NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.1

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NCERT Solutions for Class 10 Maths Chapter 7 Coordinate Geometry Exercise 7.1 is given in this article. Class 10 Maths Chapter 7 is an important chapter and its Exercise 7.1 has about 10 questions related to the distance formula.

Read More: Coordinate Geometry MCQs

Download PDF: NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.1

Check out the solutions of Class 10 Maths NCERT solutions chapter 7 Coordinate Geometry Exercise 7.1

Check out other exercise solutions of Class 10 Maths Chapter 7

Class 10 Chapter 7 Topics:

Section Formula	Cartesian System	Ordinate
Quadrant	Centroid	Midpoint Formula
Centroid Formula	Centroid of a Triangle	Point of Intersection Formula

CBSE Class 10 Maths Study Guides:

Math Formula	Math Study Notes	Trigonometry
Math MCQs	NCERT Solutions for Class 10 Maths	Difference between in Maths
Arithmetic	Mensuration	Calculus
Class 10 Notes	Number System	Geometry

CBSE X Related Questions

1.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.
View Solution
2.
The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :
- \(\frac{35}{4}^\circ\)
- \(\frac{35}{2}^\circ\)
- 35°
- 70°
View Solution
3.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :
- \( 130^\circ \)
- \( 50^\circ \)
- \( 120^\circ \)
- \( 90^\circ \)
View Solution
4.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)
View Solution
5.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.
View Solution
6.
Find the H.C.F. and L.C.M. of 1530 and 2040.
View Solution

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NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.1

CBSE X Related Questions

1.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

2.
The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :

3.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

4.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

5.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

6.
Find the H.C.F. and L.C.M. of 1530 and 2040.

Similar Mathematics Concepts

Comments

dOGVmW

NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.1

CBSE X Related Questions

1.In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

2.The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :

3.In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

4.Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

5.D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

6.Find the H.C.F. and L.C.M. of 1530 and 2040.

Similar Mathematics Concepts

Comments

dOGVmW

1.
In a class test, the sum of Anamika's marks obtained in Maths and Science is 30. Had she got 2 marks more in Maths and 3 marks less in Science, the product of the marks would have been 210. Find the marks she got in the two subjects.

2.
The hour hand of a clock is 7 cm long. The angle swept by it between 7:00 a.m. and 8:10 a.m. is :

3.
In the given figure, PA and PB are tangents to a circle centred at O. If \( \angle AOB = 130^\circ \), then \( \angle APB \) is equal to :

4.
Prove that : \( \frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\text{cosec}^3 \theta}{\text{cosec}^2 \theta - 1} = \sec \theta \cdot \text{cosec} \theta (\sec \theta + \text{cosec} \theta) \)

5.
D is the mid-point of side BC of \(\triangle ABC\). CE and BF intersect at O, a point on AD. AD is produced to G such that \(OD = DG\). Prove that OBGC is a parallelogram.

6.
Find the H.C.F. and L.C.M. of 1530 and 2040.