MHT CET PYQs for Projectile motion with Solutions: Practice MHT CET Previous Year Questions

Content Curator | Updated on - Oct 27, 2026

Projectile Motion is a topic from the Motion in a Plane chapter of Class 11 Physics, and it is part of the Physics section of the MHT CET for candidates who are preparing for the PCM (Physics, Chemistry, and Mathematics).

The key topics covered in Projectile Motion PYQs are:

Maximum height, range and angle of projection
Time of flight from given data
Complementary angles and equal range
Speed and energy at the highest point
Trajectory equation of a projectile

Practising Projectile Motion MHT CET PYQ helps candidates to understand question pattern, improve calculation speed, and identify concepts which were asked in previous exams.

Based on chapter-wise analysis of the MHT CET Physics paper, Projectile Motion is a small topic worth up to 1 mark in a paper. It recorded 13 questions across the 80 shifts in the data, and 9 of them came in the 2025 and 2026 papers. The 7 questions from 2026 each came from a different shift.

MHT CET Projectile Motion Chapter: Question Count, Marks and Weightage:

0.16 Average questions per shift (2018-2026)	9 Questions in the 2025 and 2026 papers (33 shifts)
13 Questions in the PDF (2021-2026)	0.3% Estimated Physics paper weightage (0.5% in 2025-2026)

The PDF holds 13 questions from MHT CET 2026 to 2021, newest first, each with its exam date and shift. Options are as printed and answer keys are not included.

Projectile Motion PYQ Statistics (2022-2026)

The table below shows the number of questions asked in MHT CET Projectile Motion PYQs. Every shift has 50 Physics questions, so the last column is the average per shift divided by 50.

Year	Total Questions (across shifts)	Shifts in the Data	Average per Shift	Weightage (out of 50 Physics Qs)
2026	7	16	0.44	0.9%
2025	2	17	0.12	0.2%
2024	1	18	0.06	0.1%
2023	1	12	0.08	0.2%
2022	1	1	1.00	2.0%

The 2018 to 2021 papers in the PDF add 1 more questions: 2021 had 1, 2020 had none, 2019 had none, 2018 had none. The 2022 and 2021 questions in the PDF are the shell with a time of flight and the cricketer's ball.

MHT CET Projectile Motion Important Questions: Based on the Last 5 Years

The major types of questions asked from Projectile Motion in MHT CET cover the following topics:

Topic	Questions in the PDF	Questions in 2022-2026	Average per Shift (2022-2026)
Relations between range, maximum height and angle of projection, including equal range at complementary angles and the maximum area covered by bullets	6	6	0.09
Time of flight and maximum height from given data, such as H, the speed of the shell, or the time the ball stays in the air	3	2	0.03
Speed and potential energy at the highest point	2	2	0.03
Trajectory equation and statements about the path in a figure	2	2	0.03

Pair PYQs with Other Study Material for MHT CET 2027

Click on the link to practise problems and time management skills:

Resource	Link
MHT CET Sample Paper	Check Here
MHT CET Mock Test	Check Here

Question Style in MHT CET Projectile Motion PYQs

All 13 questions in this PDF are single-correct MCQs. Most are ratio or angle questions that need one or two formulas of projectile motion.

Question Style	What it Tests
Ratio of velocities, heights or ranges	Two projectiles with the same maximum height, or with angles that add up to 90 degrees, and the ratio asked is found from H = u²sin²θ/2g and R = u²sin2θ/g
Angle from a given relation	The angle of projection when R is n times H, or when the maximum height equals the range
Trigonometric values supplied	Several questions give sin 30, sin 45, sin 60 or cos 60 in brackets, so the working is substitution and simplification
Time of flight and height from data	Time of flight of a shell fired at 30 degrees with 196 m/s, the time of flight in terms of H, and the height reached when the ball is caught after 2 seconds
Concept and figure based	The statement that is NOT correct about a projectile path drawn in a figure, and the initial velocity from the equation of the trajectory

How to Use the Projectile Motion PYQ PDF for MHT CET

Start with the 2026 papers first, because they hold 7 of the 13 questions.
Write down the three formulas of H, R and time of flight before you start and check each question against them.
Keep sin 30, sin 45 and sin 60 values on one line of your rough work, since many questions give them in brackets.
Solve year-wise PYQs by timing yourself, as time management is crucial.
Re-attempt only the questions you got wrong, and note which formula you missed.

