BITSAT 2025 Question Paper June 24 Shift 2 (Available): Download Solutions with Answer Key

Shivam Yadav's profile photo

Shivam Yadav

Educational Content Expert | Updated 3+ months ago

The BITSAT 2025 Exam was conducted on 24th June 2025, from 2:00 P.M. to 5:00 P.M. in CBT Mode at more than 74 exam centres across the country.

The BITSAT 2025 Exam is conducted online and consists of 130 MCQs, and candidates are given 3 hours to attempt the exam with each correct answer giving +3 marks and incorrect answers giving -1 marks.

BITSAT 2025 Question Paper with Answer Key PDF – Memory Based

BITSAT 2025 Question Paper with Answer Key June 24 Shift 2
Download PDF Check Solutions
BITSAT Question Paper 2025

Question 1:

A block of mass 5 kg is placed on a frictionless surface and a force of 20 N is applied horizontally. What is the acceleration of the block?

  • (1) 4 m/s\(^2\)
  • (2) 2 m/s\(^2\)
  • (3) 5 m/s\(^2\)
  • (4) 10 m/s\(^2\)

Question 2:

What is the pH of a 0.01 M solution of HCl?

  • (1) 1
  • (2) 2
  • (3) 3
  • (4) 4

Question 3:

Find the derivative of \( y = \sin(x^2) \) with respect to \( x \).

  • (1) \( \cos(x^2) \)
  • (2) \( 2x \cos(x^2) \)
  • (3) \( \sin(x^2) \cdot 2x \)
  • (4) \( \cos(x^2) \cdot x \)

Question 4:

The equivalent resistance between points A and B in a circuit with two resistors of 6 \(\Omega\) each connected in parallel is:

  • (1) 12 \(\Omega\)
  • (2) 6 \(\Omega\)
  • (3) 3 \(\Omega\)
  • (4) 4 \(\Omega\)

Question 5:

What is the IUPAC name of CH\(_3\)CH(OH)CH\(_3\)?

  • (1) Propan-1-ol
  • (2) Propan-2-ol
  • (3) Ethanol
  • (4) Butan-2-ol

Question 6:

A simple pendulum has a time period of 2 s on Earth’s surface. What is its time period at a height equal to the Earth’s radius (R)? (Acceleration due to gravity at height h is \( g_h = \frac{g}{(1 + h/R)^2} \)).

  • (1) 2 s
  • (2) 2\(\sqrt{2}\) s
  • (3) 4 s
  • (4) \(\sqrt{2}\) s

Question 7:

Solve for \( x \): \( \log_{10}(x^2) = 2 \).

  • (1) 10
  • (2) 100
  • (3) \(\pm 10\)
  • (4) \(\pm 100\)

Question 8:

Choose the word most opposite in meaning to “Candid”:

  • (1) Honest
  • (2) Deceptive
  • (3) Frank
  • (4) Sincere

Question 9:

In a certain code, “CAT” is written as “DBU.” How is “DOG” written in that code?

  • (1) EPH
  • (2) FQI
  • (3) EQH
  • (4) FPH

Question 10:

The work done by a gas during an isothermal expansion from 2 L to 4 L at a constant temperature, with pressure initially at 2 atm, is: (Use \( R = 8.314 \, J/mol·K \), \( T = 300 \, K \)).

  • (1) 281 J
  • (2) 831.4 J
  • (3) 1247.1 J
  • (4) 1662.8 J

BITSAT 2025 Exam Pattern

BITSAT 2025 is conducted in a CBT Mode for admission in B.E., B.Pharm & M.Sc in BITS Pilani campuses.

The BITSAT consists of 130 MCQs, to be solved in 3 hours with 12 bonus questions.

Component Details
Mode of Exam Computer-Based Test (CBT)
Duration 3 Hours (180 Minutes)
Total Questions 130 MCQs + 12 Bonus Questions (if all 130 are attempted)
Total Marks 390 (excluding bonus questions)
Marking Scheme +3 for each correct answer, -1 for each incorrect answer
Section-wise Distribution
  • Physics – 30
  • Chemistry – 30
  • English Proficiency – 10
  • Logical Reasoning – 20
  • Mathematics/Biology – 40
Bonus Questions 12 Optional Questions (4 each from Physics, Chemistry, Maths/Biology)
Question Type Multiple Choice Questions (MCQs)
Language of Paper English

BITSAT Topper Strategy on How to Score Good in BITSAT

BITSAT Questions

  • 1.
    An ideal gas expands from 2 L to 6 L at a constant temperature of 300 K. Calculate the work done by the gas if pressure remains constant at 2 atm. (1 atm = $1.013 \times 10^5$ Pa)

      • 810.4
      • 820
      • 820.5
      • 795.5

    • 2.
      In an isobaric process, 200 J of heat is supplied to a gas. The gas does 50 J of work. What is the change in internal energy?

        • 150 J
        • 250 J
        • 100 J
        • 200 J

      • 3.
        A projectile is fired with a velocity $u$ making an angle $\theta $ with the horizontal. What is the magnitude of change in velocity when it is at the highest point -

          • $u \cos \theta$
          • $u$
          • $u \sin \theta$
          • $u \cos \theta - u $

        • 4.
          At what point of a projectile motion, acceleration and velocity are perpendicular to each other ?

            • At the point of projection
            • At the point of drop
            • At the top most point
            • Anywhere in between the point of projection and top most point

          • 5.
            A projectile is launched with an initial velocity of \( 20 \, \text{m/s} \) at an angle of \( 30^\circ \) with the horizontal. What is the maximum height reached by the projectile? (Take \( g = 10 \, \text{m/s}^2 \))

              • \( 5 \, \text{m} \)
              • \( 10 \, \text{m} \)
              • \( 15 \, \text{m} \)
              • \( 20 \, \text{m} \)

            • 6.
              A particle of mass ' $m$ ' is projected with a velocity $v$ making an angle of $30^{\circ}$ with the horizontal. The magnitude of angular momentum of the projectile about the point of projection when the particle is at its maximum height ' $h$ ' is

                • $\frac{\sqrt{3}}{2} \frac{mv^{2}}{g}$
                • zero
                • $\frac{mv^{3}}{\sqrt{2g}}$
                • $\frac{\sqrt{3}}{16} \frac{mg^{3}}{g}$

              Fees Structure

              Structure based on different categories

              CategoriesState
              General3400
              Women2900
              Others7000

              Note: Candidates opting Dubai as exam centre, will have to pay INR 7000 as the application fee.

              In case of any inaccuracy, Notify Us! 

              Comments


              No Comments To Show