NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

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NCERT Solutions for Class 11 Physics Chapter 10 Mechanical Properties of Fluids are given in this article. Fluids are substances that can flow e.g., liquids and gases. It does not possess definite shape. When an object is submerged in a liquid at rest, the fluid exerts a force on its surface normally.

Class 11 Physics Chapter 10 Mechanical Properties of Fluids belongs to Unit 7 Properties of Bulk Matter which has a weightage of 20 marks in the Class 11 Examination along with Unit 8 and Unit 9. NCERT Solutions for Mechanical Properties of Fluids covers concepts of Pascal’s law, Archimedes Principle, and Viscosity.

Download PDF: NCERT Solutions for Class 11 Physics Chapter 10

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

Pressure is the thrust experienced per unit area of the surface of a liquid that is at rest.

The pressure at any point in the liquid depends on the depth (h) below the surface, density of liquid and acceleration due to gravity.

Pascal’s Law states that the pressure applied to an enclosed liquid is transmitted to every portion of the liquid and walls of the containing vessel.

\(P = {F \over A}\)

Archimedes Principle: When a body is either partially or fully immersed in a liquid, it loses some of its weight. The loss in the weight of the body is equal to the weight of the liquid that is displaced by the immersed part.

The upward force that’s exerted by the liquid displaced when a body is immersed is known as buoyancy.

The energy possessed by a liquid by the virtue of its pressure is known as pressure energy.

Pressure energy of liquid in volume dV = PdV

Bernoulli’s Theorem: For an incompressible, irrotational, and non-viscous liquid with a streamlined flow, the sum of the kinetic energy, pressure energy, and potential energy per unit mass is a constant

\({P \over \rho} + {v^2 \over 2}+gh=constant\)

Class 11 Physics Chapter 10 Related Guides –

Hydraulic Machines	Bernoulli’s Principle	Venturimeter
Stokes’ Law	Surface Tension	Surface Energy
Barometer	Reynolds Number	Density
Buoyant Force	Fluid Friction	Fluid Pressure
Hydrostatic Paradox	Terminal Velocity Formula	Dynamic Lift

Class 11 Physics Study Guides:

NCERT Solutions for Class 11 Physics	Difference between in Physics	Relation between articles in Physics
Physics Formula	Physics Study Notes	SI Units in Physics
Derivations in Physics	Physics Constants	Class 11 Physics Notes

CBSE CLASS XII Related Questions

1.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:
- \( \frac{q}{4 \pi \epsilon_0 l^2} \) pointing along MA
- \( \frac{q}{\pi \epsilon_0 l^2} \) pointing along AM
- \( \frac{q}{2 \pi \epsilon_0 l^2} \) pointing along AM
- Zero
View Solution
2.
Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))
View Solution
3.
Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).
View Solution
4.
A long solenoid of length \( L \) and radius \( r_1 \) having \( N_1 \) turns is surrounded symmetrically by a coil of radius \( r_2 \, (r_2>r_1) \) having \( N_2 \) turns (\( N_2 \ll N_1 \)) around its mid-point. Derive an expression for the mutual inductance of solenoid and coil. Is \( M_{12} = M_{21} \) valid in this case?
View Solution
5.
Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]
View Solution
6.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.
View Solution

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NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

CBSE CLASS XII Related Questions

1.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

2.
Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))

3.
Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

5.
Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]

6.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

Similar Physics Concepts

Comments

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NCERT Solutions For Class 11 Physics Chapter 10: Mechanical Properties of Fluids

NCERT Solutions for Class 11 Physics Chapter 10

Class 11 Physics Chapter 10 – Concepts Covered

CBSE CLASS XII Related Questions

1.The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

2.Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))

3.Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

5.Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]

6.Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.

Similar Physics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
The figure shows three point charges kept at the vertices of triangle ABC. The net electric field, due to this system of charges, at the midpoint M of base BC will be:

2.
Suppose a pure Si crystal has \( 5 \times 10^{28} \) atoms per \( \text{m}^3 \). It is doped with \( 5 \times 10^{22} \) atoms per \( \text{m}^3 \) of Arsenic. Calculate majority and minority carrier concentration in the doped silicon. (Given: \( n_i = 1.5 \times 10^{16} \, \text{m}^{-3} \))

3.
Write the expression for the magnetic field due to a current element in vector form. Consider a 1 cm segment of a wire, centered at the origin, carrying a current of 10 A in positive x-direction. Calculate the magnetic field \( \mathbf{B} \) at a point \( (1 \, \text{m}, 1 \, \text{m}, 0) \).

5.
Two thin lenses of focal length \( f_1 \) and \( f_2 \) are placed in contact with each other coaxially. Prove that the focal length \( f \) of the combination is given by \[ f = \frac{f_1 f_2}{f_1 + f_2}. \]

6.
Photoemission of electrons occurs from a metal (\( \phi_0 = 1.96 \, \text{eV} \)) when light of frequency \( 6.4 \times 10^{14} \, \text{Hz} \) is incident on it. Calculate: Energy of a photon in the incident light, The maximum kinetic energy of the emitted electrons, and The stopping potential.