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NCERT Solutions for Class 10 Maths Chapter 13 Exercise 13.2 Solutions

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NCERT Solutions for Class 10 Maths Chapter 13 Surface Areas and Volume Exercise 13.2 Solutions are based on Volume of Combination of Solids.

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Read More: NCERT Solutions For Class 10 Maths Chapter 13 Surface Areas and Volume

Exercise Solutions of Class 10 Maths Chapter 13 Surface Areas and Volume

Also check other Exercise Solutions of Class 10 Maths Chapter 13 Surface Areas and Volume

Also Check:

Chapter Related Topics
Surface Areas And Volumes Revision Notes	Area Of Prism	Volume Of A Rectangular Prism Formula
Volume Of A Square Pyramid Formula	Volume Of A Triangular Prism Formula	Surface Area Of A Prism Formula
Surface Area Of A Pyramid Formula	Surface Area Of A Rectangular Prism Formula	Surface Area Of A Square Pyramid Formula
Surface Area of a Cylinder	Area of Hollow Cylinder	Surface Area of a Prism Formula

Also check:

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Class 10 Maths Notes	Permutations and Combinations	Mensuration
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Math Formula	NCERT Solutions for Class 10 Maths	Algebra

CBSE X Related Questions

1.
In a right triangle ABC, right-angled at A, if $\sin B = \dfrac{1}{4}$, then the value of $\sec B$ is
- 4
- $\dfrac{\sqrt{15}}{4}$
- $\sqrt{15}$
- $\dfrac{4}{\sqrt{15}}$
View Solution
2.
On the day of her examination, Riya sharpened her pencil from both ends as shown below.

The diameter of the cylindrical and conical part of the pencil is 4.2 mm. If the height of each conical part is 2.8 mm and the length of the entire pencil is 105.6 mm, find the total surface area of the pencil.
View Solution
3.
From one face of a solid cube of side 14 cm, the largest possible cone is carved out. Find the volume and surface area of the remaining solid.
Use $\pi = \dfrac{22}{7}, \sqrt{5} = 2.2$
View Solution
4.
A peacock sitting on the top of a tree of height 10 m observes a snake moving on the ground. If the snake is $10\sqrt{3}$ m away from the base of the tree, then angle of depression of the snake from the eye of the peacock is
- $60^\circ$
- $45^\circ$
- $30^\circ$
- $90^\circ$
View Solution
5.
Using prime factorisation, find the HCF of 144, 180 and 192.
View Solution
6.
Solve the equation \(4x^2 - 9x + 3 = 0\), using quadratic formula.
View Solution

Similar Mathematics Concepts

Surface Areas and Volumes Revision Notes

Area of Hollow Cylinder: Total Surface Area & Lateral Surface Area

Surface Area of a Cylinder Formula: Definition and Solved Examples

Area of Square: Formula & How to Find Area of Square?

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NCERT Solutions for class 10 Mathematics Chapter 13: Surface Areas and Volumes

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