AP EAPCET 2026 May 18 Shift 1 Engineering Question Paper- Download Solution PDF

AP EAPCET Questions

• 1.

  A thin metal disc of radius \(r\) floats on water surface and bends the surface downwards along the perimeter making an angle \(\theta\) with vertical edge of the disc. If the disc displaces a weight of water \(W\) and surface tension of water is \(T\), then the weight of metal disc is
  

  • \(2\pi r T + W\)
    
  • \(2\pi r \cos\theta - W\)
    
  • \(2\pi r T \cos\theta + W\)
    
  • \(W - 2\pi r T \cos\theta\)
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• 2.

  Twenty seven drops of same size are charged at $220\text{ V}$ each. They combine to form a bigger drop. Calculate the potential of the bigger drop.}

  • $1320\text{ V}$
    
  • $1520\text{ V}$
    
  • $1980\text{ V}$
    
  • $660\text{ V}$
    
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• 3.

  A particle is executing SHM of amplitude \(4\text{ cm}\) and time period \(4\text{ s}\). The time taken by it to move from positive extreme position to half the amplitude is
  

  • \(1\text{ s}\)
    
  • \(\frac{1}{3}\text{ s}\)
    
  • \(\frac{2}{3}\text{ s}\)
    
  • \(\sqrt{\frac{2}{3}}\text{ s}\)
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• 4.

  Which of the following sets are correctly matched? {|c|c|c|} Set & Molecule & Geometry
  I & $\text{BrF}_5$ & Square pyramidal
  II & $\text{XeF}_6$ & Distorted octahedral
  III & $\text{SF}_4$ & Square planar
  IV & $\text{PbCl}_2$ & Linear
  

  • I and II
    
  • II and III
    
  • III and IV
    
  • I and IV
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• 5.

  If the direction ratios of two lines are given by $ l + m + n = 0 $ and $ mn - 2ln + lm = 0 $, then the angle between the lines is:

  • $ \frac{\pi}{4} $
    
  • $ \frac{\pi}{3} $
    
  • $ \frac{\pi}{2} $
    
  • $ 0 $
    
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• 6.

  Gas is being pumped into a spherical balloon at the rate of $ 30 \, \text{ft}^3/\text{min} $. Then the rate at which the radius increases when it reaches the value $ 15 \, \text{ft} $ is:

  • $ \frac{1}{30\pi} \, \text{ft}/\text{min} $
    
  • $ \frac{1}{15\pi} \, \text{ft}/\text{min} $
    
  • $ \frac{1}{20\pi} \, \text{ft}/\text{min} $
    
  • $ \frac{1}{25\pi} \, \text{ft}/\text{min} $
    
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