Video: Projectile Motion PYQs and MCQs

Source: Ritesh Dalal | Physics Edupoint

Projectile Motion PYQ for MHT CET Physics FAQs

Ques. How many questions come from Projectile Motion every year?

Ans. In this PDF, 7 questions are from the 2026 papers, 2 from 2025, and 1 each from 2024, 2023, 2022 and 2021. The questions in 2026 came from 7 different shifts.

Ques. Which topics are asked most frequently in MHT CET Projectile Motion?

Ans. Relations between range, maximum height and angle of projection make up 6 of the 13 questions. Time of flight and maximum height from data account for 3, and speed or energy at the highest point and the trajectory equation have 2 each.

Ques. What kind of questions are asked from Projectile Motion?

Ans. Single-correct MCQs, mostly ratios and angles that follow from the formulas for H, R and time of flight. A few give trigonometric values in brackets.

Ques. What is the best way to practise Projectile Motion PYQs?

Ans. First solve the 2026 questions completely, then the older ones, and finally re-attempt the questions you got wrong.

Ques. Can I score full marks from Projectile Motion?

Ans. The topic is small. It carried about 1 question in a few shifts of 2026, and each Physics question in MHT CET is worth 1 mark. Knowing the formulas of H, R and time of flight is enough to secure that mark.

Ques. Does the Projectile Motion PYQ PDF include solutions?

Ans. No. The PDF contains the questions with their exam date and shift, without answer keys or solutions.

