NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.2 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.2 Solutions are based on Volume of Combination of Solids.

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CBSE X Related Questions

  • 1.

    In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.


      • 2.
        The sum of a number and its reciprocal is \(\frac{13}{6}\). Find the number.


          • 3.
            In \(\triangle ABC, DE || BC\). If AE = (2x + 1) cm, EC = 4 cm, AD = (x + 1) cm and DB = 3 cm, then value of x is
             △ABC,DE||BC. If AE = (2x + 1) cm, EC = 4 cm, AD = (x + 1)

              • 1
              • \(\frac{1}{2}\)
              • --1
              • \(\frac{1}{3}\)

            • 4.
              Find the smallest value of $p$ for which the quadratic equation $x^2 - 2(p + 1)x + p^2 = 0$ has real roots. Hence, find the roots of the equation so obtained.


                • 5.
                  Solve the following pair of linear equations by graphical method : \(2x + y = 9\) and \(x - 2y = 2\).


                    • 6.
                      If the mode of some observations is 10 and sum of mean and median is 25, then the mean and median respectively are

                        • 12 and 13
                        • 13 and 12
                        • 10 and 15
                        • 15 and 10

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