BITSAT 2026 May 26 Slot 2 Expected Marks vs Rank

Candidates scoring 380 marks in BITSAT 2026 May 26 Slot 2 can expect a rank of around 300, depending on the shift difficulty.

BITSAT 2026 May 26 Slot 2 paper is expected to be moderate to tough based on previous session analysis.
A 350 score is expected to have a rank around 8700+ for the BITSAT 2026 May 26 Slot 2 paper.
According to previous years’ trends, candidates require 350+ marks out of 390 to get CSE at BITS Pilani, as it is the most competitive across all BITS campuses.
Scoring around 320- 355 in BITSAT 2026 will help you secure CSE at BITS Hyderabad and BITS Goa, as it is the most preferred branch for engineering candidates.
With a score of 250 in BITSAT 2026, May 26 Slot 2, your rank will be around 22400+, making admission to BITS Hyderabad and Goa in Chemical and Civil Engineering courses possible, as it is an average score.

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BITSAT 2026 May 26 Slot 2 Expected Marks vs Rank

Key Summary

BITSAT 2026 May 26 Slot 2 timing is from 2:00 PM to 5:00 PM.
BITS Pilani has the competitive cutoff scores for all courses compared to all other campuses.
Candidates can expect their BITSAT 2026 results to be published around July 2026 on the official website at admissions.bits-pilani.ac.in for all the courses offered.
The best scores of candidates who have appeared in BITSAT Sessions 1 and 2 will be considered for the admission process.

BITSAT 2026 May 26 Slot 2: Expected Marks vs Rank

The table below shows the expected BITSAT 2026 marks vs rank based on previous sessions' cutoff analysis.

Scoring around 380+ marks in the BITSAT 2026 May 26 Slot 2 paper opens the door to BITS Pilani CSE programme, as your expected rank will be below 300.
A score of above 300 is considered good, as you can expect your BITSAT rank to be within 8700, making you eligible for CSE at BITS Hyderabad and the Goa campus.
With 250 marks in BITSAT 2026, you can expect your rank to be within 8000- 22400, helping you secure lower branches such as CE and ME at the BITS Goa campus.

Score Range	Expected Rank	Category Standing
380+	1- 304	Elite BITS Campus: BITS Pilani
351- 379	2319- 305	High Merit
301- 350	8789- 2320	Good
251- 300	22441- 8790	Average
226- 250	32500- 22441	Below Average
175- 225	32501- 35000	Low
Below 175	35001+	Very Low

Note: The above table is prepared based on the previous year's rank vs mark. The 2026 cutoff will be released on the official website.

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Ques. What rank can I expect for 320 marks in BITSAT 2026 May 26 Slot 2?

Ans. According to previous years' trend analysis, candidates scoring around 320 marks can expect a rank of around 8700+, which is considered a good performance. With 320 marks in BITSAT 2026 May 26 Slot 2 paper, you will get admission in ECE, EEE and Chemical Engineering at BITS Hyderabad and BITS Goa.

Ques. Is Slot 2 harder than Slot 1 in BITSAT 2026?

Ans. Yes, as per the previous session analysis, Slot 2 was harder than Slot 1 for the April 15 and April 16, 2026 paper. Maths and Physics were considered harder sections by candidates. The harder paper will yield lower marks for the same rank, making it less competitive for admission in the BITS campuses.

BITSAT 2026 May 26 Slot 2: Expected Difficulty Level

The following table shows the expected difficulty level for May 26 Slot 2 and good attempts based on the BITSAT 2026 session 1 trends.

Physics is expected to be moderate to tough with formula-based questions, and is expected to cover questions from high-weightage topics.
Chemistry is expected to be easy to moderate based on previous shifts' analysis.
Maths is expected to be moderate to tough, like every year and has the highest section-wise marks.

