NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.3 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.3 Solutions are based on the following concepts:

  • Height of the cylinder based on given condition
  • Radius of the resulting sphere
  • Number of cones for a given situation.
  • Number of coins formed by melting a cuboid structured object.

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CBSE X Related Questions

  • 1.
    If \(\alpha, \beta\) are the zeroes of the polynomial \(p(x) = x^2 - 3x - 1\), then find the value of \(\frac{1}{\alpha} + \frac{1}{\beta}\).


      • 2.
        The HCF of 960 and 432 is :

          • 48
          • 54
          • 72
          • 36

        • 3.
          A kite is flying at a height of \(60 \text{ m}\) above the ground level. Ravi, standing at the roof of the house is holding the string straight and observes the angle of elevation of kite as \(30^{\circ}\). From the bottom of the same building, the angle of elevation of kite is \(45^{\circ}\). Find the length of the string and height of roof from the ground. (Use \(\sqrt{3} = 1.73\))


            • 4.
              Assertion (A) : H.C.F. \((36 m^{2}, 18 m) = 18 m\), where \(m\) is a prime number.
              Reason (R) : H.C.F. of two numbers is always less than or equal to the smaller number.

                • Both Assertion (A) and Reason (R) are true and Reason (R) is the correct explanation of the Assertion (A).
                • Both Assertion (A) and Reason (R) are true, but Reason (R) is not the correct explanation of the Assertion (A).
                • Assertion (A) is true, but Reason (R) is false.
                • Assertion (A) is false, but Reason (R) is true.

              • 5.
                \(ABCD\) is a parallelogram such that \(AF = 7 \text{ cm}\), \(FB = 3 \text{ cm}\) and \(EF = 4 \text{ cm}\), length \(FD\) equals

                  • \(\frac{21}{4} \text{ cm}\)
                  • \(\frac{28}{3} \text{ cm}\)
                  • \(\frac{12}{7} \text{ cm}\)
                  • \(5.5 \text{ cm}\)

                • 6.
                  The first term of an AP is $p$ and the common difference is $q$, then its 10th term is :

                    • $q - 9p$
                    • $p - 9q$
                    • $p + 9q$
                    • $2p + 9q$

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