1.
Two projectiles are projected at $ 30^\circ $ and $ 60^\circ $ with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:
- $ 2 : \sqrt{3} $
- $ \sqrt{3} : 1 $
- $ 1 : 3 $
- $ 1 : \sqrt{3} $
View Solution
2.
For a projectile motion, the range R is 'n' times the maximum height H. So the angle of projection is
- $sin^{-1}(\frac{2}{n})$
- $cos^{-1}(\frac{4}{n})$
- $tan^{-1}(\frac{4}{n})$
- $tan^{-1}(\frac{2}{n})$
View Solution
3.
Two balls A and B are projected at an angle of $45^{\circ}$ and $60^{\circ}$ respectively, so that the maximum heights reached are same for both. The ratio of initial velocity of projection of ball A to that for ball B is
$(sin30^{\circ} = cos60^{\circ} = \frac{1}{2}, sin45^{\circ} = cos45^{\circ} = \frac{1}{\sqrt{2}}, sin60^{\circ} = cos30^{\circ} = \frac{\sqrt{3}}{2})$
- $2:\sqrt{3}$
- $\sqrt{3}:2$
- $\sqrt{2}:\sqrt{3}$
- $\sqrt{3}:\sqrt{2}$
View Solution
4.
What is the relation between the height $h$ and the range $R$ when a projectile is fired at $45^\circ$?
- $R = h$
- $R = 2h$
- $R = 4h$
- $R = 8h$
View Solution
5.
A batsman hits a ball with a velocity 'v', making an angle of $60^{\circ}$ with the vertical. After some time direction of velocity is making an angle of $60^{\circ}$ with the horizontal. The speed of the ball at this instant is
$[cos(60^{\circ}) = \frac{1}{2},cos(30^{\circ}) = \frac{\sqrt{3}}{2}]$
- $\frac{\sqrt{3}}{2}v$
- $\sqrt{3}v$
- $\frac{v}{2}$
- $V$
View Solution
6.
A ball P is projected at an angle of $60^{\circ}$ with the vertical with certain initial speed. Another ball Q of the same mass as that of ball P is projected vertically upwards with the same initial speed as that of P. At the highest point, the ratio of potential energy of ball P to that of ball Q is
$(sin30^{\circ} = 0.5)$
- $1:4$
- $4:1$
- $2:3$
- $3:2$
View Solution
7.
Two spheres are projected at angles $30^{\circ}$ and $45^{\circ}$ with the horizontal. The maximum height reached by both is same. The ratio of their initial velocities is, $(sin45^{\circ} = \frac{1}{\sqrt{2}},sin30^{\circ} = 0.5)$
- $2:3$
- $\sqrt{2}:1$
- $3:1$
- $\sqrt{2}:\sqrt{3}$
View Solution
8.
A solid metallic cube having total surface area $ 24 \, \text{m}^2 $ is uniformly heated. If its temperature is increased by $ 10^\circ \, \text{C} $, calculate the increase in volume of the cube.
$ \text{(Given: } \alpha = 5.0 \times 10^{-4} \, \text{C}^{-1} \text{)} $
- $ 2.4 \times 10^6 \, \text{cm}^3 $
- $ 1.2 \times 10^5 \, \text{cm}^3 $
- $ 6.0 \times 10^4 \, \text{cm}^3 $
- $ 4.8 \times 10^5 \, \text{cm}^3 $
View Solution
9.
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is
- $\text{E}^2 \sin^2 \theta$
- $\text{E} \sin \theta$
- $E \cos^2 \theta$
- $\text{E} \cos \theta$
View Solution
10.
Two objects are projected with same velocity 'u' at different angles $α$ and $β$ with the horizontal. If $α+β = 90^{\circ}$, the ratio of horizontal range of the first object to the second object will be $[sin(π-θ) = sinθ]$
- $4:1$
- $2:1$
- $1:1$
- $1:2$
View Solution
11.
The equation of the trajectory of a ball projected at an angle $θ$ with the horizontal, is given as $y = x-\frac{gx^2}{2}$
The initial velocity of the ball is
[Given : $tan45^{\circ} = 1$, $cos45^{\circ} = \frac{1}{\sqrt{2}}$ ]
- $2\sqrt{2}\,\text{m/s}$
- $2\,\text{m/s}$
- $\sqrt{2}\,\text{m/s}$
- $\frac{1}{\sqrt{2}}\,\text{m/s}$
View Solution
12.
The value of acceleration due to gravity at Earth's surface is $ 9.8 \, \text{m/s}^2 $. The altitude above its surface at which the acceleration due to gravity decreases to $ 4.9 \, \text{m/s}^2 $ is close to: (Radius of Earth $ R = 6.4 \times 10^6 \, \text{m} $)
- $ 2.6 \times 10^6 \, \text{m} $
- $ 6.4 \times 10^6 \, \text{m} $
- $ 9.0 \times 10^6 \, \text{m} $
- $ 1.6 \times 10^6 \, \text{m} $
View Solution
13.
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is
- $\text{E}^2 \sin^2 \theta$
- $\text{E} \sin \theta$
- $E \cos^2 \theta$
- $\text{E} \cos \theta$
View Solution
14.
An object is dropped from a helicopter flying horizontally at 360 km/h. It falls from a height of 2 km and reaches the ground in 20 seconds. What is the displacement of the package relative to the helicopter's position when it was dropped?
- 2 km
- $ 2\sqrt{2} $ km
- 4 km
- $ 8 $ km
View Solution
15.
A ball is thrown vertically upward with an initial velocity of $ 20 \, \text{m/s} $. Calculate the time taken for the ball to reach its maximum height.
- $ 2 \, \text{s} $
- $ 4 \, \text{s} $
- $ 1.5 \, \text{s} $
- $ 3 \, \text{s} $
View Solution