Subjects	Number of Questions	Maximum Marks	Expected Difficulty	Good Attempts
Physics	30	90	Moderate to Tough	21- 25
Chemistry	30	90	Easy to Moderate	24- 28
Maths	40	120	Moderate to Tough	27- 33
English Proficiency	10	30	Easy	9- 10
Logical Reasoning	20	60	Easy to Moderate	16- 19
Total	130	390	Moderate to Tough	97- 115

BITSAT 2026 May 26 Slot 2: Expected Difficulty Level

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BITSAT 2026 May 26 Slot 2: College Options Based On Your Marks

The following table shows the college options based on your BITSAT 2026 May 26 Slot 2 marks vs. rank analysis.

You will get BITS Pilani CSE and other top branches by scoring above 350+, as it corresponds to a rank below 300.
Candidates are likely to get CSE at BITS Hyderabad and BITS Goa with BITSAT marks of around 285 and 300+.
A score of 310+ helps you secure admission in the lower branches at BITS Pilani, Hyderabad and Goa campuses.
Scoring below 175 will make your admission only in BPharm courses and MSc at the BITS Hyderabad campus.

Score Range	Expected Rank	Campus Options	Available Branches
380+	1- 304	BITS Pilani	CSE, ECE
351 – 379	2319- 305	BITS Pilani and Goa	CSE ECE, EEE and other branches
306- 350	6000- 2320	BITS Hyderabad, Goa and Pilani	ECE, EEE, Mechanical, CSE (Goa and Hyd)
270 – 305	15000- 6001	BITS Goa / Hyderabad	Mechanical, ECE, EEE, Chemical
220 – 269	32000- 15001	BITS Hyderabad / Goa	Chemical, Civil, B.Pharm, Integrated MSc
175- 219	35000- 32000	BITS Hyderabad	B.Pharm, Integrated MSc Programmes
Below 175	Above 35000	BITS Hyderabad	Limited, depending on seat availability

Note: BITS Pilani official admissions data for 2026 is based on 2024 and 2025. All 2026 values will be released on admissions.bits-pilani.ac.in

You can check the campuses available based on your BITSAT Expected marks using Collegedunia’s BITSAT College Predictor by clicking on the link below:

Check BITSAT College Predictor 2026: Top Colleges Based on BITSAT Scores

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Ques. What is the good score in BITSAT May 26 Slot 2?

Ans. Scores ranging from 301 to 350+ in BITSAT 2026, May 26 slot 2, are expected to have a good score. Candidates will get admission in CSE, ECE, EE and ME at BITS Pilani, Goa and Hyderabad campuses as it is expected to have a rank around 2320- 8700+.

Ques. Is 250 a good score in BITSAT 2026?

Ans. 250 score in BITSAT is considered an average performance. Candidates with a score of 250 are expected to have a rank range of 8800 - 22400, and will have the opportunity to pursue Mechanical, Chemical or ECE at BITS Hyderabad and BITS Goa.

BITSAT Marks vs Rank: Reddit Discussion

According to a Reddit post, the user wanted to know the course and campus options based on a 221 score in the BITSAT exam. Many suggested that he/she will get lower branches such as BTech/ BPharm courses, BE lower branches such as ME, CE and MSC courses at BITS Hyderabad and BITS Goa campuses.

Source: Reddit

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BITSAT Marks vs Rank Last 3 Years’ Data

You can check the last three years BITSAT Cutoff marks from the table below:

Year	Document	PDF Link
2025	BITSAT 2025 Official Cutoff Marks	Check Here
2024	BITSAT 2024 Official Cutoff Marks	Check Here
2023	BITSAT 2023 Official Cutoff Marks	Check Here

Related Article:

Check BITSAT Counselling 2026: Dates, Choice Filling, Fees and Seat Allotment at bits-pilani.ac.in

Ques. Does BITSAT use percentile for admissions?

Ans. No, BITSAT admission is based on rank and marks scored by candidates in session 1 or 2. The merit list mainly shows the marks scored and the corresponding rank, and not on a percentile basis.

Ques. If I appeared in both sessions 1 and 2, which score will be considered for BITS admission?

Ans. If a candidate has appeared in session 1 and session 2, then BITS Pilani will consider the highest score achieved in both sessions for preparing the merit list.

