KCET 2024 Mathematics Question Paper is available here for download. KCET Mathematics question paper was conducted on April 18, 2024 by Karnataka Examination Authority (KEA). KCET 2024 Mathematics question paper consists of 60 questions to be attempted in 80 minutes for a total of 60 marks.
KCET 2024 Mathematics Question Paper with Answer Key PDF
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KCET 2024 Mathematics Question Paper with Solution
Question 1:
Two finite sets have *m* and *n* elements respectively. The total number of subsets of the first set is 56 more than the total number of subsets of the second set. The values of *m* and *n* respectively are:
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If [x]2 - 5[x] + 6 = 0, where [x] denotes the greatest integer function, then:
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If in two circles, arcs of the same length subtend angles 30° and 78° at the center, then the ratio of their radii is:
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If ∆ABC is right-angled at C, then the value of tan A + tan B is:
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The real value of α for which (1 - i sin α)/(1 + 2i sin α) is purely real is:
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The length of a rectangle is five times the breadth. If the minimum perimeter of the rectangle is 180 cm, then:
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The value of 49C3 + 48C3 + 47C3 + 46C3 + 45C3 + 45C4 is:
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Using the recursive property of binomial coefficients: n+1Cr = nCr + nCr-1. Adding terms iteratively, we combine: 49C3+ 48C3+...+45C4 = 50C4
Quick Tip: Use the recursive property of binomial coefficients to simplify summations.In the expansion of (1 + x)n, nC1 + 2 * nC2 + 3 * nC3 + ... + n * nCn is equal to:
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If Sn stands for the sum to n terms of a G.P. with a as the first term and r as the common ratio, then S1/S2 is:
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If A.M. and G.M. of roots of a quadratic equation are 5 and 4 respectively, then the quadratic equation is:
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The angle between the line x + y = 3 and the line joining the points (1, 1) and (-3, 4) is:
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The equation of the parabola whose focus is (6,0) and directrix is x = -6 is:
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Question 13:
limx→π/4 (√2 cos x - 1)/(cot x - 1) is equal to:
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The negation of the statement “For every real number x, x2 + 5 is positive” is:
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Let *a*, *b*, *c*, and *d* be the observations with mean *m* and standard deviation *S*. The standard deviation of the observations *a* + *k*, *b* + *k*, *c* + *k*, *d* + *k* is:
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Let f : R → R be given by f(x) = tan x. Then f-1(1) is:
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Let f : R → R be defined by f(x) = x2 + 1. Then the pre-images of 17 and -3 respectively are:
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Let (g o f)(x) = sin x and (f o g)(x) = (sin √x)2. Then:
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Let A = {2, 3, 4, 5, . . ., 16, 17, 18}. Let R be the relation on the set A of ordered pairs of positive integers defined by (a, b)R(c, d) if and only if ad = bc for all (a, b), (c, d) ∈ A × A. Then the number of ordered pairs of the equivalence class of (3, 2) is:
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If cos-1x + cos-1y + cos-1z = 3π, then x(y + z) + y(z + x) + z(x + y) equals to:
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If 2 sin-1x - 3 cos-1x = 4x, x ∈ [-1,1], then 2 sin-1x + 3 cos-1x is equal to:
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If A is a square matrix such that A2 = A, then (I + A)3 is equal to:
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If A = [1 1] [1 1] then A10 is equal to:
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If
then f(1) * f(3) * f(5) + f(5) * f(1) is:
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If
is the adjoint of a 3 x 3 matrix A and |A| = 4, then α is equal to:
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If A = [x 1] [1 x] and B = [x 1 1] [1 x 1] [1 1 x] then dB/dx is:
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Let f(x) = [cos x x 1 ] [2sin x x 2x] [sin x x x ] Then lim x→0 f(x) / x2 is:
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Examine each element of the matrix f(x) as x → 0. The trigonometric terms behave as cos x → 1 and sinx ~ x for small x. Dividing each element by x2: - Terms involving cos x approach 0 because cos x does not scale with x2. - Terms involving sin x approach 0 as sin x ~ x and dividing by x2 yields 0. - Constant terms divided by x2 also approach 0. Thus, the entire matrix f(x)/x2 approaches 0 as x → 0.
Which one of the following observations is correct for the features of the logarithm function to any base b > 1?
- (A) The domain of the logarithm function is R, the set of real numbers.
- (B) The range of the logarithm function is R+, the set of all positive real numbers.
- (C) The point (1,0) is always on the graph of the logarithm function.
- (D) The graph of the logarithm function is decreasing as we move from left to right.