View more MHT CET Questions

SHARE ON FACEBOOK SHARE ON TWITTER

MHT CET PYQs for Projectile motion with Solutions: Practice MHT CET Previous Year Questions

Projectile Motion PYQ Statistics (2022-2026)

MHT CET Projectile Motion Important Questions: Based on the Last 5 Years

Pair PYQs with Other Study Material for MHT CET 2027

Question Style in MHT CET Projectile Motion PYQs

How to Use the Projectile Motion PYQ PDF for MHT CET

Video: Projectile Motion PYQs and MCQs

Projectile Motion PYQ for MHT CET Physics FAQs

1.
Two projectiles are projected at \( 30^\circ \) and \( 60^\circ \) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

2.
For a projectile motion, the range R is 'n' times the maximum height H. So the angle of projection is

4.
What is the relation between the height $h$ and the range $R$ when a projectile is fired at $45^\circ$?

7.
Two spheres are projected at angles \(30^{\circ}\) and \(45^{\circ}\) with the horizontal. The maximum height reached by both is same. The ratio of their initial velocities is, \((sin45^{\circ} = \frac{1}{\sqrt{2}},sin30^{\circ} = 0.5)\)

8.
A solid metallic cube having total surface area $ 24 \, \text{m}^2 $ is uniformly heated. If its temperature is increased by $ 10^\circ \, \text{C} $, calculate the increase in volume of the cube.
$ \text{(Given: } \alpha = 5.0 \times 10^{-4} \, \text{C}^{-1} \text{)} $

9.
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

10.
Two objects are projected with same velocity 'u' at different angles \(α\) and \(β\) with the horizontal. If \(α+β = 90^{\circ}\), the ratio of horizontal range of the first object to the second object will be \([sin(π-θ) = sinθ]\)

11.
The equation of the trajectory of a ball projected at an angle \(θ\) with the horizontal, is given as \(y = x-\frac{gx^2}{2}\)
The initial velocity of the ball is
[Given : \(tan45^{\circ} = 1\), \(cos45^{\circ} = \frac{1}{\sqrt{2}}\) ]

12.
The value of acceleration due to gravity at Earth's surface is \( 9.8 \, \text{m/s}^2 \). The altitude above its surface at which the acceleration due to gravity decreases to \( 4.9 \, \text{m/s}^2 \) is close to: (Radius of Earth \( R = 6.4 \times 10^6 \, \text{m} \))

13.
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

14.
An object is dropped from a helicopter flying horizontally at 360 km/h. It falls from a height of 2 km and reaches the ground in 20 seconds. What is the displacement of the package relative to the helicopter's position when it was dropped?

15.
A ball is thrown vertically upward with an initial velocity of \( 20 \, \text{m/s} \). Calculate the time taken for the ball to reach its maximum height.

Comments

SUBSCRIBE TO OUR NEWS LETTER

Projectile Motion PYQ Statistics (2022-2026)

MHT CET Projectile Motion Important Questions: Based on the Last 5 Years

Pair PYQs with Other Study Material for MHT CET 2027

Question Style in MHT CET Projectile Motion PYQs

How to Use the Projectile Motion PYQ PDF for MHT CET

Video: Projectile Motion PYQs and MCQs

Projectile Motion PYQ for MHT CET Physics FAQs

1.Two projectiles are projected at \( 30^\circ \) and \( 60^\circ \) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

2.For a projectile motion, the range R is 'n' times the maximum height H. So the angle of projection is

4.What is the relation between the height $h$ and the range $R$ when a projectile is fired at $45^\circ$?

