:00 AM – 1:00 PM Paper II (Physics & Chemistry): 2:00 PM – 4:00 PM |
| Medium of Exam | English & Bengali |








Comments