NCERT Solutions for class 11 Physics Chapter 4: Motion in a plane

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The NCERT Solutions for Class 11 Physics Chapter 4 Motion in a plane are provided in the article below. The motion of a body can be referred to as its change in position depending on its surroundings in a given time interval. The motion of any object which has some mass can be measured in distance, displacement, speed and velocity, acceleration, and time.

Class 11 Physics Chapter 4 Motion in a Plane belongs to Unit 2 Kinematics which has a weightage of 23 marks along with Unit 1 Physical World and Measurement and Unit 3 Laws of Motion. NCERT Solutions for Chapter 4 Physics Class 11 deals with the concept of scalars and vectors, uniform circular motion, and relative velocity in two dimensions.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 4

NCERT Solutions for Class 11 Physics Chapter 4

Class 11 Physics Chapter 4 – Concepts Covered

Motion in a plane is known as motion in two dimensions. For example, projectile motion, circular motion etc.
Scalar Quantities are the physical quantities that are specified by their magnitude or size alone.

Examples of Scalar Quantities – Length, mass, density, speed, work, etc

Vector Quantities are the physical quantities that are characterised by both magnitude and direction.

Example of Vector Quantities – Velocity, displacement, acceleration, force, momentum, torque etc.

A unit vector is a vector with a unit magnitude that points in a particular direction. It is used to only specify the direction.

It can be represented as $\widehat{A} = { \overrightarrow{A} \over |\overrightarrow{A}|}$

Parallelogram Law of Vector Addition: If $\overrightarrow{A}$and $\overrightarrow{B}$ are the two adjacent sides of a parallelogram, inclined at an angle $\theta$, then the magnitude of resultant vector is determined.

$R = \sqrt{A^2 + B^2 +2ABcos\theta}$

The projectile is an initial inclined velocity which subsequently follows a path determined by the gravitational force that acts on it and by the frictional resistance of the air.
The path followed by a projectile is known as its trajectory.

Class 11 Physics Chapter 4 Related Guides –

Resolution of vectors	Displacement Vector	Centripetal Acceleration
Tangential Acceleration Formula	Resultant of Vector Formula	Relation between torque and speed
Horizontal Motion	Velocity Vectors	Trajectory Formula

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Physics Formula	Physics Study Notes
Difference between in Physics	Derivations in Physics	SI Units in Physics
Relation between articles in Physics	Physics Constants	Class 11 Physics Notes

CBSE CLASS XII Related Questions

1.
Find the ratio $\dfrac{\lambda_\alpha}{\lambda_p}$ of the de Broglie wavelength $\lambda_\alpha$ associated with an alpha particle to the de Broglie wavelength $\lambda_p$ associated with a proton if both are moving with the same velocity.
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2.
A square loop of side 0.50 m is placed in a uniform magnetic field of 0.4 T perpendicular to the plane of the loop. The loop is rotated through an angle of $60^\circ$ in 0.2 s. The value of emf induced in the loop will be:
- 5 V
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- 2.5 V
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(I) The real image of an object placed between $f$ and $2f$ from a convex lens can be seen on a screen placed at the image location. If the screen is removed, is the image still there? Explain.
(II) Plane and convex mirrors produce virtual images of objects. Can they produce real images under some circumstances? Explain.
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4.
Consider a cylindrical conductor of length $l$ and area of cross-section $A$. Current $I$ is maintained in the conductor and electrons drift with velocity $\vec{v}_d$ ($|\vec{v}_d| = \frac{e|\vec{E}|}{m}\tau$), (where symbols have their usual meanings). Show that the conductivity $\sigma$ of the material of the conductor is given by
$$\sigma = \frac{ne^2}{m}\tau.$$
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6.
Two point charges -Q and Q are located at points (d, 0) and (0, d) respectively, in x-y plane. The electric field E at the origin will be:
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