BITSAT 2025 Question Paper June 25 Shift 1 (Available): Download Solutions with Answer Key

Educational Content Expert | Updated on - Jun 25, 2025

The BITSAT 2025 Exam was conducted on June 25^th 2025 Shift 1 from 9:00 A.M. to 12:00 P.M. in a CBT Mode at various exam centres in India.

The exam tests candidates based on their speed, accuracy, and ability to apply concepts. It consists of 130 multiple-choice questions covering subjects like Physics, Chemistry, English Proficiency, Logical Reasoning, and Mathematics/Biology.

BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT 2025 Question Paper with Answer Key June 25 Shift 1
Download PDF	Check Solutions

Question 1:

A ball is thrown vertically upward with a speed of 49 m/s. How long will it take to return to the thrower’s hand?

(1) 5 s
(2) 7 s
(3) 10 s
(4) 14 s

View Solution

Question 2:

The escape velocity from the surface of a planet is $v_e$. What will be the escape velocity from a planet whose mass and radius are twice that of the original planet?

(1) $v_e$
(2) $2v_e$
(3) $\sqrt{2}v_e$
(4) $4v_e$

View Solution

Question 3:

Which of the following compounds will give a positive Iodoform test?

(1) Ethanol
(2) Propanol
(3) Methanol
(4) Methanal

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Question 4:

Which of the following is not a colligative property?

(1) Osmotic pressure
(2) Depression of freezing point
(3) Elevation of boiling point
(4) Refractive index

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Question 5:

If the roots of the quadratic equation $ ax^2 + bx + c = 0 $ are real and equal, then:

(1) $ b^2 - 4ac < 0 $
(2) $ b^2 - 4ac = 0 $
(3) $ b^2 - 4ac > 0 $
(4) $ a + b + c = 0 $

View Solution

Question 6:

Let $ A = \begin{bmatrix} 2 & 0
0 & 3 \end{bmatrix} $. The determinant of $ A^3 $ is:

(1) 216
(2) 27
(3) 8
(4) 1

View Solution

Question 7:

Choose the correct word to complete the sentence:
“She was so tired that she could ......... keep her eyes open.”

(1) hardly
(2) hard
(3) barely
(4) clearly

View Solution

Question 8:

Statement: All flowers are beautiful. Some beautiful things are fragile.
Conclusion I: Some flowers are fragile.
Conclusion II: All beautiful things are flowers.

(1) Only I follows
(2) Only II follows
(3) Both follow
(4) Neither follows

View Solution

Question 9:

Which number comes next in the series?
3, 6, 11, 18, 27, ?

(1) 36
(2) 38
(3) 40
(4) 48

View Solution

BITSAT 2025 Expected Cutoff

The BITSAT cutoff is the minimum score a candidate needs to get into different programs at BITS Pilani, Goa, and Hyderabad.

This cutoff changes every year and is influenced by several factors, including the number of applicants, seats available, the exam's difficulty level, and how well candidates perform.

Program	Pilani Campus (Expected)	Goa Campus (Expected)	Hyderabad Campus (Expected)
B.E. Computer Science	375 – 385	345 – 355	335 – 345
B.E. Electrical & Electronics	335 – 345	300 – 310	295 – 305
B.E. Mechanical	305 – 315	280 – 290	275 – 285
B.E. Chemical	290 – 300	265 – 275	260 – 270
B.E. Electronics & Instrumentation	325 – 335	295 – 305	285 – 295
M.Sc. Economics	315 – 325	280 – 290	270 – 280
M.Sc. Mathematics	300 – 310	270 – 280	265 – 275
M.Sc. Biological Sciences	270 – 280	240 – 250	235 – 245

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BITSAT Questions

1.
Let $ A = \begin{bmatrix} 2 & 0 \\ 0 & 3 \end{bmatrix} $. The determinant of $ A^3 $ is:

View Solution

2.
Calculate the electric field at a point due to a uniformly charged spherical shell.

$ \frac{Q}{4 \pi \epsilon_0 r^2} $
$ 0 $
$ \frac{Q}{4 \pi \epsilon_0 r} $
$ \frac{Q}{8 \pi \epsilon_0 r^2} $

View Solution

3.
Evaluate the integral: $$ \int_0^{\pi/4} \frac{\ln(1 + \tan x)}{\cos x \sin x} \, dx $$

$ \frac{\pi}{4} \ln 2 $
$ \frac{\pi}{8} \ln 2 $
$ \ln 2 $
$ \frac{1}{2} \ln 2 $

View Solution

4.
What is the dot product of the vectors $ \mathbf{a} = (2, 3, 1) $ and $ \mathbf{b} = (1, -1, 4) $?

View Solution

5.
The electric field at a point on the axis of a uniformly charged ring of radius R at a distance x from its center is given by: \[ E = \frac{1}{4\pi\epsilon_0} \cdot \frac{2\pi kQx}{(x^2 + R^2)^{3/2}}. \] If x = 2R, what is the magnitude of the electric field?