7.Two spheres are projected at angles \(30^{\circ}\) and \(45^{\circ}\) with the horizontal. The maximum height reached by both is same. The ratio of their initial velocities is, \((sin45^{\circ} = \frac{1}{\sqrt{2}},sin30^{\circ} = 0.5)\)

8.A solid metallic cube having total surface area $ 24 \, \text{m}^2 $ is uniformly heated. If its temperature is increased by $ 10^\circ \, \text{C} $, calculate the increase in volume of the cube. $ \text{(Given: } \alpha = 5.0 \times 10^{-4} \, \text{C}^{-1} \text{)} $

9.A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

10.Two objects are projected with same velocity 'u' at different angles \(α\) and \(β\) with the horizontal. If \(α+β = 90^{\circ}\), the ratio of horizontal range of the first object to the second object will be \([sin(π-θ) = sinθ]\)

11.The equation of the trajectory of a ball projected at an angle \(θ\) with the horizontal, is given as \(y = x-\frac{gx^2}{2}\)The initial velocity of the ball is[Given : \(tan45^{\circ} = 1\), \(cos45^{\circ} = \frac{1}{\sqrt{2}}\) ]

12.The value of acceleration due to gravity at Earth's surface is \( 9.8 \, \text{m/s}^2 \). The altitude above its surface at which the acceleration due to gravity decreases to \( 4.9 \, \text{m/s}^2 \) is close to: (Radius of Earth \( R = 6.4 \times 10^6 \, \text{m} \))

13.A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

14.An object is dropped from a helicopter flying horizontally at 360 km/h. It falls from a height of 2 km and reaches the ground in 20 seconds. What is the displacement of the package relative to the helicopter's position when it was dropped?

15.A ball is thrown vertically upward with an initial velocity of \( 20 \, \text{m/s} \). Calculate the time taken for the ball to reach its maximum height.

Comments

SUBSCRIBE TO OUR NEWS LETTER

1.
Two projectiles are projected at \( 30^\circ \) and \( 60^\circ \) with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

2.
For a projectile motion, the range R is 'n' times the maximum height H. So the angle of projection is

4.
What is the relation between the height $h$ and the range $R$ when a projectile is fired at $45^\circ$?

7.
Two spheres are projected at angles \(30^{\circ}\) and \(45^{\circ}\) with the horizontal. The maximum height reached by both is same. The ratio of their initial velocities is, \((sin45^{\circ} = \frac{1}{\sqrt{2}},sin30^{\circ} = 0.5)\)

8.
A solid metallic cube having total surface area $ 24 \, \text{m}^2 $ is uniformly heated. If its temperature is increased by $ 10^\circ \, \text{C} $, calculate the increase in volume of the cube.
$ \text{(Given: } \alpha = 5.0 \times 10^{-4} \, \text{C}^{-1} \text{)} $

9.
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

10.
Two objects are projected with same velocity 'u' at different angles \(α\) and \(β\) with the horizontal. If \(α+β = 90^{\circ}\), the ratio of horizontal range of the first object to the second object will be \([sin(π-θ) = sinθ]\)

11.
The equation of the trajectory of a ball projected at an angle \(θ\) with the horizontal, is given as \(y = x-\frac{gx^2}{2}\)
The initial velocity of the ball is
[Given : \(tan45^{\circ} = 1\), \(cos45^{\circ} = \frac{1}{\sqrt{2}}\) ]

12.
The value of acceleration due to gravity at Earth's surface is \( 9.8 \, \text{m/s}^2 \). The altitude above its surface at which the acceleration due to gravity decreases to \( 4.9 \, \text{m/s}^2 \) is close to: (Radius of Earth \( R = 6.4 \times 10^6 \, \text{m} \))

13.
A stone is projected with kinetic energy E, making an angle $\theta$ with the horizontal. When it reaches a highest point, its kinetic energy is

14.
An object is dropped from a helicopter flying horizontally at 360 km/h. It falls from a height of 2 km and reaches the ground in 20 seconds. What is the displacement of the package relative to the helicopter's position when it was dropped?

15.
A ball is thrown vertically upward with an initial velocity of \( 20 \, \text{m/s} \). Calculate the time taken for the ball to reach its maximum height.