NCERT Solutions for class 10 Maths chapter 7: Coordinate Geometry

Content Curator

The NCERT solutions for class 10 maths chapter 7 Coordinate Geometry are provided in the article to help students prepare for their class 10 maths board exam. Coordinate Geometry is a branch of geometry that helps in determining the position of points in a plane with the help of ordered pair of numbers called coordinates.

Chapter 7 Coordinate Geometry is a part of Unit 3 Coordinate Geometry as per the class 10 syllabus 2022-23. This chapter carries a weightage of 06 marks in cbse class 10 maths board exam. The important topics from this chapter includes distance formula, section formula and area of a triangle.

Download: NCERT Solutions for Class 10 Maths Chapter 7 pdf

NCERT Solutions for Class 10 Maths Chapter 7

Class 10 Maths Chapter 7 Coordinate Geometry: Important Topics

The important topics of chapter 7 coodinate geometry are given below:

Distance Formula – In coordinate geometry, distance formula is used to find the distance between two points in a coordinate plane. It is derived with the help of Pythagoras theorem.

Distance formula, for two points say P and Q with coordinates (x₁,y₁) and (x₂,y₂) respectively, is given by;

\(PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\)

Section Formula – Section formula is used to find the coordinates of the point that divides a line segment into two ratios.

Section formula, for a point P dividing a line segment AB with A (x₁,y₁) and B (x₂,y₂) in the ratio m₁:m₂ , is given by;

\(P(x,y) = (\frac{m_1x_2 + m_2x_1}{m_1 + m_2} , \frac{m_1y_2 + m_2y_1}{m_1 + m_2})\)

Area of a Triangle – Area of a Triangle can be calculated when coordinates of the vertices of the triangle are given.

The formula for calculating area of a triangle ABC with vertices A (x₁,y₁), B (x₂,y₂) and C (x₃,y₃) is given by;

\(Area = \frac{1}{2} [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]\)

NCERT Solutions for Class 10 Maths Chapter 7 Exercises:

The NCERTsolutions of all the exercises of class 10 maths chapter 7 Coordinate Geometry are given below:

Read Also:

Two-Dimensional Coordinate Geometry	Coordinate Geometry MCQs	Coordinate Geometry Important Questions
Quadrant	Centroid	Ordinate
Triangles	Polar Coordinates	Geometry Formula

Study Materials for Class 10 Maths:

Algebra	Mensuration Formula	Number System
Geometry	Important Formulas in Maths	Class 10 Maths Notes

CBSE X Related Questions

1.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.
View Solution
2.
Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)
View Solution
3.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is
- \(2\pi r^3\)
- \(3\pi r^3\)
- \(5\pi r^3\)
- \(4\pi r^3\)
View Solution
4.
A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))
- \(314 \sqrt{2}\) \(\text{cm}^{2}\)
- \(314\) \(\text{cm}^{2}\)
- \(\frac{3140}{3}\) \(\text{cm}^{2}\)
- \(3140 \sqrt{2}\) \(\text{cm}^{2}\)
View Solution
5.
If \(2\tan A = 3\), then value of \(\sec A\) equals
- \(\frac{\sqrt{13}}{2}\)
- \(\frac{\sqrt{13}}{4}\)
- \(\frac{2}{\sqrt{13}}\)
- \(\frac{\sqrt{13}}{2}\)
View Solution
6.
In triangles ABC and PQR, \( \angle A = \angle Q \) and \( \angle B = \angle R \), then \( AB : AC \) is equal to :
- \( PQ : PR \)
- \( PQ : QR \)
- \( QR : QP \)
- \( PR : QR \)
View Solution