Ques. What is the minimum score to get any branch at BITS Pilani in BITSAT 2026?

Ans. To get admission in the lower branches, such as EE, ME, CE and Civil engineering, you need to have a BITSAT score of around 220- 260+ to get admission and secure a seat in the BITS Pilani campus, as it is the most competitive among all BITS campuses.

BITSAT 2026 May 26 Slot 2 Expected Marks vs Rank

Key Summary

BITSAT 2026 May 26 Slot 2: Expected Marks vs Rank

BITSAT 2026 May 26 Slot 2: Expected Difficulty Level

BITSAT 2026 May 26 Slot 2: College Options Based On Your Marks

BITSAT Marks vs Rank: Reddit Discussion

BITSAT Marks vs Rank Last 3 Years’ Data

BITSAT Questions

1.
The magnetic field at the center of a circular current-carrying loop of radius $R$ is $B_0$. The magnetic field at an axial point at a distance $x = R$ from the center of the loop is:

2.
If \(y^x = e^{y - x}\), then \(\frac{dy}{dx}\) is equal to:

3.
If A and B are symmetric matrices of same order such that \(\text{AB} + \text{BA} = \text{X}\) and \(\text{AB} - \text{BA} = \text{Y}\), then \((\text{XY})^\text{T} =\)

4.
The domain of the function \(f(x) = \sqrt{x - \sqrt{1 - x^2\) is:}

5.
1.1 mole of A mixed with 2.2 moles of B and the mixture is kept in a 1 L flask and the equilibrium, \(\text{A} + 2\text{B} \rightleftharpoons 2\text{C} + \text{D}\) is reached. If at equilibrium 0.2 mole of C is formed then the value of \(\text{K}_c\) will be

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Key Summary

BITSAT 2026 May 26 Slot 2: Expected Marks vs Rank

BITSAT 2026 May 26 Slot 2: Expected Difficulty Level

BITSAT 2026 May 26 Slot 2: College Options Based On Your Marks

BITSAT Marks vs Rank: Reddit Discussion

BITSAT Marks vs Rank Last 3 Years’ Data

BITSAT Questions

1.The magnetic field at the center of a circular current-carrying loop of radius $R$ is $B_0$. The magnetic field at an axial point at a distance $x = R$ from the center of the loop is:

2.If \(y^x = e^{y - x}\), then \(\frac{dy}{dx}\) is equal to:

3.If A and B are symmetric matrices of same order such that \(\text{AB} + \text{BA} = \text{X}\) and \(\text{AB} - \text{BA} = \text{Y}\), then \((\text{XY})^\text{T} =\)

4.The domain of the function \(f(x) = \sqrt{x - \sqrt{1 - x^2\) is:}

5.1.1 mole of A mixed with 2.2 moles of B and the mixture is kept in a 1 L flask and the equilibrium, \(\text{A} + 2\text{B} \rightleftharpoons 2\text{C} + \text{D}\) is reached. If at equilibrium 0.2 mole of C is formed then the value of \(\text{K}_c\) will be

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The magnetic field at the center of a circular current-carrying loop of radius $R$ is $B_0$. The magnetic field at an axial point at a distance $x = R$ from the center of the loop is:

2.
If \(y^x = e^{y - x}\), then \(\frac{dy}{dx}\) is equal to:

3.
If A and B are symmetric matrices of same order such that \(\text{AB} + \text{BA} = \text{X}\) and \(\text{AB} - \text{BA} = \text{Y}\), then \((\text{XY})^\text{T} =\)

4.
The domain of the function \(f(x) = \sqrt{x - \sqrt{1 - x^2\) is:}

5.
1.1 mole of A mixed with 2.2 moles of B and the mixture is kept in a 1 L flask and the equilibrium, \(\text{A} + 2\text{B} \rightleftharpoons 2\text{C} + \text{D}\) is reached. If at equilibrium 0.2 mole of C is formed then the value of \(\text{K}_c\) will be