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The function f(x) = |cos x| is:
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If y = 2x3x, then dy/dx at x = 1 is:
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Let the function satisfy the equation f(x + y) = f(x)f(y) for all x, y ∈ R, where f(0) ≠ 0. If f(5) = 3 and f′(0) = 2, then f′(5) is:
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The value of C in (0,2) satisfying the mean value theorem for the function f(x) = x(x - 1)2, x ∈ [0, 2] is equal to:
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d/dx cos2[cot-1 √ (3-x) / (2+x) ] is:
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For the function f(x) = x3 – 6x2 + 12x – 3, x = 2 is:
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The function xx, x > 0 is strictly increasing at:
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The maximum volume of the right circular cone with slant height 6 units is:
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If f(x) = xex(1-x), then f(x) is:
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∫ sin x / (3 + 4 cos2 x) dx
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Substitute u = cos x: du = -sin x dx, dx = du / -sin x. Transform the integral: ∫ -du / (3 + 4u2) = -1/2√3 tan-1 (2u / √3) + C = -1/2√3 tan-1 (2 cos x / √3) + C.
∫π-π (1 - x2) sin x cos2 x dx =
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The integrand is an odd function due to sin x's presence, and the symmetric limits [-π, π] imply: ∫π-π (1 - x2) sin x cos2 x dx = 0.
∫ dx / (x (6(log x)2 + 7log x + 2)) =
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Let u = log x, then dx = x du = eu du, and rewrite the integral: ∫ du / (eu (6u2 + 7u + 2)). Apply partial fractions to decompose the quadratic expression in the denominator and integrate. Solution gives: log |(2u + 1) / (3u + 2)| + C = log |(2 log x + 1) / (3 log x + 2)| + C.
∫ sin 5x / sin x dx
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∫51 (|x − 3| + |1 – x|) dx
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limn→∞ ( 1/(n2+12) + 1/(n2+22) + ... + 1/(n2+n2)) =
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The expression can be approximated by a Riemann sum for the integral of a function over an interval. Here, the function is 1/(n2+k2), and the variable k runs from 1 to n. Thus, the sum approximates: limn→∞ Σnk=1 1/(n2+k2) = limn→∞ 1/n Σnk=1 1/(1+(k/n)2). Recognizing the expression inside the sum as a Riemann sum for the integral of 1/(1+x2) from 0 to 1, the limit evaluates to: ∫10 1/(1+x2) dx = [tan-1(x)]10 = tan-1(1) - tan-1(0) = π/4. But to match option (C), it appears there was an error in the problem or the options provided. Assuming consistency with common integral evaluations, the limit actually evaluates to π/4. Adjustments might be needed based on the actual problem intent or misprinted options.
The area of the region bounded by the line y = 3x and the curve y = x3 in sq. units is:
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The area of the region bounded by the line y = x and the curve y = x3 is:
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The solution of edy/dx = x + 1, y(0) = 3 is:
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The family of curves whose *x* and *y* intercepts of a tangent at any point are respectively double the *x* and *y* coordinates of that point is:
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The vectors AB = 3i + 4k and AC = 5i – 2j + 4k are the sides of a △ABC. The length of the median through A is:
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The volume of the parallelepiped whose co-terminous edges are i + j, i + k, i + j is:
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Let a and b be two unit vectors and θ is the angle between them. Then a + b is a unit vector if:
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If a, b, c are three non-coplanar vectors and p, q, r are vectors defined by: p = (b x c)/[a b c], q = (c x a)/[a b c], r = (a x b)/[a b c] then (a + b) · p + (b + c) · q + (c + a) · r is:
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If lines (x-1)/(-3) = (y-2)/(2k) = (z-3)/2 and (x-1)/(3k) = (y-5)/2 = (z-6)/(-5) are mutually perpendicular, then k is equal to:
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The distance between the two planes 2x + 3y + 4z = 4 and 4x + 6y + 8z = 12 is:
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The sine of the angle between the straight line (x-2)/3 = (y-3)/4 = (z-4)/-5 and the plane 2x – 2y + z = 5 is:
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The equation xy = 0 in three-dimensional space represents:
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The plane containing the point (3, 2, 0) and the line (x-2)/1 = (y-6)/5 = (z-4)/4 is:
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Corner points of the feasible region for an LPP are (0, 2), (3, 0), (6, 0), (6, 8) and (0, 5). Let z = 4x + 6y be the objective function. The minimum value of z occurs at:
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A die is thrown 10 times. The probability that an odd number will come up at least once is:
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A random variable X has the following probability distribution:

If the mean of the random variable X is 1/3, then the variance is:
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If a random variable X follows the binomial distribution with parameters n = 5, p, and P(X = 2) = 9 P(X = 3), then p is equal to:
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