View All

Similar Mathematics Concepts

Midpoint Formula: Midpoint Definition, Theorem, Solved Examples

Centroid: Definition, Types, Theorem, Properties, Formulas

NCERT Solutions for Class 9 Maths Chapter 3: Coordinate Geometry

NCERT Solutions for Class 10 Maths: Chapter-wise Solutions and Important Topics

Coordinate Geometry MCQs

Point of Intersection Formula: Gradient & Point Slope

Important MCQs on Coordinate Geometry with Explanation

Perpendicular Distance of a Point from a Plane Formula

Coordinate Geometry: Important Questions

NCERT Solutions for Class 10 Maths Chapter 7 Exercise 7.1

CBSE X Syllabus

Mathematics Preparation Guides

Arithmetic Progressions: Properties, Formulas and Solved Examples

Distance Formula and Derivation of Coordinate Geometry

Probability- A Theoretical Approach: An Overview and Examples

Area of Circle: Area Formula, Derivation with Solved Examples

Mode of Grouped Data

Pythagoras Theorem: Formula, Theorem, Proof and Examples

Nature of Roots of Quadratic Equation

Probability: Concepts, Problems and Solved Examples

Trigonometry: Ratios, Identities & Trigonometric Table

Heights and Distances: Applications in Trigonometry

Real Numbers: Euclid’s Division Lemma, Properties & Sets

Surface Areas and Volumes Revision Notes

Circles: Definition, Properties, Parts, Theorems

Constructions Revision Notes

Pair of Linear Equations In Two Variables Important Questions

Circles Revision Notes: Theorems of Tangent to the Circle

Statistics Important Questions

Mathematics NCERT Solutions

Euclid's Division Lemma: Proof, Finding HCF & Examples

Area of a Sector: Definition, Formulae and Solved Examples

Real Numbers: Definition, Properties and Examples

Events in Probability: Definition, Types, Examples

Relation Between HCF and LCM: Definition, Methods and Formulas

Geometric Probability: Formula, Illustration, Model

Algebra Formula: Important Formulas in Algebra & Solved Examples

Angle of Depression: Definition, Formula and Solved Examples

Cyclic Quadrilateral: Properties, Theorems and Formulas

Polynomial Notation: Types, Remainder Theorem, Linear and Quadratic Equation

NCERT Solutions for class 10 Maths chapter 7: Coordinate Geometry

NCERT Solutions for Class 10 Maths Chapter 7

Class 10 Maths Chapter 7 Coordinate Geometry: Important Topics

NCERT Solutions for Class 10 Maths Chapter 7 Exercises:

CBSE X Related Questions

1.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

2.
Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)

3.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

4.
A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))

5.
If \(2\tan A = 3\), then value of \(\sec A\) equals

6.
In triangles ABC and PQR, \( \angle A = \angle Q \) and \( \angle B = \angle R \), then \( AB : AC \) is equal to :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

NCERT Solutions for class 10 Maths chapter 7: Coordinate Geometry

NCERT Solutions for Class 10 Maths Chapter 7

Class 10 Maths Chapter 7 Coordinate Geometry: Important Topics

NCERT Solutions for Class 10 Maths Chapter 7 Exercises:

CBSE X Related Questions

1.A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

2.Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)

3.Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

4.A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))

5.If \(2\tan A = 3\), then value of \(\sec A\) equals

6.In triangles ABC and PQR, \( \angle A = \angle Q \) and \( \angle B = \angle R \), then \( AB : AC \) is equal to :

Similar Mathematics Concepts

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
A trader has three different types of oils of volume \(870 \text{ l}\), \(812 \text{ l}\) and \(638 \text{ l}\). Find the least number of containers of equal size required to store all the oil without getting mixed.

2.
Prove that: \(\frac{\sec^3 \theta}{\sec^2 \theta - 1} + \frac{\csc^3 \theta}{\csc^2 \theta - 1} = \sec \theta \cdot \csc \theta (\sec \theta + \csc \theta)\)

3.
Three tennis balls are just packed in a cylindrical jar. If radius of each ball is \(r\), volume of air inside the jar is

4.
A conical cavity of maximum volume is carved out from a wooden solid hemisphere of radius 10 cm. Curved surface area of the cavity carved out is (use \(\pi = 3.14\))

5.
If \(2\tan A = 3\), then value of \(\sec A\) equals

6.
In triangles ABC and PQR, \( \angle A = \angle Q \) and \( \angle B = \angle R \), then \( AB : AC \) is equal to :