$ \frac{kQ}{R^2} $
$ \frac{2kQ}{R^2} $
$ \frac{3kQ}{R^2} $
$ \frac{kQ}{2R^2} $

View Solution

6.
A bag contains 5 red, 3 blue, and 2 green balls. If two balls are drawn at random without replacement, what is the probability that both are red?

$ \frac{1}{2} $
$ \frac{1}{3} $
$ \frac{5}{9} $
$ \frac{1}{6} $

View Solution

Categories	State
General	3400
Women	2900
Others	7000

BITSAT 2025 Question Paper June 25 Shift 1 (Available): Download Solutions with Answer Key

BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT 2025 Expected Cutoff

BITSAT Topper Strategy on How to Score Good in BITSAT

BITSAT Questions

1.
Let \( A = \begin{bmatrix} 2 & 0 \\ 0 & 3 \end{bmatrix} \). The determinant of \( A^3 \) is:

2.
Calculate the electric field at a point due to a uniformly charged spherical shell.

3.
Evaluate the integral: $$ \int_0^{\pi/4} \frac{\ln(1 + \tan x)}{\cos x \sin x} \, dx $$

4.
What is the dot product of the vectors \( \mathbf{a} = (2, 3, 1) \) and \( \mathbf{b} = (1, -1, 4) \)?

5.
The electric field at a point on the axis of a uniformly charged ring of radius R at a distance x from its center is given by: \[ E = \frac{1}{4\pi\epsilon_0} \cdot \frac{2\pi kQx}{(x^2 + R^2)^{3/2}}. \] If x = 2R, what is the magnitude of the electric field?

6.
A bag contains 5 red, 3 blue, and 2 green balls. If two balls are drawn at random without replacement, what is the probability that both are red?

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BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT 2025 Expected Cutoff

BITSAT Topper Strategy on How to Score Good in BITSAT

BITSAT Questions

1.Let \( A = \begin{bmatrix} 2 & 0 \\ 0 & 3 \end{bmatrix} \). The determinant of \( A^3 \) is:

2.Calculate the electric field at a point due to a uniformly charged spherical shell.

3.Evaluate the integral: $$ \int_0^{\pi/4} \frac{\ln(1 + \tan x)}{\cos x \sin x} \, dx $$

4.What is the dot product of the vectors \( \mathbf{a} = (2, 3, 1) \) and \( \mathbf{b} = (1, -1, 4) \)?

5.The electric field at a point on the axis of a uniformly charged ring of radius R at a distance x from its center is given by: \[ E = \frac{1}{4\pi\epsilon_0} \cdot \frac{2\pi kQx}{(x^2 + R^2)^{3/2}}. \] If x = 2R, what is the magnitude of the electric field?

6.A bag contains 5 red, 3 blue, and 2 green balls. If two balls are drawn at random without replacement, what is the probability that both are red?

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Structure based on different categories

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1.
Let \( A = \begin{bmatrix} 2 & 0 \\ 0 & 3 \end{bmatrix} \). The determinant of \( A^3 \) is:

2.
Calculate the electric field at a point due to a uniformly charged spherical shell.

3.
Evaluate the integral: $$ \int_0^{\pi/4} \frac{\ln(1 + \tan x)}{\cos x \sin x} \, dx $$

4.
What is the dot product of the vectors \( \mathbf{a} = (2, 3, 1) \) and \( \mathbf{b} = (1, -1, 4) \)?

5.
The electric field at a point on the axis of a uniformly charged ring of radius R at a distance x from its center is given by: \[ E = \frac{1}{4\pi\epsilon_0} \cdot \frac{2\pi kQx}{(x^2 + R^2)^{3/2}}. \] If x = 2R, what is the magnitude of the electric field?

6.
A bag contains 5 red, 3 blue, and 2 green balls. If two balls are drawn at random without replacement, what is the probability that both are red?