NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

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NCERT Solutions for Class 11 Physics Chapter 10 Mechanical Properties of Fluids are given in this article. Fluids are substances that can flow e.g., liquids and gases. It does not possess definite shape. When an object is submerged in a liquid at rest, the fluid exerts a force on its surface normally.

Class 11 Physics Chapter 10 Mechanical Properties of Fluids belongs to Unit 7 Properties of Bulk Matter which has a weightage of 20 marks in the Class 11 Examination along with Unit 8 and Unit 9. NCERT Solutions for Mechanical Properties of Fluids covers concepts of Pascal’s law, Archimedes Principle, and Viscosity.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 10

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

Pressure is the thrust experienced per unit area of the surface of a liquid that is at rest.

The pressure at any point in the liquid depends on the depth (h) below the surface, density of liquid and acceleration due to gravity.

Pascal’s Law states that the pressure applied to an enclosed liquid is transmitted to every portion of the liquid and walls of the containing vessel.

\(P = {F \over A}\)

Archimedes Principle: When a body is either partially or fully immersed in a liquid, it loses some of its weight. The loss in the weight of the body is equal to the weight of the liquid that is displaced by the immersed part.

The upward force that’s exerted by the liquid displaced when a body is immersed is known as buoyancy.

The energy possessed by a liquid by the virtue of its pressure is known as pressure energy.

Pressure energy of liquid in volume dV = PdV

Bernoulli’s Theorem: For an incompressible, irrotational, and non-viscous liquid with a streamlined flow, the sum of the kinetic energy, pressure energy, and potential energy per unit mass is a constant

\({P \over \rho} + {v^2 \over 2}+gh=constant\)

Class 11 Physics Chapter 10 Related Guides –

Hydraulic Machines	Bernoulli’s Principle	Venturimeter
Stokes’ Law	Surface Tension	Surface Energy
Barometer	Reynolds Number	Density
Buoyant Force	Fluid Friction	Fluid Pressure
Hydrostatic Paradox	Terminal Velocity Formula	Dynamic Lift

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Difference between in Physics	Relation between articles in Physics
Physics Formula	Physics Study Notes	SI Units in Physics
Derivations in Physics	Physics Constants	Class 11 Physics Notes

CBSE CLASS XII Related Questions

1.
Consider a cylindrical conductor of length \( l \) and area of cross-section \( A \). Current \( I \) is maintained in the conductor and electrons drift with velocity \( \vec{v}_d \, (|\vec{v}_d| = \frac{eE}{m} \tau) \), where symbols have their usual meanings. Show that the conductivity of the material of the conductor is given by \[ \sigma = \frac{n e^2 \tau}{m}. \]
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2.
The electric potential (V ) and electric field (⃗ E) are closely related concepts in electrostatics. The electric field is a vector quantity that represents the
- Production of AC is economical.
- AC can be easily and efficiently converted from one voltage to another.
- AC can be transmitted economically over long distances.
- AC is less dangerous.
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3.
In a Young's double-slit experiment, two waves each of intensity I superpose each other and produce an interference pattern. Prove that the resultant intensities at maxima and minima are 4I and zero respectively.
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4.
Four long straight thin wires are held vertically at the corners A, B, C and D of a square of side \( a \), kept on a table and carry equal current \( I \). The wire at A carries current in upward direction whereas the current in the remaining wires flows in downward direction. The net magnetic field at the centre of the square will have the magnitude:
- \( \dfrac{\mu_0 I}{\pi a} \) and directed along OC
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- \( \dfrac{2\mu_0 I}{\pi a} \) and directed along OA
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5.
A circular coil of 100 turns and radius \( \left(\frac{10}{\sqrt{\pi}}\right) \, \text{cm}\) carrying current of \( 5.0 \, \text{A} \) is suspended vertically in a uniform horizontal magnetic field of \( 2.0 \, \text{T} \). The field makes an angle \( 30^\circ \) with the normal to the coil. Calculate:
the magnetic dipole moment of the coil, and
the magnitude of the counter torque that must be applied to prevent the coil from turning.
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6.
The figure represents the variation of the electric potential \( V \) at a point in a region of space as a function of its position along the x-axis. A charged particle will experience the maximum force at:
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