NCERT Solutions for Class 9 Maths Chapter 3: Coordinate Geometry

Collegedunia Team logo

Collegedunia Team

Content Curator

The NCERT Solutions for class 9 Maths Chapter 3 Coordinate Geometry have been provided in the article below. Coordinate Geometry deals with geometrical problems solved using coordinate systems and points.

Class 9 Maths Chapter 3 Coodinate Geometry belongs to Unit 3 Coordinate Geometry having a weightage of 04 in the Class 9 Maths Examination. NCERT Solutions for Class 9 Maths for Chapter 3 cover the following important concepts: 

Download: NCERT Solutions for Class 9 Maths Chapter 3 pdf


NCERT Solutions for Class 9 Maths Chapter 3

The Chapter 3 Class 9 Maths are given below:

NCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT SolutionsNCERT Solutions


Important Topics in Class 9 Maths Chapter 3 Coordinate Geometry

Important Topics in Class 9 Maths Chapter 3 Coordinate Geometry are elaborated below: 

  • Distance Formula of Coordinate Geometry

Distance formula of coordinate geometry, derived from the Pythagoras Theorem, is used to determime the distance between any 2 given points. These points are usually located on an x-y coordinate plane. Distance Formula of coordinate geometry can be written as, AB = √[(x2-x1)²+(y2-y1)²]

Example: Consider coordinate A (-4,0) and B (0,3). With the given coordinates, determine the distance between these two points.

Solution: Considering the coordinates ofA = (-4,0) = (x1, y1)
And the coordinates of B = (0,3) = (x2,y2)
Now by using Distance Formula, we can get,
AB = √{(x2-x1)²+(y2-y1)²} = √{[0-(-4)]²+ (3-0)²}
= √(4²+3²)} = √(16+9) = √25
= 5 units

  • Section Formula of Coordinate Geometry

Section Formula helps to determine the coordinates of a point that assists division of the line joining two points in a ratio. The equation occurs either internally or externally.

Section Formula of Coordinate Geometry can be classified into two parts:

  1. Internal Section Formula: \(P(x,y) = (\frac{mx_2+nx_1}{m+n} , \frac{my_2+ny_1}{m+n})\)
  2. External Section Formula: \(P(x,y) = (\frac{mx_2-nx_1}{m-n} , \frac{my_2-ny_1}{m-n})\)
  • Ordinate 

Ordinate represents the coordinate values present on the y-axis on a coordinate system. It is the second component of an ordered pair.

Example: What will be the abscissa and ordinate of a point with coordinates (8,12)?

Solution: The coordinates of (8, 12) are:
Abscissa: 12
And, Ordinate: 8

  • Quadrant

Quadrants are the parts that form when two coordinate axes of a plane tend to intersect with one another at an angle of 90 degree. The intersection these two lines experience is called a point of reference. 

Example: Highlight the quadrants where coordinate points (-2,7) take place? 

Solution: (-2,7) falls in the second quadrant. Here, the value of the x axis becomes negative. 

  • Cartesian System

Cartesian System, derived from the number line, is used to label points in a plane. The cartesian form is derived from the number line. It has two perpendicular lines named as X-axis and Y-axis.

Important points to remember in Cartesian System:

  • The point of intersection of both the axes is called the origin. It has coordinates (0, 0).
  • An infinite number of points can be plotted on a cartesian coordinate plane.
  • Points that fall on any of the number lines don’t belong to any quadrant.

NCERT Solutions for Class 9 Maths Chapter 3 Exercises:

The detailed solutions for all the NCERT Solutions for Coordinate Geometry under different exercises are:

Also Read:

Check out:

CBSE X Related Questions

  • 1.
    Determine the ratio in which the line 3x + y - 9 = 0 divides the line segment joining the points (1, 3) and (2, 5). Find the point of intersection.


      • 2.
        Prove that : (sin A + sec A)\(^2\) + (cos A + cosec A)\(^2\) = (1 + sec A cosec A)\(^2\)


          • 3.
            Find the mean and the mode of the following frequency distribution :


              • 4.
                A tower stands vertically on the ground. A man standing at the top of the tower observes his friend at an angle of depression of 30\(^{\circ}\), who is approaching the foot of the tower with a uniform speed. 30 seconds later, the angle of depression changes to 60\(^{\circ}\). Find the time taken by his friend to reach the foot of the tower from this point.


                  • 5.
                    If sin \(\theta\) + cos \(\theta\) = \(\sqrt{3}\), then prove that tan \(\theta\) + cot \(\theta\) = 1.


                      • 6.
                        The angle of elevation of the top of a building from a point A, on the ground, is 30\(^{\circ}\). On moving a distance of 24 m towards its base to the point B, the angle of elevation changes to 60\(^{\circ}\). Find the height of the building and distance of point A from the base of the building. (Take \(\sqrt{3}\) = 1.73)

                          Comments


                          No Comments To Show