WBJEE PYQs for Hybridisation with Solutions: Practice WBJEE Previous Year Questions

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Yashodeep Mahurkar

Updated on - Dec 31, 2025

Hybridisation is an important topic in the Chemistry section in WBJEE exam. Practising this topic will increase your score overall and make your conceptual grip on WBJEE exam stronger.

This article gives you a full set of WBJEE PYQs for Hybridisation with explanations for effective preparation. Practice of WBJEE Chemistry PYQs including Hybridisation questions regularly will improve accuracy, speed, and confidence in the WBJEE 2026 exam.

WBJEE PYQs for Hybridisation with Solutions

1.
The $sp^3d^2$ hybridization of central atom of a molecule would lead to
- square planar geometry
- tetrahedral geometry
- trigonal bipyramidal geometry
- octahedral geometry
View Solution
2.
Which one of the following compounds has $ s{{p}^{2}} $- hybridisation?
- $ C{{O}_{2}} $
- $ S{{O}_{2}} $
- $ {{N}_{2}}O $
- $ ~CO $
View Solution
3.
The state of hybridization of the central atom and the number of lone pairs over the central atom in $POCl_{3}$ are
- $sp, 0$
- $sp^{2}, 0$
- $sp^{3}, 0$
- $dsp^{2}, 1$
View Solution
4.
Hybridisation of the negative carbons in (1) and (2) are:
- sp2 and sp3
- sp3 and sp2
- both sp2
- both sp3
View Solution

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WBJEE PYQs for Hybridisation with Solutions

1.The $sp^3d^2$ hybridization of central atom of a molecule would lead to

2.Which one of the following compounds has $ s{{p}^{2}} $- hybridisation?

3.The state of hybridization of the central atom and the number of lone pairs over the central atom in $POCl_{3}$ are

4. Hybridisation of the negative carbons in (1) and (2) are:

Fees Structure

Structure based on different categories

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1.
The $sp^3d^2$ hybridization of central atom of a molecule would lead to

2.
Which one of the following compounds has $ s{{p}^{2}} $- hybridisation?

3.
The state of hybridization of the central atom and the number of lone pairs over the central atom in $POCl_{3}$ are

4.
Hybridisation of the negative carbons in (1) and (2) are: