NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.1

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NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Exercise 8.1 is provided in this article. Class 10 Maths Chapter 8 Introduction to Trigonometry covers important concepts like trigonometric ratios, trigonometry table, trigonometric identities and formulas. Chapter 8 exercise 8.1 includes questions based on trigonometric ratios.

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Check out NCERT solutions of other exercises of class 10 maths chapter 8 Introduction to Trigonometry:

Class 10 Chapter 8 Introduction to Trigonometry Related Links:

Trigonometry Table	Trigonometric Functions	Value of Cos 60
Some Applications of Trigonometry	Introduction to Trigonometry Important Formula	Heights and Distances
Angle of Depression	Introduction to Trigonometry Revision Notes	Sin 30 Degrees

CBSE Class 10 Maths Study Guides:

Math Formula	Math Study Notes	Trigonometry
Math MCQs	NCERT Solutions for Class 10 Maths	Difference between in Maths
Arithmetic	Mensuration	Calculus
Class 10 Notes	Number System	Geometry

CBSE X Related Questions

1.
Find the H.C.F. and L.C.M. of 408 and 312.
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2.
Find the missing frequencies p and q in the following frequency distribution, when sum of frequencies is 40 and mean is 19 :
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3.
There are many varieties of mushrooms available in the world. One such mushroom ‘Amanita muscaria’ has a upper part which is like red cap (hemispherical) and lower part is like white stem (cylindrical). The hemispherical cap’s radius = 3 cm and cylindrical stem is 2 cm high with diameter 1.4 cm. Considering mushroom a solid object, answer the following questions:

36(i) What is the total height of a mushroom ?
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4.
If \( 2 \sin A = 1 \), then the value of \( \tan A + \cot A \) is :
- \( \sqrt{3} \)
- \( \frac{4}{\sqrt{3}} \)
- \( \frac{\sqrt{3}}{2} \)
- \( 1 \)
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5.
PQ is tangent to the circle with centre O such that OP = 2OQ. m\(\angle\)OPQ is
- 15\(^\circ\)
- 60\(^\circ\)
- 45\(^\circ\)
- 30\(^\circ\)
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6.
In the given figure, two triangles ABC and PQR are shown such that \(\angle A = \angle P\) and \(\angle C = \angle R\). If \(AD \perp BC\) and \(PS \perp QR\), then prove that (i) \(\Delta ADB \sim \Delta PSQ\) (ii) \(AD \times QS = BD \times PS\).
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